Hi all,
I am working on RedHat Linux GCC 3.0.
I am trying to convert a long to string through sprintf.
but i m getting segmantation fault.
I tried snprintf also but no avail.here is the piece of code..
----------------------------
long myLong=200000;
char myStr[50];
memset[myStr,'\0',50];
sprintf(myStr," %s",myLong);
-------------------------------------
This sprintf causes segmentation fault.
Hoping for help.
Saurabh
10  4211 
Saurabh wrote: Hi all,
I am working on RedHat Linux GCC 3.0.
I am trying to convert a long to string through sprintf.
but i m getting segmantation fault.
I tried snprintf also but no avail.here is the piece of code..
----------------------------
long myLong=200000;
char myStr[50];
memset[myStr,'\0',50];
sprintf(myStr," %s",myLong);
^
%s is for printing (C style) strings.
use %ld, or use iostreams.
--
Ian Collins.
Ian Collins wrote: Saurabh wrote: Hi all,
I am working on RedHat Linux GCC 3.0.
I am trying to convert a long to string through sprintf.
but i m getting segmantation fault.
I tried snprintf also but no avail.here is the piece of code..
----------------------------
long myLong=200000;
char myStr[50];
memset[myStr,'\0',50];
sprintf(myStr," %s",myLong);
^
%s is for printing (C style) strings.
use %ld, or use iostreams.
--
Ian Collins.
hi Ian,
Thanks a lot.
You solved my problem.
actually I thought that the second argument to
sprintf() refers to the format you wish to convert
to,instead it refers to the format you wish to
convert from.
anyways..
thanks again.
saurabh
Saurabh wrote: Ian Collins wrote: Saurabh wrote: Hi all,
I am working on RedHat Linux GCC 3.0.
I am trying to convert a long to string through sprintf.
but i m getting segmantation fault.
I tried snprintf also but no avail.here is the piece of code..
----------------------------
long myLong=200000;
char myStr[50];
memset[myStr,'\0',50];
sprintf(myStr," %s",myLong);
^
%s is for printing (C style) strings.
use %ld, or use iostreams.
--
Ian Collins.
hi Ian,
Thanks a lot.
You solved my problem.
actually I thought that the second argument to
sprintf() refers to the format you wish to convert
to,instead it refers to the format you wish to
convert from.
anyways..
thanks again.
saurabh
I would suggest that if you are STILL using sprinf, then you haven't
fixed the problem, it will surely break one day. Why not use
boost::lexical_ cast (or you're own similar code) instead.
Geo wrote: Saurabh wrote: Ian Collins wrote: Saurabh wrote:
> Hi all,
>
> I am working on RedHat Linux GCC 3.0.
> I am trying to convert a long to string through sprintf.
> but i m getting segmantation fault.
> I tried snprintf also but no avail.here is the piece of code..
>
> ----------------------------
> long myLong=200000;
> char myStr[50];
> memset[myStr,'\0',50];
> sprintf(myStr," %s",myLong);
^
%s is for printing (C style) strings.
use %ld, or use iostreams.
--
Ian Collins.
hi Ian,
Thanks a lot.
You solved my problem.
actually I thought that the second argument to
sprintf() refers to the format you wish to convert
to,instead it refers to the format you wish to
convert from.
anyways..
thanks again.
saurabh
I would suggest that if you are STILL using sprinf, then you haven't
fixed the problem, it will surely break one day. Why not use
boost::lexical_ cast (or you're own similar code) instead.
hi Geo,
I have never used boost::lexical_ cast.Is this an STL component?
or are you hinting me to write my own version of sprintf()?
Thanks & Regards
saurabh
Saurabh wrote: Geo wrote: Saurabh wrote: Ian Collins wrote:
> Saurabh wrote:
> > Hi all,
> >
> > I am working on RedHat Linux GCC 3.0.
> > I am trying to convert a long to string through sprintf.
> > but i m getting segmantation fault.
> > I tried snprintf also but no avail.here is the piece of code..
> >
> > ----------------------------
> > long myLong=200000;
> > char myStr[50];
> > memset[myStr,'\0',50];
> > sprintf(myStr," %s",myLong);
> ^
> %s is for printing (C style) strings.
>
> use %ld, or use iostreams.
>
> --
> Ian Collins.
hi Ian,
Thanks a lot.
You solved my problem.
actually I thought that the second argument to
sprintf() refers to the format you wish to convert
to,instead it refers to the format you wish to
convert from.
anyways..
thanks again.
saurabh
I would suggest that if you are STILL using sprinf, then you haven't
fixed the problem, it will surely break one day. Why not use
boost::lexical_ cast (or you're own similar code) instead.
hi Geo,
I have never used boost::lexical_ cast.Is this an STL component?
or are you hinting me to write my own version of sprintf()?
Thanks & Regards
saurabh
Hi,
No I was suggesting you write you're own lexical cast function, if you
can't use boost. You could start with something like this, you may want
to make this more robust,
template<typena me out, typename in> out lexical_cast(co nst in &i)
{
std::stringstre am ss;
ss << i;
out temp;
ss >> temp;
return temp;
}
then do
int x = 123;
std::string s = lexical_cast<st d::string>(x);
you can also do the reverse
std::string s = "5678";
int z = lexical_cast<in t>(s);
Saurabh wrote: memset[myStr,'\0',50];
Take this line out of your code.
Old Wolf wrote: Saurabh wrote:
memset[myStr,'\0',50];
Take this line out of your code.
Yep, Agree.
And use %d instead of %s.It makes your program think that your 'MyLong'
as a pointer to characters.
Saurabh wrote: I have never used boost::lexical_ cast.Is this an STL component?
or are you hinting me to write my own version of sprintf()?
Thanks & Regards
saurabh
I would not suggest boost::lexical_ cast here. The boost equivalent of
sprintf is boost::format.
lexical_cast is useful for converting the other way, i.e. string to
integer.
Geo wrote: Saurabh wrote: Geo wrote: Saurabh wrote:
> Ian Collins wrote:
> > Saurabh wrote:
> > > Hi all,
> > >
> > > I am working on RedHat Linux GCC 3.0.
> > > I am trying to convert a long to string through sprintf.
> > > but i m getting segmantation fault.
> > > I tried snprintf also but no avail.here is the piece of code..
> > >
> > > ----------------------------
> > > long myLong=200000;
> > > char myStr[50];
> > > memset[myStr,'\0',50];
> > > sprintf(myStr," %s",myLong);
> > ^
> > %s is for printing (C style) strings.
> >
> > use %ld, or use iostreams.
> >
> > --
> > Ian Collins.
>
> hi Ian,
> Thanks a lot.
> You solved my problem.
> actually I thought that the second argument to
> sprintf() refers to the format you wish to convert
> to,instead it refers to the format you wish to
> convert from.
> anyways..
> thanks again.
> saurabh
I would suggest that if you are STILL using sprinf, then you haven't
fixed the problem, it will surely break one day. Why not use
boost::lexical_ cast (or you're own similar code) instead.
hi Geo,
I have never used boost::lexical_ cast.Is this an STL component?
or are you hinting me to write my own version of sprintf()?
Thanks & Regards
saurabh
Hi,
No I was suggesting you write you're own lexical cast function, if you
can't use boost. You could start with something like this, you may want
to make this more robust,
template<typena me out, typename in> out lexical_cast(co nst in &i)
{
std::stringstre am ss;
ss << i;
out temp;
ss >> temp;
return temp;
}
but g++ told me that:
In function `out lexical_cast(co nst in&) [with out = std::string, in =
int]':
instantiated from here
error: `ss' has incomplete type
error: storage size of `ss' isn't known
then do
int x = 123;
std::string s = lexical_cast<st d::string>(x);
you can also do the reverse
std::string s = "5678";
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