lgamma function: ANSI C or not?

[Bart Vandewoestyne]

I'm having a .c source file which at the top contains the line

#include <math.h>

In that source file, i declare a function dt which in its body uses
the lgamma function. `man lgamma' on my linux system tells me
that i have to include math.h so it seems like I'm doing the
right thing in order to be able to use the lgamma function.

When I compile the .c file with

$ gcc -ansi -c rand.c

or

$ gcc -Wall -c rand.c

then I get no errors or warnings. When I compile it with

$ gcc -Wall -ansi -c rand.c

I get the warning:

rand.c: In function `dt':
rand.c:544: warning: implicit declaration of function `lgamma'

which seems strange to me. Why am I getting this warning and how do I
resolve this warning? I assume it has something to do with ANSI C or not,
but I'm confused...

Thanks,
Bart

PS: the version of gcc I'm using is gcc (GCC) 3.3.5 (Debian 1:3.3.5-13).
Upgrading to a newer version is no option because I do not have admin rights
to install or upgrade packages on my system.

--
"Share what you know. Learn what you don't."

[Vladimir Oka]

Bart Vandewoestyne wrote:

I'm having a .c source file which at the top contains the line

#include <math.h>

In that source file, i declare a function dt which in its body uses
the lgamma function. `man lgamma' on my linux system tells me
that i have to include math.h so it seems like I'm doing the
right thing in order to be able to use the lgamma function.

When I compile the .c file with

$ gcc -ansi -c rand.c

or

$ gcc -Wall -c rand.c

then I get no errors or warnings. When I compile it with

$ gcc -Wall -ansi -c rand.c

I get the warning:

rand.c: In function `dt':
rand.c:544: warning: implicit declaration of function `lgamma'

which seems strange to me. Why am I getting this warning and how do I
resolve this warning? I assume it has something to do with ANSI C or not,
but I'm confused...

Thanks,
Bart

PS: the version of gcc I'm using is gcc (GCC) 3.3.5 (Debian 1:3.3.5-13).
Upgrading to a newer version is no option because I do not have admin rights
to install or upgrade packages on my system.

Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

[P.J. Plauger]

"Bart Vandewoestyne" <My************ ********@telene t.be> wrote in message
news:11******** *******@seven.k ulnet.kuleuven. ac.be...

I'm having a .c source file which at the top contains the line

#include <math.h>

In that source file, i declare a function dt which in its body uses
the lgamma function. `man lgamma' on my linux system tells me
that i have to include math.h so it seems like I'm doing the
right thing in order to be able to use the lgamma function.

When I compile the .c file with

$ gcc -ansi -c rand.c

or

$ gcc -Wall -c rand.c

then I get no errors or warnings. When I compile it with

$ gcc -Wall -ansi -c rand.c

I get the warning:

rand.c: In function `dt':
rand.c:544: warning: implicit declaration of function `lgamma'

which seems strange to me. Why am I getting this warning and how do I
resolve this warning? I assume it has something to do with ANSI C or not,
but I'm confused...

lgamma is required by C99 and the Single Unix Specification
(effectively Posix). It is found in some older math libraries,
but not all.

P.J. Plauger
Dinkumware, Ltd.
http://www.dinkumware.com

[Bart Vandewoestyne]

On 2006-05-09, Vladimir Oka <no****@btopenw orld.com> wrote:

Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

Indeed: this doesn't generate warnings:

$ gcc -Wall -std=c99 -c rand.c

This does:

$ gcc -Wall -std=c89 -c rand.c
rand.c: In function `dt':
rand.c:545: warning: implicit declaration of function `lgamma'
So my options are:

* implement lgamma myself if i want to be c89 compatible
* don't try to be c89 compatible and compile with -std=c99

Thanks!
Bart

--
"Share what you know. Learn what you don't."

[Flash Gordon]

Bart Vandewoestyne wrote:

I'm having a .c source file which at the top contains the line

#include <math.h>

In that source file, i declare a function dt which in its body uses
the lgamma function. `man lgamma' on my linux system tells me
that i have to include math.h so it seems like I'm doing the
right thing in order to be able to use the lgamma function.
Yes you are.
When I compile the .c file with

$ gcc -ansi -c rand.c

or

$ gcc -Wall -c rand.c

then I get no errors or warnings. When I compile it with

$ gcc -Wall -ansi -c rand.c

I get the warning:

rand.c: In function `dt':
rand.c:544: warning: implicit declaration of function `lgamma'

which seems strange to me. Why am I getting this warning and how do I
resolve this warning? I assume it has something to do with ANSI C or not,
but I'm confused...

Yes and no. It was not part of the original ANSI standard but it is part
of the latest C standard known colloquially as C99. See
http://clc-wiki.net/wiki/c_standard for more about the various versions
of the C standard.

<OT>
With gcc you could try using -std=c99 instead of -ansi, however you
should be aware that gcc does not fully implement C99.

My man page for lgamma included
| CONFORMING TO
| C99, SVID 3, BSD 4.3

which tells you that it is C99 and which other standard provided it as
an extension to C.
</OT>

If you need further help on getting gcc to recognise the lgamma function
gnu.gcc.help could be useful.
--
Flash Gordon, living in interesting times.
Web site - http://home.flash-gordon.me.uk/
comp.lang.c posting guidelines and intro:
http://clc-wiki.net/wiki/Intro_to_clc

Inviato da X-Privat.Org - Registrazione gratuita http://www.x-privat.org/join.php

[Tim Prince]

Bart Vandewoestyne wrote:

On 2006-05-09, Vladimir Oka <no****@btopenw orld.com> wrote:

Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

Indeed: this doesn't generate warnings:

$ gcc -Wall -std=c99 -c rand.c

This does:

$ gcc -Wall -std=c89 -c rand.c
rand.c: In function `dt':
rand.c:545: warning: implicit declaration of function `lgamma'
So my options are:

* implement lgamma myself if i want to be c89 compatible
* don't try to be c89 compatible and compile with -std=c99

or, you could edit <math.h> and remove the c99 guard on math functions
you consider eligible for c89 compatibility.

[Flash Gordon]

Bart Vandewoestyne wrote:

On 2006-05-09, Vladimir Oka <no****@btopenw orld.com> wrote:

Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

Indeed: this doesn't generate warnings:

$ gcc -Wall -std=c99 -c rand.c

This does:

$ gcc -Wall -std=c89 -c rand.c
rand.c: In function `dt':
rand.c:545: warning: implicit declaration of function `lgamma'
So my options are:

* implement lgamma myself if i want to be c89 compatible
* don't try to be c89 compatible and compile with -std=c99

If you chose to implement it yourself then I would strongly suggest
using a different name. That way you avoid confusion.
--
Flash Gordon, living in interesting times.
Web site - http://home.flash-gordon.me.uk/
comp.lang.c posting guidelines and intro:
http://clc-wiki.net/wiki/Intro_to_clc

[Ico]

Bart Vandewoestyne <My************ ********@telene t.be> wrote:

I'm having a .c source file which at the top contains the line

#include <math.h>

In that source file, i declare a function dt which in its body uses
the lgamma function. `man lgamma' on my linux system tells me
that i have to include math.h so it seems like I'm doing the
right thing in order to be able to use the lgamma function.

When I compile the .c file with

$ gcc -ansi -c rand.c

or

$ gcc -Wall -c rand.c

then I get no errors or warnings. When I compile it with

$ gcc -Wall -ansi -c rand.c

I get the warning:

rand.c: In function `dt':
rand.c:544: warning: implicit declaration of function `lgamma'

which seems strange to me. Why am I getting this warning and how do I
resolve this warning? I assume it has something to do with ANSI C or not,
but I'm confused...

The manpages also have information on conformaing standards: look a bit
further down in the same manpage :

CONFORMING TO
C99, SVID 3, 4.3BSD

As you can see, ANSI is not in the list
--
:wq
^X^Cy^K^X^C^C^C ^C

[Flash Gordon]

Tim Prince wrote:

Bart Vandewoestyne wrote:

On 2006-05-09, Vladimir Oka <no****@btopenw orld.com> wrote:

Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

Indeed: this doesn't generate warnings:

$ gcc -Wall -std=c99 -c rand.c

This does:

$ gcc -Wall -std=c89 -c rand.c
rand.c: In function `dt':
rand.c:545: warning: implicit declaration of function `lgamma'
So my options are:

* implement lgamma myself if i want to be c89 compatible
* don't try to be c89 compatible and compile with -std=c99

or, you could edit <math.h> and remove the c99 guard on math functions
you consider eligible for c89 compatibility.

This is probably a bad idea for several reasons. It could break valid
C89 code (e.g. code that defines an lgamma function with a different
prototype) which you might not hit until months or years later, the C99
stuff may depend on compiler support which is only enabled when C99
support is enabled, it may depend on things in other headers that are
only enabled when C99 is enabled etc. Also the OP does not have admin
writes so probably can't do this anyway.
--
Flash Gordon, living in interesting times.
Web site - http://home.flash-gordon.me.uk/
comp.lang.c posting guidelines and intro:
http://clc-wiki.net/wiki/Intro_to_clc

[P.J. Plauger]

"Flash Gordon" <sp**@flash-gordon.me.uk> wrote in message
news:ko******** ****@news.flash-gordon.me.uk...

Tim Prince wrote:

Bart Vandewoestyne wrote:

On 2006-05-09, Vladimir Oka <no****@btopenw orld.com> wrote:
Function `lgamma()` is only available in C99. GCC `-ansi` assumes C89
(same as `-std=c89`). Therein lies your problem. Have you tried
`-std=c99` instead?

Indeed: this doesn't generate warnings:

$ gcc -Wall -std=c99 -c rand.c

This does:

$ gcc -Wall -std=c89 -c rand.c
rand.c: In function `dt':
rand.c:545: warning: implicit declaration of function `lgamma'
So my options are:

* implement lgamma myself if i want to be c89 compatible
* don't try to be c89 compatible and compile with -std=c99

or, you could edit <math.h> and remove the c99 guard on math functions
you consider eligible for c89 compatibility.

This is probably a bad idea for several reasons. It could break valid C89
code (e.g. code that defines an lgamma function with a different
prototype) which you might not hit until months or years later, the C99
stuff may depend on compiler support which is only enabled when C99
support is enabled, it may depend on things in other headers that are only
enabled when C99 is enabled etc. Also the OP does not have admin writes so
probably can't do this anyway.

Most of those reasons are pretty esoteric, and not likely to matter
in real life. Nevertheless, I agree that it's a bad idea to edit
system headers. Besides, chances are all you have to do is put:

double (lgamma)(double );

at the top of the source file that calls the function. (The parens are
to protect the declaration against a macro override that may one day
come along.)

P.J. Plauger
Dinkumware, Ltd.
http://www.dinkumware.com