Can Any one tell me why this program is crashing .
testFunc()
{
int a1[10], *ptr ;
f=&a1[0];
f=f+1;
return 0;
} 8 2045
code break wrote: Can Any one tell me why this program is crashing .
NO. For why, see below. testFunc()
int testFunc(void) /* much better style */
{ int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
Because it's not a program? Show as a compilable minimum C program that
exhibits whatever problem you have. What you posted does not even
compile as a separate compilation unit to be later linked into a proper
program (e.g. you never define `f`).
code break wrote: Can Any one tell me why this program is crashing .
testFunc() { int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
A minimal program code please. What is f ?
This is not crashing its working absolutely fine.
Vladimir S. Oka wrote: code break wrote: Can Any one tell me why this program is crashing .
NO. For why, see below.
testFunc()
int testFunc(void) /* much better style */
{ int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
Because it's not a program? Show as a compilable minimum C program that exhibits whatever problem you have. What you posted does not even compile as a separate compilation unit to be later linked into a proper program (e.g. you never define `f`).
This is not crashing its working absolutely fine.
Vladimir S. Oka wrote: code break wrote: Can Any one tell me why this program is crashing .
NO. For why, see below.
testFunc()
int testFunc(void) /* much better style */
{ int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
Because it's not a program? Show as a compilable minimum C program that exhibits whatever problem you have. What you posted does not even compile as a separate compilation unit to be later linked into a proper program (e.g. you never define `f`).
Nikunj Shah wrote: This is not crashing its working absolutely fine.
Please don't top post.
While you're at it, can you explain exactly how this works "absolutely
fine"?
Vladimir S. Oka wrote: code break wrote: Can Any one tell me why this program is crashing .
NO. For why, see below.
testFunc()
int testFunc(void) /* much better style */
{ int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
Because it's not a program? Show as a compilable minimum C program that exhibits whatever problem you have. What you posted does not even compile as a separate compilation unit to be later linked into a proper program (e.g. you never define `f`).
code break wrote: Can Any one tell me why this program is crashing .
What program. I can't see a program in your post; all I see is a
function.
testFunc()
int testFunc(void)
or
int testFunc(...) /* this looks strange. I have to review variable
argument list material */
I prefer to specify return type and parameters explicitly rather than
relying on the defaults.
{ int a1[10], *ptr ;
f=&a1[0];
There's no scope for `f' at this point (unless it's a global variable).
Assuming it's been declared as int* or void*, I'd write that as
f = a1;
because the name of an array specifies the address of its first element,
and, for a simple assignment to a pointer the redundant "&" and "[0]"
actally make it less legible for me.
f=f+1; return 0;
ptr has been declared but has never been used. Delete its declaration.
}
If you really have this function in some code of yours, as what it
really does is just return 0 to the caller, I think you could make your
program much simpler by removing the function and replacing it with a
constant zero instead;
Example (where foo has been defined as a int):
if (foo == testFunc()) { /* do something */ }
/* replace last line with */
if (foo == 0) { /* do something */ }
--
If you're posting through Google read <http://cfaj.freeshell. org/google>
code break wrote: Can Any one tell me why this program is crashing .
testFunc() { int a1[10], *ptr ;
f=&a1[0]; f=f+1; return 0; }
What the f()***!
--
==============
*Not a pedant*
==============
Pedro Graca <he****@dodgeit .com> writes: code break wrote:
[...] testFunc()
int testFunc(void)
or
int testFunc(...) /* this looks strange. I have to review variable argument list material */
A prototype with "..." requires at least one parameter before the "...".
Since testFunc doesn't use va_arg, there's no reason for it to have a
"..." in its prototype anyway.
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
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