C++ : Help prog does not fully work

[Signeg]

Hey guys,
I have some work for university and i never used C++ in my life so i'm kinda lost..
But i've still managed to write something woth it.
But too bad for me the prog does compile and lunch propely, but once i enter "-1" for the second while, nothing more is happening..

This is the code
http://rafb.net/paste/results/rHKKIF94.html
Could you guys tell me whats wrong because it looks okay for me :(


Ps: I'm from Belgium so i wrote the prog in french (sorry sorry).
If u need help tell me ;)
Ps2: THIS IS NOOB STUFF :x

THX !

[Banfa]

The problems I see are in this code chunk

                while (cdt=false){
                      if (-1<cote>20){ // S'assure que la cote est bien sur 20
                         cdt=false;
                         cout << "Erreur, veuillez entrer une cote sur 20" << "Veuillez recommencer" << endl; 
                      }   
                      if (ponderation==0){ // La pondération devant obligatoirement être supérieure à 1
                         cdt=false;
                         cout << "Erreur, la pondération ne peut être nulle." << "Veuillez recommencer" << endl;
                      }
                      else
                          cdt=true;
                } 
 

if (-1<cote>20)

The condition of this if statement awlays evaluates to FALSE did you mean

if (-1<cote && cote<20)


In this code chunk once ponderation has a value of 0 the while loop

while (cdt=false)

will go into an infinite loop.

[Signeg]

Yep i've noted this error an hour ago :$
Thank you !

I'm trying to fix it, but not sure it will work :(

[Signeg]

Could you tell me if this is correct ?

while (!verf){
                      if (-1>cote || cote>20){ // S'assure que la cote est bien sur 20
                         verf=false;
                         cout << "Erreur, veuillez entrer une cote sur 20 " << "Veuillez recommencer" << endl; 
                      }   
                      if (ponderation<1){ // La pondération devant obligatoirement être supérieure à 0
                         verf=false;
                         cout << "Erreur, la pondération ne peut être inférieure à 1." << "Veuillez recommencer" << endl;
                      }
                      else
                          verf=true;
                } 
                total=total+(cote*ponderation);
                pondtotale=pondtotale+ponderation;
                cout << "Veuillez introduire la cote obtenu pour ce cours" << endl;
                cout << "Introduisez -1 pour obtenir votre moyenne" << endl;
                cin >> cote; 
                verf=false;

Because the first two have the same importance..
It's

- Check Cote
- Check pond
- IF OK proceed

How do i do that ?

[Banfa]

This will still go into an infiniteloop if either of the 2 conditions fail because the loop does not encompass any code that changes the variables that are tested. If the values are bad you probably want to give the user a chance to re-enter them.

for 2 coditions the pseudo code looks some like

IF CONDITION 1 OK AND CONDITION 2 OK
    PERFORM SUCCESS OPERATION
ELSE
    PERFORM FAILED OPERATION
 
    IF CONDITION 1 NOT OK
        PRINT CONDITION 1 ERROR MESSAGE
    ENDIF
    IF CONDITION 2 NOT OK
        PRINT CONDITION 2 ERROR MESSAGE
    ENDIF
ENDIF