Hi,
I have a method like this:
const A* getMaxArea(cons t vector<A*>& aList);
And in my caller, i have this:
A* const a = NULL;
if (!aList.empty() ) {
a = getMaxArea(aLis t);
//.....
}
But I get this compile error:
.../NavBarGroupResu ltListProcessor .cpp:49: error: assignment of
read-only variable 'a'
Can you please tell me what is the pointer,
i think
A* const a // is a pointer to 'const a', not a const pointer to 'a', so
I should be able to assign it, right? 5 19034
<yi*****@gmail. com> wrote in message
news:11******** **************@ i39g2000cwa.goo glegroups.com.. . Hi,
I have a method like this:
const A* getMaxArea(cons t vector<A*>& aList);
And in my caller, i have this:
A* const a = NULL;
if (!aList.empty() ) { a = getMaxArea(aLis t); //..... }
But I get this compile error: ../NavBarGroupResu ltListProcessor .cpp:49: error: assignment of read-only variable 'a'
Can you please tell me what is the pointer, i think A* const a // is a pointer to 'const a', not a const pointer to 'a', so I should be able to assign it, right?
I believe it should be read from right to left: 'a' is a const pointer to
'A'. Therefore, 'a' (the pointer) is constant and may not be re-assigned.
- Dennis yi*****@gmail.c om wrote: I have a method like this:
const A* getMaxArea(cons t vector<A*>& aList);
And in my caller, i have this:
A* const a = NULL;
if (!aList.empty() ) { a = getMaxArea(aLis t); //..... }
But I get this compile error: ../NavBarGroupResu ltListProcessor .cpp:49: error: assignment of read-only variable 'a'
Can you please tell me what is the pointer, i think A* const a // is a pointer to 'const a', not a const pointer to 'a', so I should be able to assign it, right?
No, it is a const pointer to an object of type 'A'. Always read the
types from right to left.
Changing the type to 'A const*' will fix your problem, as far as I
can see.
hth
--
jb
(reply address in rot13, unscramble first)
Thanks. It works.
I have another question:
I have another funcion, which is this:
void f1(const A* aPtr);
A const *a = NULL;
if (!aList.empty() ) {
a = getMaxArea(aLis t);
// try to call f1() here,
const A* a1 = a;
f1 (a1); // won't compile due to error: invalid conversion from
'const A*' to 'A*'
}
Any idea?
On Sat, 29 Apr 2006 09:29:44 -0700, yinglcs wrote: Thanks. It works.
I have another question:
I have another funcion, which is this:
void f1(const A* aPtr);
A const *a = NULL;
if (!aList.empty() ) { a = getMaxArea(aLis t);
// try to call f1() here, const A* a1 = a; f1 (a1); // won't compile due to error: invalid conversion from 'const A*' to 'A*' }
Any idea?
Yes, your f1() function isn't declared to take a pointer to const. yi*****@gmail.c om wrote: Thanks. It works.
I have another question:
I have another funcion, which is this:
void f1(const A* aPtr);
A const *a = NULL;
if (!aList.empty() ) { a = getMaxArea(aLis t);
// try to call f1() here, const A* a1 = a; f1 (a1); // won't compile due to error: invalid conversion from 'const A*' to 'A*' }
Any idea?
Are you sure the code above is actually the code that won't compile?
After writing code to put it in a suitable context it compiled just fine
for me. (By the way, when posting example code it helps a lot if you
provide something that can be directly cut and paste without any
additional context needed.)
For what it's worth, "const A *" and "A const *" are the same type, both
meaning "pointer to a const A".
--
Alan Johnson This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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