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if Constructor can be used to initialize ...



If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Thanks

Oct 25 '06 #1
14 1648
* 2005:
>
If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?
Sometime before the constructor is called.

For the "new" operator that's immediately before.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #2
Does it mean that if we use a constructor, we don't need a "new"
operator?

Thanks

Alf P. Steinbach wrote:
* 2005:

If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Sometime before the constructor is called.

For the "new" operator that's immediately before.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #3

2005 wrote:
If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Thanks
You don't need the new operator to allocate - in a perfect world, using
new should be discouraged.
A ctor's primary purpose is to allocate an instance based on the
contents of its type (ignoring inherited classes for now) and whatever
resources are required.
In C++ it happens to have a secondary purpose that is to initialize
members, if any, using an init list. The initialisation is not a
requirement but too often overlooked and quite usefull.

To answer your question: allocation happens when the constructor is
invoked.
and "invoke" does not mean "call".

#include <iostream>

class N
{
int n;
public:
N() : n(0) { std::cout << "invoke ctor\n"; }
~N() { std::cout << "invoke d~tor\n"; }
const int& get() const { return n; }
};

int main()
{
N instance; // allocation happens here
std::cout << "instance.n = " << instance.get() << std::endl;

return 0;
} // deallocation happens here - at end of scope

/*
invoke ctor
instance.n = 0
invoke d~tor
*/

The explanation is in the FAQ:
http://www.parashift.com/c++-faq-lite/ctors.html

Oct 25 '06 #4
* Salt_Peter:
2005 wrote:
>If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Thanks

You don't need the new operator to allocate - in a perfect world, using
new should be discouraged.
Sorry, that's meaningless.

A ctor's primary purpose is to allocate an instance based on the
contents of its type (ignoring inherited classes for now) and whatever
resources are required.
Sorry, that's incorrect.

In C++ it happens to have a secondary purpose that is to initialize
members, if any, using an init list.
Sorry, that's incorrect.

The initialisation is not a
requirement but too often overlooked and quite usefull.
Sorry, that's incorrect.
To answer your question: allocation happens when the constructor is
invoked.
Sorry, that's incorrect.

and "invoke" does not mean "call".
Sorry, that's incorrect.
#include <iostream>

class N
{
int n;
public:
N() : n(0) { std::cout << "invoke ctor\n"; }
~N() { std::cout << "invoke d~tor\n"; }
const int& get() const { return n; }
};

int main()
{
N instance; // allocation happens here
Sorry, that's incorrect (although in practice true).

std::cout << "instance.n = " << instance.get() << std::endl;

return 0;
} // deallocation happens here - at end of scope
Sorry, that's incorrect (although in practice true).

/*
invoke ctor
instance.n = 0
invoke d~tor
*/

The explanation is in the FAQ:
http://www.parashift.com/c++-faq-lite/ctors.html
Sorry, that's incorrect (this FAQ section does not concern allocation,
and provides no explanation of when allocation occurs).

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #5
Anyway, I think the faq-list is exactly what 2005 needs.
Alf P. Steinbach 写道:
* Salt_Peter:
2005 wrote:
If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Thanks
You don't need the new operator to allocate - in a perfect world, using
new should be discouraged.

Sorry, that's meaningless.

A ctor's primary purpose is to allocate an instance based on the
contents of its type (ignoring inherited classes for now) and whatever
resources are required.

Sorry, that's incorrect.

In C++ it happens to have a secondary purpose that is to initialize
members, if any, using an init list.

Sorry, that's incorrect.

The initialisation is not a
requirement but too often overlooked and quite usefull.

Sorry, that's incorrect.
To answer your question: allocation happens when the constructor is
invoked.

Sorry, that's incorrect.

and "invoke" does not mean "call".

Sorry, that's incorrect.
#include <iostream>

class N
{
int n;
public:
N() : n(0) { std::cout << "invoke ctor\n"; }
~N() { std::cout << "invoke d~tor\n"; }
const int& get() const { return n; }
};

int main()
{
N instance; // allocation happens here

Sorry, that's incorrect (although in practice true).

std::cout << "instance.n = " << instance.get() << std::endl;

return 0;
} // deallocation happens here - at end of scope

Sorry, that's incorrect (although in practice true).

/*
invoke ctor
instance.n = 0
invoke d~tor
*/

The explanation is in the FAQ:
http://www.parashift.com/c++-faq-lite/ctors.html

Sorry, that's incorrect (this FAQ section does not concern allocation,
and provides no explanation of when allocation occurs).

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #6
Please do not top-post in this group. It's frowned upon.

2005 wrote [top-posting and sig-quoting corrected]
>
Alf P. Steinbach wrote:
>* 2005:
>
If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Sometime before the constructor is called.

For the "new" operator that's immediately before.
Does it mean that if we use a constructor, we don't need a "new"
operator?
An object is a region of storage [1.8/1]. Thus, before you initialize an
object, you need to have that region of memory. Now, how you get that
region of storage, depends on how the object is created (not initialized).

An object is created by a definition, by a new-expression, or by the
implementation when needed [1.8/1]. Examples:

a) Defining a variable:

SomeClass some_var ( some_args );

Memory is allocated automagically by the compiler. Then the object is
created.
b) Dynamic allocation via new:

SomeClass* some_ptr = new SomeClass ( some_args );

Here, new will allocate memory by calling an allocation function. Then the
constructor is called to initialize the object.
c) Creating a temporary:

some_function( SomeClass( some_args ) );

Memory allocation happens without you doing anything.
Best

Kai-Uwe Bux
Oct 25 '06 #7

You say "Sorry, that's incorrect." - Could you pls give explanations?

Alf P. Steinbach wrote:
* Salt_Peter:
2005 wrote:
If a Constructor can be used to initialize, when is memory is allocated
/ say the "new" operator etc?

Thanks
You don't need the new operator to allocate - in a perfect world, using
new should be discouraged.

Sorry, that's meaningless.

A ctor's primary purpose is to allocate an instance based on the
contents of its type (ignoring inherited classes for now) and whatever
resources are required.

Sorry, that's incorrect.

In C++ it happens to have a secondary purpose that is to initialize
members, if any, using an init list.

Sorry, that's incorrect.

The initialisation is not a
requirement but too often overlooked and quite usefull.

Sorry, that's incorrect.
To answer your question: allocation happens when the constructor is
invoked.

Sorry, that's incorrect.

and "invoke" does not mean "call".

Sorry, that's incorrect.
#include <iostream>

class N
{
int n;
public:
N() : n(0) { std::cout << "invoke ctor\n"; }
~N() { std::cout << "invoke d~tor\n"; }
const int& get() const { return n; }
};

int main()
{
N instance; // allocation happens here

Sorry, that's incorrect (although in practice true).

std::cout << "instance.n = " << instance.get() << std::endl;

return 0;
} // deallocation happens here - at end of scope

Sorry, that's incorrect (although in practice true).

/*
invoke ctor
instance.n = 0
invoke d~tor
*/

The explanation is in the FAQ:
http://www.parashift.com/c++-faq-lite/ctors.html

Sorry, that's incorrect (this FAQ section does not concern allocation,
and provides no explanation of when allocation occurs).

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #8

Kai-Uwe Bux wrote:
Please do not top-post in this group. It's frowned upon.

2005 wrote [top-posting and sig-quoting corrected]
Sorry about it - will follow it in the future.

Thanks for letting me know.

Oct 25 '06 #9
* 2005:
You say "Sorry, that's incorrect." - Could you pls give explanations?
Yes, if you'd care to respect the conventions of the group: don't
top-post, don't quote signatures, quote only relevant things, but do
quote the relevant things, ask specific questions (about what you quoted
right above the specific questions), and use plain English.

Otherwise this could amount to a fullblown tutorial on basic C++.

And I've already written that -- and besides, there isn't room enough
in a Usenet article.
Notes:
In an earlier article in this thread, in reply to Kai-Uwe Bux' request
for the same, you wrote Sorry about it - will follow it in the
future., but you didn't.
See the FAQ item titled What other "newbie" guides are there for
me?, currently at <url:
http://www.parashift.c om/c++-faq-lite/newbie.html#faq-29.21>.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Oct 25 '06 #10

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