I have code like this :
void foo(int i, void* p) { .. }
class A
{
public:
A();
~A();
private:
void foobar(int i, char* c);
};
Is there a way for foo to call foobar() ? 3 1683
Lucy Ludmiller wrote:
I have code like this :
void foo(int i, void* p) { .. }
class A
{
public:
A();
~A();
private:
void foobar(int i, char* c);
};
Is there a way for foo to call foobar() ?
Sure:
void foo(int i, void* p)
{
A a;
a.foobar(i, static_cast<cha r*>(p));
}
But if your question is, can foo call foobar without an instance of
class A to call it with, the answer is no, unless you change foobar to
be a static member of A.
Best regards,
Tom
Thomas Tutone wrote:
Lucy Ludmiller wrote:
I have code like this :
void foo(int i, void* p) { .. }
class A
{
public:
A();
~A();
private:
void foobar(int i, char* c);
};
Is there a way for foo to call foobar() ?
Sure:
void foo(int i, void* p)
{
A a;
a.foobar(i, static_cast<cha r*>(p));
}
.... if class A declares foo as a friend:
class A
{
friend void foo(int i, void* p) ;
//.....
};
HTH
Radu
>
But if your question is, can foo call foobar without an instance of
class A to call it with, the answer is no, unless you change foobar to
be a static member of A.
you can declaring
Best regards,
Tom
Radu wrote:
Thomas Tutone wrote:
Lucy Ludmiller wrote:
I have code like this :
>
void foo(int i, void* p) { .. }
>
class A
{
public:
A();
~A();
private:
void foobar(int i, char* c);
};
>
Is there a way for foo to call foobar() ?
Sure:
void foo(int i, void* p)
{
A a;
a.foobar(i, static_cast<cha r*>(p));
}
... if class A declares foo as a friend:
class A
{
friend void foo(int i, void* p) ;
//.....
};
Good point - I missed that foo was private. Thanks for the
clarification.
Best regards,
Tom This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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Greetings everyone,
I'm including code, for cut/paste, to better explain my question. I create a Car object then I call some of its methods. No problem. Then I try to pass, to a function, the name of the Car object and the name of one of its methods. I found one way to get this to work but can someone show me a more orthodox way? Is there a way using references to the object and somehow the method?
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which situation should use the static function ?
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Thanks
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