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Dealing with a large integer

Hi all

I have an large integer in this format
x1*256^5 + x2*256^4 + x3*256^3 + x4*256^2 + x5*256 + x6
now I must convert it to this format
y1*900^4 + y2*900^3 + y3*900^2 + y4*900 + y5

x1-x5 is given.I must get y1-y4 from it.

How can I do this on my 32bit PC?

Sorry for that my English is poor.

Thanks.

Mar 3 '06
42 3377
On 6 Mar 2006 19:50:19 GMT, in comp.lang.c , Jordan Abel
<ra*******@gmai l.com> wrote:
Post code that you think safely uses gets and i'll prove it wrong within
the context of the API you are using to "ensure" it.
This is such an easy challenge to defeat, I won't embarrass you.
[well, i'm hoping
you're using the unix api, since i wouldn't have the first clue about
any other one]


Quite.
Mark McIntyre
--
"Debugging is twice as hard as writing the code in the first place.
Therefore, if you write the code as cleverly as possible, you are,
by definition, not smart enough to debug it."
--Brian Kernighan

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Mar 6 '06 #41
On Mon, 06 Mar 2006 12:34:53 -0800, in comp.lang.c , Ben Pfaff
<bl*@cs.stanfor d.edu> wrote:
ro******@ibd.n rc-cnrc.gc.ca (Walter Roberson) writes:
In article <sl************ ***********@ran dom.yi.org>,
Jordan Abel <ra*******@gmai l.com> wrote:
Post code that you think safely uses gets and i'll prove it wrong within
the context of the API you are using to "ensure" it. [well, i'm hoping
you're using the unix api, since i wouldn't have the first clue about
any other one]


How about something like this:

Open a file w+. Write known data into it. fseek() back to the
beginning of the file. gets() with a buffer at least as big as
the data to be written.


gets() reads from stdin. You'll have to use freopen() to replace
stdin by your file. Seems like a pretty big stretch to make just
to use gets() safely, when you could just use a better designed
function instead.


Nobody's arguing that its sensible to use gets(), merely with the
assertion that its "impossible " to use safely, even in a controlled
envrionment.

Heck if nuclear waste and anthrax can be safe, in the right
environment then ...
Mark McIntyre
--
"Debugging is twice as hard as writing the code in the first place.
Therefore, if you write the code as cleverly as possible, you are,
by definition, not smart enough to debug it."
--Brian Kernighan

----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet News==----
http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups
----= East and West-Coast Server Farms - Total Privacy via Encryption =----
Mar 6 '06 #42
russell kym horsell wrote:
yong <yo************ ****@gmail.com> wrote:
Hi all
I have an large integer in this format


[lemm call this X:]
x1*256^5 + x2*256^4 + x3*256^3 + x4*256^2 + x5*256 + x6
now I must convert it to this format


[Y:]
y1*900^4 + y2*900^3 + y3*900^2 + y4*900 + y5
x1-x5 is given.I must get y1-y4 from it.
How can I do this on my 32bit PC?
Sorry for that my English is poor.
Thanks.


Some kind of pdf encoder, eh?
There's probably a lot of literature on smart tricks, but
the basic idea (beside simply using 64-bit integers and brute force --
BTW even 32-bit PC's can do h/w 64-bit arith these days) is to note that

X % 900 = Y % 900 = y4.

Then we see that
256^5 % 900 = 376
256^4 % 900 = 796
256^3 % 900 = 316
256^2 % 900 = 736
256^1 % 900 = 256

So we must have y4 = (376*x1 + 796*x2 + 316*x3 + 736*x4 + 256*x5 + x6) % 900 .
(Look, maw, only 16-bit arithmetic!)

Similiarly for the other y_i.


Thanks.

It's really a good idea. :]

--
My Personal Weblog:
http://spaces.msn.com/cyberisblue
Mar 13 '06 #43

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