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Lvalues and Rvalues

i was reading soemthing about Lvalues Rvalues and modifiable
Lvalues....
i am confused now...
like for eg
int *y , x ;
y = &x ;
in the second is x a lvalue or rvalue
any pointers on some good reading on lvalues and rvalues on the web ??
thanks in advance
Kind Regard
rahul

Oct 14 '06 #1
3 2729
ra************* ******@gmail.co m wrote:
i was reading soemthing about Lvalues Rvalues and modifiable
Lvalues....
i am confused now...
like for eg
int *y , x ;
y = &x ;
in the second is x a lvalue or rvalue
any pointers on some good reading on lvalues and rvalues on the web ??
thanks in advance
Kind Regard
rahul
Well, there really isn't much to it, if I get where you're going. You
might want to read up on http://c-faq.com/ .... this is a general C-FAQ,
but you kind of asked a general question, so...
Oct 14 '06 #2
"ra************ *******@gmail.c om" <ra************ *******@gmail.c omwrites:
i was reading soemthing about Lvalues Rvalues and modifiable
Lvalues....
i am confused now...
like for eg
int *y , x ;
y = &x ;
in the second is x a lvalue or rvalue
any pointers on some good reading on lvalues and rvalues on the web ??
An "lvalue" is an expression that (potentially) designates an object.
The origin of the term is "left value", i.e., something that can
appear on the left side of an assignment statement (though not all
lvalues can actually appear on the left side of an assignment
statement).

In your example above:
y = &x;
both y and x are lvalues; the operand of a unary "&" must be an
lvalue, since "&" takes the address of an object. (It's not *quite*
that simple, but don't worry about it.)

A "modifiable lvalue" is an lvalue that refers to an object that can
be modified (for example, one that isn't declared as const).

The C standard doesn't actually use the term "rvalue". You can think
of an rvalue as any expression that isn't used as an lvalue, or
(loosely) as an expression that can appear on the right side of an
assignment.

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Oct 14 '06 #3
"ra************ *******@gmail.c om" <ra************ *******@gmail.c omwrote:
# i was reading soemthing about Lvalues Rvalues and modifiable
# Lvalues....
# i am confused now...
# like for eg
# int *y , x ;
# y = &x ;
# in the second is x a lvalue or rvalue
# any pointers on some good reading on lvalues and rvalues on the web ??
# thanks in advance

Unfortunately except for Algol 68 and assmebly language,
variableness is left out of type systems, requiring instead
much verbal handwaving that could be more precise.

Borrowing & from C++ with restriction that a reference type
cannot be inside any other type, then when you declare a
scalar and array,
T v,w[n],*x;
v has type (&T), w has type (*T), and x has type (&*T).

Then the pointer/variable operator types are
v = e
v is coerceable to type &T
and e is coerceable to type T
and (v=e) is type T
*x
x is coercecable to *T
and *x is type &T
&v
v is coercecable to &T
and &v is type *T
s.f
If s is coercable to &T and f has nonreference type S,
(s.f) has type &S [endowed with subnames in Algol 68].
If s is not coercable to T and f has nonreference type S,
(s.f) has type S.
LOAD(v) is an implicit operator
v is coerceable to &T
and LOAD(v) is type T

Expressions q in the language is then applied to one of two implicit
functions LVALUE(q) or RVALUE(q)
LVALUE(q) = q and q must have type &T
RVALUE(q) = LOAD(q) if q has type &T
RVALUE(q) = q if q has type T which is not a reference type

The pointer/variable operator implicits are
LVALUE(v) = RVALUE(e)
* RVALUE(x)
& LVALUE(x)
s . f - There is no implicit on s.
A variable by itself has its declared type, T or &T.
All other expressions are
prefixop RVALUE(operand)
RVALUE(leftoper and) infixop RVALUE(rightope rand)
RVALUE(predicat e) ? RVALUE(truebran ch) : RVALUE(falsebra nch)

GCC has an alternate rule for ?: - there is no implicit RVALUE or
LVALUE on the branches except they must be coerceable to a balanced
type T, T may be a reference type.
(p?v:*x) = e
LVALUE((RVALUE( p) ? v : *RVALUE(x))) = RVALUE(e)
with the types LVALUE(RVALUE(i nt) ? &T : *RVALUE(&*T)) = RVALUE(S)
LVALUE(RVALUE(i nt) ? &T : *(LOAD(&*T))) = S
LVALUE(RVALUE(i nt) ? &T : *(*T)) = S
LVALUE(RVALUE(i nt) ? &T : &T) = S
LVALUE(&T) = S
&T = S
and if S is coerceable to T, the assignment is valid in GCC,
but in ANSI C, the types are T=S which is invalid.

--
SM Ryan http://www.rawbw.com/~wyrmwif/
But I do believe in this.
Oct 14 '06 #4

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