problem calling method from parent of an object if object relayson template arguments of current template class?

[Rafał Maj Raf256]

Test case:

#include <boost/shared_ptr.hpp>

using namespace boost;

template <typename typ1> class cData {
public:
template <typename T> T As() { } // As
};
template <typename D, typename T>
class cTaggedData : public cData<D> {
public:
};

template <typename D, typename T>
class cAttr : public cTaggedData<D,T > {
public:
};

template <typename D, typename T>
class cNode : public cTaggedData<D,T > {
public:

shared_ptr< cAttr<D,T> > RetAttr() { }
template <typename X> X MyAs(T t, X& x) {
#line 100
shared_ptr< cAttr<int,int> > attr1; attr1->As<int>(); // works
#line 200
shared_ptr< cAttr<D,T> > attr2; attr2->As<int>(); // FAILS
#line 300
shared_ptr< cAttr<int,int> > attr3; attr3->As<X>(); // works
#line 400
shared_ptr< cAttr<D,T> > attr4; attr4->As<X>(); // my goal, FAILS
} // As

};
/*
gives:

x.cpp: In member function 'X cNode<D, T>::MyAs(T, X&)':
x.cpp:200: error: expected primary-expression before 'int'
x.cpp:200: error: expected `;' before 'int'
x.cpp:400: error: expected primary-expression before '>' token
x.cpp:400: error: expected primary-expression before ')' token
*/

int main() { }

How to fix thoes two errors? Especially the 400 one?

[Alf P. Steinbach]

* Rafał Maj Raf256:

Test case:

#include <boost/shared_ptr.hpp>

using namespace boost;

template <typename typ1> class cData {
public:
template <typename T> T As() { } // As
};
template <typename D, typename T>
class cTaggedData : public cData<D> {
public:
};

template <typename D, typename T>
class cAttr : public cTaggedData<D,T > {
public:
};

template <typename D, typename T>
class cNode : public cTaggedData<D,T > {
public:

shared_ptr< cAttr<D,T> > RetAttr() { }
template <typename X> X MyAs(T t, X& x) {
#line 100
shared_ptr< cAttr<int,int> > attr1; attr1->As<int>(); // works
#line 200
shared_ptr< cAttr<D,T> > attr2; attr2->As<int>(); // FAILS
#line 300
shared_ptr< cAttr<int,int> > attr3; attr3->As<X>(); // works
#line 400
shared_ptr< cAttr<D,T> > attr4; attr4->As<X>(); // my goal, FAILS
} // As

};
/*
gives:

x.cpp: In member function 'X cNode<D, T>::MyAs(T, X&)':
x.cpp:200: error: expected primary-expression before 'int'
x.cpp:200: error: expected `;' before 'int'
x.cpp:400: error: expected primary-expression before '>' token
x.cpp:400: error: expected primary-expression before ')' token
*/

Using #line is a really good idea, I'll steal that for my own examples!

Anyway,

#line 100
shared_ptr< cAttr<int,int> > attr1; attr1->As<int>(); // works
#line 200
shared_ptr< cAttr<D,T> > attr2; attr2->template As<int>(); // works
#line 300
shared_ptr< cAttr<int,int> > attr3; attr3->As<X>(); // works
#line 400
shared_ptr< cAttr<D,T> > attr4; attr4->template As<X>(); // works

The problem is that you're using the name As which depends on the
template paramters D and T, and the compiler knows nothing about what As
could be (especially, that it would be a template) for any specific D and T.

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

[Rafał Maj Raf256]

Alf P. Steinbach wrote:

Using #line is a really good idea, I'll steal that for my own examples!
Nice :)
#line 100
shared_ptr< cAttr<int,int> > attr1; attr1->As<int>(); // works
#line 200
shared_ptr< cAttr<D,T> > attr2; attr2->template As<int>(); // works
#line 300
shared_ptr< cAttr<int,int> > attr3; attr3->As<X>(); // works
#line 400
shared_ptr< cAttr<D,T> > attr4; attr4->template As<X>(); // works The problem is that you're using the name As which depends on the
template paramters D and T, and the compiler knows nothing about what As
could be (especially, that it would be a template) for any specific D
and T.

#line 200
shared_ptr< cAttr<D,T> > attr2; attr2->template As<int>();

#line 400
shared_ptr< cAttr<D,T> > attr4; attr4->template As<X>();

is the finall solution then :)

I was quite close, tried to add, in the main class { } cNode scope
using cAttr<D,T>::As< >;
g++ warned me:
note: use 'cAttr<D, T>::template As' to indicate that it is a template
only I put it in wrong place

btw, it seem to compile fine on newer MSVC even without the template

--
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Myśl. Głosuj rozsądnie. Nie na tanie hasła. // Rafał Maj Raf256