is there a better way to compare 2 stl list? I write a function like
this below, but I wonder if there is a better way to achieve that (e.g.
less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) {
if (srcList.size() != destList.size() ) {
return false;
}
int size = srcList.size();
for (int i = 0; i < size; i++) {
if (srcList[i] != destList[i]) {
return false;
}
}
return true;
}
Thank you. 5 13024 si************* **@gmail.com wrote: is there a better way to compare 2 stl list? I write a function like this below, but I wonder if there is a better way to achieve that (e.g. less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) { if (srcList.size() != destList.size() ) { return false; }
int size = srcList.size(); for (int i = 0; i < size; i++) { if (srcList[i] != destList[i]) { return false; } }
return true; }
I suppose you did not compile this, did you? Try it .. it will fail
to compile, because std::list does not have an 'operator []'.
Try this instead:
bool isSame (std::list <int> const& l1, std::list <int> const& l2)
{
if (l1.size () == l2.size ())
return std::equal (l1.begin (), l1.end (), l2.begin ());
else
return false;
}
hth
--
jb
(reply address in rot13, unscramble first)
Hello
AFAIK, lists implement '==' operator.
So just test as:
bool isSame = list1 == list2;
Also check the std::equal()
--
Elias
<si************ ***@gmail.com> wrote in message
news:11******** **************@ z34g2000cwc.goo glegroups.com.. . is there a better way to compare 2 stl list? I write a function like this below, but I wonder if there is a better way to achieve that (e.g. less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) { if (srcList.size() != destList.size() ) { return false; }
int size = srcList.size(); for (int i = 0; i < size; i++) { if (srcList[i] != destList[i]) { return false; } }
return true; }
Thank you. si************* **@gmail.com skrev: is there a better way to compare 2 stl list? I write a function like this below, but I wonder if there is a better way to achieve that (e.g. less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) { if (srcList.size() != destList.size() ) { return false; }
int size = srcList.size(); for (int i = 0; i < size; i++) { if (srcList[i] != destList[i]) { return false; } }
return true; }
Thank you.
How about list1 == list2?
/Peter si************* **@gmail.com wrote: is there a better way to compare 2 stl list? I write a function like this below, but I wonder if there is a better way to achieve that (e.g. less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) { if (srcList.size() != destList.size() ) { return false; }
int size = srcList.size(); for (int i = 0; i < size; i++) { if (srcList[i] != destList[i]) { return false; } }
return true; }
Thank you.
Hello,
How about operator ==() ?
See
"http://www.dinkumware. com/manuals/reader.aspx?b=p/&h=list.html#op erator==" si************* **@gmail.com wrote: is there a better way to compare 2 stl list? I write a function like this below, but I wonder if there is a better way to achieve that (e.g. less code)?
bool isSame(const list<int>& srcList, const list<int>& destList ) { if (srcList.size() != destList.size() ) { return false; }
int size = srcList.size(); for (int i = 0; i < size; i++) { if (srcList[i] != destList[i]) { return false; } }
return true; }
Thank you.
What's wrong with
srcList == destList
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