advanced string manipulation

[MC felon]

hello again..
i want to design a program which takes in a string and replaces all 's'
characters with 'sh'. how do i do it? thanks a lot!

[Ian Collins]

MC felon wrote:

hello again..
i want to design a program which takes in a string and replaces all 's'
characters with 'sh'. how do i do it? thanks a lot!

What have you tried?

--
Ian Collins.

[MC felon]

here's what i have tried:

cout<< "enter a string\n\n";

gets(take);

//calculation

int len = 0;

char temp[2];

len = strlen(take);

for(int g=0;g<len;g++)
{
while(take[g] != ' \0 ')
{
if(take[g] == 's')
{
//dont know what to do
}
}
}
cout<< take;
getch();
}

[Ian Collins]

MC felon wrote:

In future, please a) quote some context in your reply and b) post
something that compiles on its own.

here's what i have tried:

cout<< "enter a string\n\n";

gets(take);

gets is vile (the root or most buffer overflows), avoid at all cost.
Use std::getline, which takes the maximum buffer size as a parameter.

//calculation

int len = 0;

Introduce len where it is assigned.

char temp[2];

len = strlen(take);

for(int g=0;g<len;g++)
{
while(take[g] != ' \0 ')

You don't want this inner loop, the for is already traversing take. Use
one or the other.

{
if(take[g] == 's')
{

You would be best to declare a second array, double the size of take and
copy the characters to this. Where take[g] == 's', add an 'h'.

//dont know what to do
}
}
}
cout<< take;

Should add << std::endl here.

getch();

why?

--
Ian Collins.

[peter koch]

MC felon wrote:

here's what i have tried:

cout<< "enter a string\n\n";

gets(take);

//calculation

int len = 0;

char temp[2];

len = strlen(take);

for(int g=0;g<len;g++)
{
while(take[g] != ' \0 ')
{
if(take[g] == 's')
{
//dont know what to do
}
}
}
cout<< take;
getch();
}

What I see above (disregarding cout) is C code. So you have basically
two choices:

a) switch to the more appropriate std::string and return if you have
problems using that one.
b) Remove the line that couts take and ask at comp.lang.c. That group
will have all the expertise needed to deal with C and can give you a
much better answer.

/Peter