parse comma delimited text string

[electrixnow]

in MS VC++ Express I need to know how to get from one comma delimited
text string to many strings.

from this:

main_string = "onE,Two,Th ree , fouR,five, six "

to these:

string1 = "one"
string2 = "two"
string3 = "three"
string4 = "four"
string5 = "five"
string6 = "six"

the white space needs to be removed and the case needs to be all upper
or lower.
The result needs to be strings and not pointers or addresses in memory
so I can test:

string test = "three";

if (three == "three")

some getlines will only have two strings some may have up to 10
Please help with examples, you input with exact syntax is greatly
appreciated

I have been struggling with not using pointers but every time I end up
using them.

Thanks in advance

[Ian Collins]

electrixnow wrote:

in MS VC++ Express I need to know how to get from one comma delimited
text string to many strings.

from this:

main_string = "onE,Two,Th ree , fouR,five, six "

to these:

string1 = "one"
string2 = "two"
string3 = "three"
string4 = "four"
string5 = "five"
string6 = "six"
For this, a couple of options are the good old C strtok, or the
std::string find members.
the white space needs to be removed and the case needs to be all upper
or lower.

See toxxxx() and isxxx() functions.

Looks too much like homework to me...

--
Ian Collins.

[electrixnow]

Howework, not even close. I am an 42 year old EE and not really a
programmer. I have an application at work to apply this to. I am trying
to compare two data files and create a third to let my department know
when new releases for drawing are ready. I have tried strtok, and
strtok_s but those functions allways create pointers. That is fine if I
knew how to easly change them back to STRINGS for string comparison. By
the way we have the same last name, that's wierd.

been out of school for too many years!

The only coding I have done was born, corn and c shell in the 80's. C++
is so much more robust, I am trying to learn more. I just purchased a
book C++ without fear. If you have any suggestions for books for VC++
let me know.

what is the best way to compare text strings like this:

if ( "test string" == pointer_returne d_from_strtok )

that will get me going in the right directions.

Thanks!

[Ben Pope]

electrixnow wrote:

Howework, not even close. I am an 42 year old EE and not really a
programmer. I have an application at work to apply this to. I am trying
to compare two data files and create a third to let my department know
when new releases for drawing are ready. I have tried strtok, and
strtok_s but those functions allways create pointers. That is fine if I
knew how to easly change them back to STRINGS for string comparison. By
#include <string>
#include <iostream>

int main() {
// C style string
char mystring[] = "hello world";

// pointer to null terminated token
char* token = mystring + 6;

// create string from token
std::string newString(token );

if (newString == "world") {
std::cout << "Comparison True" << std::endl;
} else {
std::cout << "Comparison Fasle" << std::endl;
}
}
The only coding I have done was born, corn and c shell in the 80's. C++
is so much more robust, I am trying to learn more. I just purchased a
book C++ without fear. If you have any suggestions for books for VC++
let me know.
Accelerated C++, by Koenig and Moo.
what is the best way to compare text strings like this:

if ( "test string" == pointer_returne d_from_strtok )
// create string on the fly
if ("test string" == std::string(poi nter_returned_f rom_strtok))
that will get me going in the right directions.

Off you go then! :)

Ben Pope
--
I'm not just a number. To many, I'm known as a string...

[Alf P. Steinbach]

* electrixnow:

in MS VC++ Express I need to know how to get from one comma delimited
text string to many strings.

from this:

main_string = "onE,Two,Th ree , fouR,five, six "

to these:

string1 = "one"
string2 = "two"
string3 = "three"
string4 = "four"
string5 = "five"
string6 = "six"

the white space needs to be removed and the case needs to be all upper
or lower.
The result needs to be strings and not pointers or addresses in memory
so I can test:

string test = "three";

if (three == "three")

some getlines will only have two strings some may have up to 10
Please help with examples, you input with exact syntax is greatly
appreciated

I have been struggling with not using pointers but every time I end up
using them.

std::string uppercase( std::string const& s )
{
std::string result = s;
for( std::size_t i = 0; i < s.length(); ++i )
{
result[i] = static_cast<cha r>( std::toupper( s[i] ) );
}
return result;
}

typedef std::vector<std ::string> StringVector;

StringVector stringsFrom( std::string s )
{
std::replace( s.begin(), s.end(), ',', ' ' );
std::istringstr eam stream( s );
StringVector result;
for( ;; )
{
std::string word;
if( !( stream >> word ) ) { break; }
result.push_bac k( uppercase( word ) );
}
return result;
}

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

[Sumit Rajan]

"electrixno w" <info...@charte r.net> wrote in message
news:11******** *************@g 47g2000cwa.goog legroups.com...

in MS VC++ Express I need to know how to get from one comma delimited
text string to many strings.

from this:

main_string = "onE,Two,Th ree , fouR,five, six "

You could try something like this:
#include <string>
#include <iostream>
#include <sstream>
#include <algorithm>
#include <cctype>
void trim(std::strin g& str)
{
std::string::si ze_type idx = str.find_first_ not_of(' ');
if (idx != std::string::np os) {
str.erase(0, idx);
}
idx = str.find_last_n ot_of(' ');
if (idx != std::string::np os) {
str.erase(idx+1 , str.size()-1);
}
}

int main()
{
std::string main_string = "onE,Two,Th ree , fouR,five, six ,,
d, , ";

std::istringstr eam iss(main_string );
std::string tok;

while (getline(iss, tok, ',')) {
std::transform( tok.begin(), tok.end(), tok.begin(),
std::tolower);
trim(tok);
std::cout << '!' << tok << "!\n";
}
}

Regards,
Sumit.
--
Sumit Rajan <su****@msdc.hc ltech.com>

[Sumit Rajan]

"Sumit Rajan" <su*********@gm ail.com> wrote in message
news:44******** ****@individual .net...

void trim(std::strin g& str)
{
std::string::si ze_type idx = str.find_first_ not_of(' ');
if (idx != std::string::np os) {
str.erase(0, idx);
}
idx = str.find_last_n ot_of(' ');
if (idx != std::string::np os) {
str.erase(idx+1 , str.size()-1);
}
}

Sorry, this function has a bug. May be simplest to use an std::istringstr eam
as you will see in Alf's post.

Sumit.
--
Sumit Rajan <su****@msdc.hc ltech.com>

[Sumit Rajan]

"Sumit Rajan" <su*********@gm ail.com> wrote in message
news:44******** ****@individual .net...

void trim(std::strin g& str)
{
std::string::si ze_type idx = str.find_first_ not_of(' ');
if (idx != std::string::np os) {
str.erase(0, idx);
}
idx = str.find_last_n ot_of(' ');
if (idx != std::string::np os) {
str.erase(idx+1 , str.size()-1);
}
}

void trim(std::strin g& str)
{
while((!str.emp ty()) && isspace(str[0])) {
str.erase(0, 1);
}
std::string::si ze_type idx = str.find_last_n ot_of(' ');
if (!((idx == std::string::np os)||(idx == str[str.size()-1]))) {
str.erase(idx+1 , str.size()-1);
}
}

Regards,
Sumit.
--
Sumit Rajan <su****@msdc.hc ltech.com>

[Daniel T.]

In article <11************ *********@g47g2 000cwa.googlegr oups.com>,
"electrixno w" <info...@charte r.net> wrote:

in MS VC++ Express I need to know how to get from one comma delimited
text string to many strings.

from this:

main_string = "onE,Two,Th ree , fouR,five, six "

to these:

string1 = "one"
string2 = "two"
string3 = "three"
string4 = "four"
string5 = "five"
string6 = "six"

the white space needs to be removed and the case needs to be all upper
or lower.
The result needs to be strings and not pointers or addresses in memory
so I can test:

string test = "three";

if (three == "three")

some getlines will only have two strings some may have up to 10
Please help with examples, you input with exact syntax is greatly
appreciated

I have been struggling with not using pointers but every time I end up
using them.

Thanks in advance

Assuming there are no spaces other than the ones just before or just
after the commas, the following will work:

template < typename Out >
void fn( string str, Out it )
{
int (*lower)(int) = &tolower;
transform( str.begin(), str.end(), str.begin(), lower );
replace( str.begin(), str.end(), ',', ' ' );
stringstream ss( str );
copy( istream_iterato r<string>( ss ), istream_iterato r<string>(),
it );
}

Call the above with a container that has the space or using a
back_inserter. For example:

vector<string> vec;
fn( main_string, back_inserter( vec ) );

The only magic is replacing the comma's with spaces so that the
stringstream will ignore them.
If there are spaces that must be saved then the above won't work. For
example:

main_string = "John Smith, Mark Allen ,Joe";

If the above needs to be parsed to:
vec[0] = "john smith"
vec[1] = "mark allen"
vec[2] = "joe"

Here we can't just dump the commas...

// returns a string that has had the whitespace at the front
// and back removed without disturbing the whitespace in the middle
string strip( string str )
{
const char* const whitespace = " \t";
str.erase( 0, str.find_first_ not_of( whitespace ) );
string::size_ty pe pos = str.find_last_n ot_of( whitespace );
if ( pos != string::npos )
str.erase( pos + 1 );
return str;
}

template < typename Out >
void foo( string str, Out it )
{
int (*lower)(int) = &tolower;
transform( str.begin(), str.end(), str.begin(), lower );
string::size_ty pe prev = 0;
for ( string::size_ty pe pos = str.find( ',' ); pos != string::npos;
pos = str.find( ',', prev ) )
{
string s = strip( str.substr( prev, pos - prev ) );
it++ = s;
prev = pos + 1;
}
string s = strip( str.substr( prev ) );
it = s;
}

--
Magic depends on tradition and belief. It does not welcome observation,
nor does it profit by experiment. On the other hand, science is based
on experience; it is open to correction by observation and experiment.

[Daniel T.]

In article <po************ *************** ***@news.east.e arthlink.net>,
"Daniel T." <po********@ear thlink.net> wrote:

If there are spaces that must be saved then the above won't work. For
example:

main_string = "John Smith, Mark Allen ,Joe";

If the above needs to be parsed to:
vec[0] = "john smith"
vec[1] = "mark allen"
vec[2] = "joe"

Here we can't just dump the commas...

// returns a string that has had the whitespace at the front
// and back removed without disturbing the whitespace in the middle
string strip( string str )
{
const char* const whitespace = " \t";
str.erase( 0, str.find_first_ not_of( whitespace ) );
string::size_ty pe pos = str.find_last_n ot_of( whitespace );
if ( pos != string::npos )
str.erase( pos + 1 );
return str;
}

template < typename Out >
void foo( string str, Out it )
{
int (*lower)(int) = &tolower;
transform( str.begin(), str.end(), str.begin(), lower );
string::size_ty pe prev = 0;
for ( string::size_ty pe pos = str.find( ',' ); pos != string::npos;
pos = str.find( ',', prev ) )
{
string s = strip( str.substr( prev, pos - prev ) );
it++ = s;
prev = pos + 1;
}
string s = strip( str.substr( prev ) );
it = s;
}

I liked Sumit Rajan's use of getline... Modified my code to use it.

string& strip( string& str )
{
const char* const whitespace = " \t";
str.erase( 0, str.find_first_ not_of( whitespace ) );
string::size_ty pe pos = str.find_last_n ot_of( whitespace );
if ( pos != string::npos )
str.erase( pos + 1 );
return str;
}

template < typename Out >
void fn( string str, Out it )
{
int (*lower)(int) = &tolower;
transform( str.begin(), str.end(), str.begin(), lower );
stringstream ss( str );
string s;
while ( getline( ss, s, ',' ) )
it++ = strip( s );
}
--
Magic depends on tradition and belief. It does not welcome observation,
nor does it profit by experiment. On the other hand, science is based
on experience; it is open to correction by observation and experiment.