fork inside an for

[mutley]

for(i=1;i<CONFI G_POLLER_FORKS; i++)
{
if((pid = fork()) == 0)
{
server_num=i;
break;
}
else
{
pids[i-1]=pid;
}
}

in this code:
the fork occurs just inside this little cut of code, I don't understand
if,
- in first fork(),
is create a child and it entries in if,
server_num receive a number 1
in break; i don't understand if, both child and parent break, or
just parent, and this child, continue or
execute de for() white parent?

excuse-me my inglish, I'm brazilian

[Kenny McCormack]

In article <11************ ********@i3g200 0cwc.googlegrou ps.com>,
mutley <mu***********@ gmail.comwrote:

>for(i=1;i<CONF IG_POLLER_FORKS ;i++)
{
if((pid = fork()) == 0)

Allow me to be the first (of many) to say:

Not portable. Can't discuss it here. Blah, blah, blah.

[Richard]

"mutley" <mu***********@ gmail.comwrites :

for(i=1;i<CONFI G_POLLER_FORKS; i++)
{
if((pid = fork()) == 0)
{
server_num=i;
break;
}
else
{
pids[i-1]=pid;
}
}

in this code:
the fork occurs just inside this little cut of code, I don't understand
if,
- in first fork(),
is create a child and it entries in if,
server_num receive a number 1
in break; i don't understand if, both child and parent break, or
just parent, and this child, continue or
execute de for() white parent?

Its offtopic here, but ...

fork creates a NEW process. The break in the child code breaks to outside
the for loop : in a different address space. So effectively fork returns
twice - once in the child process and once in the parent process (the
else statement). The break cant break the parent because in the parent
fork return 0 - so the else statement is reached.

There are lots of tutorials available : use google.

http://yolinux.com/TUTORIALS/ForkExecProcesses.html

[Frederick Gotham]

Troll Alert: Kenny McCormack

The only way to deal with trolls is to limit your reaction to reminding
others not to respond to trolls.

Information on trolls: http://members.aol.com/intwg/trolls.htm

--

Frederick Gotham

[Keith Thompson]

Richard <rg****@gmail.c omwrites:

"mutley" <mu***********@ gmail.comwrites :

>for(i=1;i<CONF IG_POLLER_FORKS ;i++)
{
if((pid = fork()) == 0)
{
server_num=i;
break;
}
else
{
pids[i-1]=pid;
}
}

[snip]

Its offtopic here, but ...

[snip]

.... it's on topic on comp.unix.progr ammer.

(Please don't try to answer off-topic questions, especially when
there's a group where it's topical, full of experts who probably know
more about this than either of us.)

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.

[Keith Thompson]

Frederick Gotham <fg*******@SPAM .comwrites:

Troll Alert: Kenny McCormack

The only way to deal with trolls is to limit your reaction to reminding
others not to respond to trolls.

Information on trolls: http://members.aol.com/intwg/trolls.htm

Frederick, at this point I think almost everyone is aware that KM is a
troll, and most of us have been doing a good job of ignoring him. By
posting this followup every time he posts, you're giving him more
attention.

My suggestion: Ignore him completely. If anyone else posts a
followup, post a gentle reminder not to feed the troll (unless someone
else has already done so).

You might also consider killfiling him, but that's entirely up to you.

Your efforts are appreciated, but I don't believe they're necessary.

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.