I need to do just a few multiplies of long integers and have a divide
by ten. Can I avoid using floats? Can I use two longs as a 64 bit value
somehow? Thanks.
Sep 7 '06
27 2877 dc*****@connx.c om wrote:
ga*****@hotmail .com wrote:
>I need to do just a few multiplies of long integers and have a divide by ten. Can I avoid using floats? Can I use two longs as a 64 bit value somehow? Thanks.
/*
An integral version will work OK if the quantities are huge, but
breaks down badly for small quantities.
*/
To use the ratapprx program I published here earlier, I suggest the
following (untested) routine for the OP.
/* File mulrat.c */
#include "mulrat.h"
/* multiply an integral value by a rational fraction */
/* returns rounded product, -1 for overflow */
long int mulrat(long int value, /* to be processed */
const int num, /* numerator */
const int denom) /* denominator */
{
if (LONG_MAX / num < value + denom / 2) {
/* calculation will overflow */
return -1;
}
return ((value + denom/2) * num) / denom;
} /* mulrat */
/* File mulrat.h */
#ifndef H_mulrat_h
# ifdef __cplusplus
extern "C" {
# endif
#include <limits.h>
/* multiply an integral value by a rational fraction */
/* returns rounded product, -1 for overflow */
long int mulrat(long int value, /* to be processed */
const int num, /* numerator */
const int denom); /* denominator */
# ifdef __cplusplus
}
# endif
#endif
I repeat, untested code.
--
"The smaller aperture of the lid has been designed to prevent
hedgehogs from entering the McFlurry container in the
unfortunate incidence that the lid is littered"
-- McDonalds, as quoted in Time, 2006-09-11
Eric Sosman wrote:
ga*****@hotmail .com wrote On 09/07/06 13:53,:
Konstantin Miller wrote:
>ga*****@hotmai l.com wrote:
I need to do just a few multiplies of long integers and have a divide by ten. Can I avoid using floats? Can I use two longs as a 64 bit value somehow? Thanks.
Hi!
Can you specify more clearly what you want to do? :-)
Konstantin
I have some long values in Liters and I want to convert to gallons (and
back). If I could do integer multiplication and divide by 10 I could
avoid the float library. Thanks.
Have you considered
long liters, gallons;
liters = ...whatever...;
gallons = liters * 3 / 10;
"Times three, over ten" is a crude approximation to 0.2641721,
but it's the only one I can think of that satisfies your desire
to divide by ten. If you're willing to consider other divisors,
more accurate conversions are possible:
gallons = liters * 26 / 100;
gallons = liters * 264 / 1000;
gallons = liters * 2642 / 10000;
...
picking something that is a power of two might be smart ;)
makes the division simple and also makes it easy to add up
fractions if you need to.
-Lasse
Keith Thompson wrote:
dc*****@connx.c om writes:
>>ga*****@hotma il.com wrote:
>>>I need to do just a few multiplies of long integers and have a divide by ten. Can I avoid using floats? Can I use two longs as a 64 bit value somehow? Thanks.
/* An integral version will work OK if the quantities are huge, but breaks down badly for small quantities. */
You can sometimes get decent results using fixed-point arithmetic. C
doesn't directly support this but you can, for example, use an integer
to represent a number of microliters or nanoliters.
This is the solution I have used on a number of embedded control
applications where floating point requires expensive library calls.
Pick the accuracy you require and the minimum sized integer that gives
you adequate headroom and scale the values appropriately.
In most of my applications, the inputs have been analogue voltages,
currents and temperatures where milli-whatevers have been accurate
enough for the application.
Or you can just use floating-point, and the performance and precision
will probably be perfectly acceptable.
Assuming an FPU.
--
Ian Collins.
In article <od************ *************** ***@comcast.com Joe Wright <jo********@com cast.netwrites:
ga*****@hotmail .com wrote:
....
I have some long values in Liters and I want to convert to gallons (and
back). If I could do integer multiplication and divide by 10 I could
avoid the float library. Thanks.
Not so simple I'd guess. Have a look at this..
Let's see. 1 US gallon is 231 cubic inches. 1 inch is 2.54 cm.
1000 cubic cm is 1 liter. So 1 (US) gallon is 3.785411784 liter
exactly. And 1 UK gallon is 4.54609 liter exactly. So converting
liters to gallons can not be done with only division by 10, but it
can be done the other way around. (This is all according to the
latest standards.)
But let me see:
One survey foot = 0.3048006096 meters.
1200 / 3937 exactly.
One statute mile = 1.6093472187 kilometers.
6336 / 3937 exactly.
One cubic foot = 7.48051948 US gallons.
1728 / 231 exactly.
One US gallon = 3.785411784 liters (exactly).
Indeed.
One ounce (fluid) = 29.573529562 milliliters.
29.5735295625 ml (473176473 / 16000000) exactly (for the US fluid ounce)
28.4130625 ml (454609 / 16000) exactly (for the UK fluid ounce)
Doing stuff like this without floating point is something I don't want
to even think about.
The conversion factors are all plain rational numbers. In the US that
is the case since 1866 and in the UK since 1995. So doing this with
integer operations only is very viable. (Yes, 1866 was not an error.)
The difference in the US between the survey foot and the standard foot
comes because originally (1866) the US linked the foot to the meter
by a reverse factor to that introduced in 1963. The original foot
remained in use in surveying. Something similar did happen with the
US pound, but here the original pound is no longer used (1 kg =
2.2046 lb in 1866, in 1893 adapted to 2.20462 and in 1894 to 2.20462234).
In 1959 changed to the current definition that was also adopted in the
UK in 1963.
But *all* measures in the US are tightly linked, through rational
conversion factors, to the metric system since 1866.
--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/
Dik T. Winter wrote:
In article <od************ *************** ***@comcast.com Joe Wright <jo********@com cast.netwrites:
ga*****@hotmail .com wrote:
...
I have some long values in Liters and I want to convert to gallons (and
back). If I could do integer multiplication and divide by 10 I could
avoid the float library. Thanks.
>
Not so simple I'd guess. Have a look at this..
Let's see. 1 US gallon is 231 cubic inches. 1 inch is 2.54 cm.
1000 cubic cm is 1 liter. So 1 (US) gallon is 3.785411784 liter
exactly. And 1 UK gallon is 4.54609 liter exactly. So converting
liters to gallons can not be done with only division by 10, but it
can be done the other way around. (This is all according to the
latest standards.)
But let me see:
One survey foot = 0.3048006096 meters.
1200 / 3937 exactly.
One statute mile = 1.6093472187 kilometers.
6336 / 3937 exactly.
One cubic foot = 7.48051948 US gallons.
1728 / 231 exactly.
One US gallon = 3.785411784 liters (exactly).
Indeed.
One ounce (fluid) = 29.573529562 milliliters.
29.5735295625 ml (473176473 / 16000000) exactly (for the US fluid ounce)
28.4130625 ml (454609 / 16000) exactly (for the UK fluid ounce)
Doing stuff like this without floating point is something I don't want
to even think about.
The conversion factors are all plain rational numbers. In the US that
is the case since 1866 and in the UK since 1995. So doing this with
integer operations only is very viable. (Yes, 1866 was not an error.)
The difference in the US between the survey foot and the standard foot
comes because originally (1866) the US linked the foot to the meter
by a reverse factor to that introduced in 1963. The original foot
remained in use in surveying. Something similar did happen with the
US pound, but here the original pound is no longer used (1 kg =
2.2046 lb in 1866, in 1893 adapted to 2.20462 and in 1894 to 2.20462234).
In 1959 changed to the current definition that was also adopted in the
UK in 1963.
But *all* measures in the US are tightly linked, through rational
conversion factors, to the metric system since 1866.
All this is trivial, I know, but I remain fascinated.
Using your UK ounce and multiplying by 160 for a UK gallon, I get
4546.09 milliliters. Dividing that by grams per pound gives 10.022412855
pounds per UK gallon. The Imperial Gallon was 10 pounds exactly.
How shall we accommodate this gross inaccuracy? Revisit the
International Standards somehow? :=)
In fun..
--
Joe Wright
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---
In article <Rp************ *************** ***@comcast.com Joe Wright <jo********@com cast.netwrites:
Dik T. Winter wrote:
....
All this is trivial, I know, but I remain fascinated.
Not so very trivial.
Using your UK ounce and multiplying by 160 for a UK gallon, I get
4546.09 milliliters. Dividing that by grams per pound gives 10.022412855
pounds per UK gallon. The Imperial Gallon was 10 pounds exactly.
It was. Since 1963 it was 10 pounds of water with density 0.998859 gr/ml
weighed in air of density 0.001217 gr/ml against weights of density
8.136 gr/ml. Weights and Measures Bill (G.B.), HC 70 (1963). Now
calculate the volume. Unless I seriously misunderstood Archimedes I
come at 1 gallon = 368987550040571 / 81168153120 ml, or about
4545.96459 ml.
And I think it is; just tweak some of the densities. With the densities
of 1963 I come at 368997729217300 8 / 368987550040571 or about
10.0002758678 pounds. Slightly better than you think, I would say.
Offhand I would not know densities of similar precision that give the
same result, but I think those might exist.
--
dik t. winter, cwi, kruislaan 413, 1098 sj amsterdam, nederland, +31205924131
home: bovenover 215, 1025 jn amsterdam, nederland; http://www.cwi.nl/~dik/
Joe Wright wrote:
ga*****@hotmail .com wrote:
>Konstantin Miller wrote:
>>ga*****@hotmail .com wrote:
I need to do just a few multiplies of long integers and have a divide by ten. Can I avoid using floats? Can I use two longs as a 64 bit value somehow? Thanks. Hi!
Can you specify more clearly what you want to do? :-)
Konstantin
I have some long values in Liters and I want to convert to gallons (and back). If I could do integer multiplication and divide by 10 I could avoid the float library. Thanks.
Not so simple I'd guess. Have a look at this..
One survey foot = 0.3048006096 meters.
One statute mile = 1.6093472187 kilometers.
One inch = 0.0254 meters (exactly).
One foot = 0.3048 meters (exactly).
One yard = 0.9144 meters (exactly).
One cubic inch = 16.387064 cubic centimeters (exactly).
One cubic foot = 28.316846592 liters (exactly).
One cubic foot = 7.48051948 US gallons.
One US gallon = 3.785411784 liters (exactly).
One ounce (fluid) = 29.573529562 milliliters.
One pound = 453.59237 grams (exactly).
One pound = 7000 grains (exactly).
One ounce (avdp) = 28.349523125 grams (exactly).
One ounce (avdp) = 437.5 grains (exactly).
One grain = 64.79891 milligrams (exactly).
One carat = 3.08647167 grains.
One meter = 39.37007874 inches.
One meter = 3.280839895 feet.
One meter = 1.093613298 yards.
One kilogram = 2.204622622 pounds.
One gram = 15.43235835 grains.
One gram = 0.035273962 ounces.
One US gallon (water) weighs 8.345404 pounds.
Ten pounds of water is 1.198264 US gallons.
Doing stuff like this without floating point is something I don't want
to even think about.
I take it you do not write embedded code.
I assume the OP is or why ask the question.
floating point is slow and uses a large chunk of RAM and ROM.
The required accuracy is what fits on the display.
besides even on big iron floating point has it's own issues. ga*****@hotmail .com wrote:
Eric Sosman wrote:
>[...] However, all these conversions, no matter how accurate an approximatio n you use, must eventually express the result as a whole number of gallons or liters. [...]
Not if I use some number of the least significant digits as a
"fractional " part. As you say the value is effectively in something
like milliliters. Thanks.
A lot of theory here.
If you want a real solution.
The range of liters.
The range of gallons.
The number of significant digits you want to display. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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