All,
Well, now i modify a bit my code:
Will it make sense?
void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}
regards,
Vynce
4  2233 
"asimorio" <th******@gmail .com> wrote in message
| All,
| Well, now i modify a bit my code:
| Will it make sense?
It will only be legal if the memory pointed to by a has been obtained by a
call to new operator. Also if the pointer is NULL, then delete has no
effects.
Sharad
| void A::Foo(void* a)
| {
| char* buffer = (char*) a;
| delete buffer;
| return;
| }
"asimorio" <th******@gmail .com> wrote in message
news:11******** *************@i 39g2000cwa.goog legroups.com... All,
Well, now i modify a bit my code:
Will it make sense?
void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}
It depends if a was allocated with new or not. If a was allocated with new,
it is legal. If it was not allocated with new, it is undefined and will
most likely cause a memory fault.
asimorio posted: All,
Well, now i modify a bit my code:
Will it make sense?
void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}
There are two sole conditions under which that would work:
int main()
{
A::Foo( new char );
A::Foo( 0 );
}
-Tomás
asimorio wrote: All,
Well, now i modify a bit my code:
Will it make sense?
void A::Foo(void* a)
{
char* buffer = (char*) a;
delete buffer;
return;
}
What are actually trying to do? What problem are you solving? What you
propose is rarely a good idea.
Brian This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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