Forward declarations to static variables

[fox]

How do I (portably) make a forward reference to a static (I mean
file-scope) variable?

I've been using "extern" for years, for example:

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

.... and gcc 3.4.4 and MSVC 2005 do not even warn that anything's wrong
here.

But gcc 4 gives me an error:

static declaration of 'x' follows non-static declaration

It seems that replacing "extern" with "static" makes it happy.

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?
Please note that I can remove the second "static int x" line and it
still compiles...

Can you explain me what C standards say about this issue and why some
compilers don't issue a warning while gcc 4 gives an error? Is it
because some compilers default to C89 and the other default to C9X ?

Thanks,
Piotr

[Eric Sosman]

fo*@scene.pl wrote On 01/19/06 11:16,:

How do I (portably) make a forward reference to a static (I mean
file-scope) variable?

I've been using "extern" for years, for example:

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

... and gcc 3.4.4 and MSVC 2005 do not even warn that anything's wrong
here.

But gcc 4 gives me an error:

static declaration of 'x' follows non-static declaration

It seems that replacing "extern" with "static" makes it happy.

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?
Please note that I can remove the second "static int x" line and it
still compiles...

Can you explain me what C standards say about this issue and why some
compilers don't issue a warning while gcc 4 gives an error? Is it
because some compilers default to C89 and the other default to C9X ?

Both versions of the Standard say

If, within a translation unit, the same identifier
appears with both internal and external linkage, the
behavior is undefined.

That's 6.2.2/7 in C99 and 3.1.2.2/7 in Original ANSI (which
ISO renumbered to produce C90).

"The behavior is undefined" implies a couple of things.
First, it means that different compilers are allowed to handle
the situation differently; it can even happen that a single
compiler could handle it inconsistently. Second, it means
that the compiler is not required to complain; any diagnostic
you may receive is just a bonus.

The conclusion: Don't Do That. The duelling declarations
are not valid C, in the sense that C assigns no meaning to
them. Hence, when you write them you have no idea what the
effect might be, no idea what you're asking the compiler to do.

--
Er*********@sun .com

[lawrence.jones]

fo*@scene.pl wrote:

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?

It's a declaration and a *tentative* definition. That is, if no actual
definition is found later on in the translation unit, then it will act
as a definition, but it doesn't preclude an actual definition from
appearing later. An actual definition includes an initializer:

static int x; // tentative definition
static int x = 0; // actual definition

-Larry Jones

Any game without push-ups, hits, burns or noogies is a sissy game. -- Calvin

[Rod Pemberton]

<fo*@scene.pl > wrote in message
news:11******** **************@ g44g2000cwa.goo glegroups.com.. .

How do I (portably) make a forward reference to a static (I mean
file-scope) variable?

I've been using "extern" for years, for example:

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

... and gcc 3.4.4 and MSVC 2005 do not even warn that anything's wrong
here.

But gcc 4 gives me an error:

static declaration of 'x' follows non-static declaration

It seems that replacing "extern" with "static" makes it happy.

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?
Please note that I can remove the second "static int x" line and it
still compiles...

Can you explain me what C standards say about this issue and why some
compilers don't issue a warning while gcc 4 gives an error? Is it
because some compilers default to C89 and the other default to C9X ?

Thanks,
Piotr

Why can't you just move the declaration to the top of the file? For
portability, you'll probably need to remove all references to 'static'.
'static' on variables is supposed to mean that it doesn't get exported to
the linker. However, I've seen some compilers that treat 'static' as
'const' and optimize away the code...
Rod Pemberton

[Keith Thompson]

"Rod Pemberton" <do*******@bitb ucket.cmm> writes:
[...]

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

[...] Why can't you just move the declaration to the top of the file? For
portability, you'll probably need to remove all references to 'static'.
'static' on variables is supposed to mean that it doesn't get exported to
the linker. However, I've seen some compilers that treat 'static' as
'const' and optimize away the code...

I can't imagine a compiler treating "static" as "const"; they're
entirely different things. However, if the compiler is able to
determine that the value of x is never modified, it can internally
replace all references to x with a literal value 5 and remove x.
Without the "static", it wouldn't be able to do this, because x could
be referenced from another source file; with "static", the compiler
knows that x exists only within the current source file.

(Even with "static", x could still be modified in another source file
if its address is passed to an external function, or is otherwise made
externally visible. The compiler can still do the optimization if it
can prove that this never happens.)

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.

[Joe Wright]

fo*@scene.pl wrote:

How do I (portably) make a forward reference to a static (I mean
file-scope) variable?

I've been using "extern" for years, for example:

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

... and gcc 3.4.4 and MSVC 2005 do not even warn that anything's wrong
here.

But gcc 4 gives me an error:

static declaration of 'x' follows non-static declaration

It seems that replacing "extern" with "static" makes it happy.

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?
Please note that I can remove the second "static int x" line and it
still compiles...

Can you explain me what C standards say about this issue and why some
compilers don't issue a warning while gcc 4 gives an error? Is it
because some compilers default to C89 and the other default to C9X ?

Thanks,
Piotr

You seem to misunderstand the whole system. Assume a C program written
in two or more translation units (.c files). Variables defined in these
files outside of any function have static duration (storage class) and
external linkage.

For sake of argument, let's say we have a program 'foo' which consists
of three translation units, foo.c, bar.c and baz.c plus a header, foo.h
which is #included in each of the .c files. Further assume there is a
single int object named x, defined in foo.c and accessable by functions
in foo.c, bar.c and baz.c as well. This way..

[foo.h]
extern int x;

[baz.c]
#include "foo.h"
void baz(void) {
x = 3;
}

[bar.c]
#include "foo.h"
void bar(void) {
x = 2;
}

[foo.c]
#include <stdio.h>
#include "foo.h"

int x = 1;

int main(void) {
printf("%d\n", x);
bar();
printf("%d\n", x);
baz();
printf("%d\n", x);
return 0;
}

I assume you know how to compile the three .c files and then create the
executable. That's technically Off Topic here. :-)

Each of foo.c, bar.c and baz.c include foo.h and so declare x an int
somewhere. Only foo.c defines 'int x = 1;' with external linkage. Now
bar and baz can 'see' x as if it were theirs.

There is no case for 'static int x = 1;'.

--
Joe Wright
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---

[fox]

> It's a declaration and a *tentative* definition.

That is clear, thanks.
Is it defined by C89 and supported by all C compilers (I don't care
about pre-ANSI ones) ?

Why can't you just move the declaration to the top of the file?
The real code is like this:

#include <xmms/plugin.h>

extern InputPlugin mod; // <-- I'll change it to static

static void init(void)
{
// ...
}

static int is_our_file(cha r *filename)
{
// ...
}

static void play_file(char *filename)
{
// ...
// (I use mod.output here)
}

static void pause(short paused)
{
mod.output->pause(paused );
}

static void stop(void)
{
// ....
}

static int get_time(void)
{
// ...
}

static InputPlugin mod = {
// ...
init,
NULL,
NULL,
is_our_file,
NULL,
play_file,
stop,
pause,
NULL,
NULL,
get_time,
// these are filled by XMMS at runtime (this includes the "output"
field):
NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL
};

// this is exported from the compiled *.so:
InputPlugin *get_iplugin_in fo(void)
{
return &mod;
}

Of course I could make forward declarations of my static functions,
for example:

static void pause(short paused);

(I'm sure this is a declaration and never a definition)
and then define "mod" at the top, but as you can see there are several
static functions while there's just one "mod".
For portability, you'll probably need to remove all references to 'static'.
Ehm, what?
'static' on variables is supposed to mean that it doesn't get exported to
the linker.
This is exactly what I want.
You seem to misunderstand the whole system.

No.

Thanks,
Piotr

[Antonio Contreras]

Joe Wright wrote:

fo*@scene.pl wrote:

How do I (portably) make a forward reference to a static (I mean
file-scope) variable?

I've been using "extern" for years, for example:

extern int x;
int foo(void)
{
return x++;
}
static int x = 5;

... and gcc 3.4.4 and MSVC 2005 do not even warn that anything's wrong
here.

But gcc 4 gives me an error:

static declaration of 'x' follows non-static declaration

It seems that replacing "extern" with "static" makes it happy.

I always thought that "static" means a definition (and not merely a
declaration) for variables
and if you want to just declare a variable then you use "extern". Now I
cannot understand what "static int x;" actually is: just a declaration?
or declaration and definition?
Please note that I can remove the second "static int x" line and it
still compiles...

Can you explain me what C standards say about this issue and why some
compilers don't issue a warning while gcc 4 gives an error? Is it
because some compilers default to C89 and the other default to C9X ?

Thanks,
Piotr

You seem to misunderstand the whole system.

I didn't get this impression reading his post.

Assume a C program written in two or more translation units (.c files). Variables defined in these
files outside of any function have static duration (storage class) and
external linkage.

For sake of argument, let's say we have a program 'foo' which consists
of three translation units, foo.c, bar.c and baz.c plus a header, foo.h
which is #included in each of the .c files. Further assume there is a
single int object named x, defined in foo.c and accessable by functions
in foo.c, bar.c and baz.c as well. This way..

[foo.h]
extern int x;

[baz.c]
#include "foo.h"
void baz(void) {
x = 3;
}

[bar.c]
#include "foo.h"
void bar(void) {
x = 2;
}

[foo.c]
#include <stdio.h>
#include "foo.h"

int x = 1;

int main(void) {
printf("%d\n", x);
bar();
printf("%d\n", x);
baz();
printf("%d\n", x);
return 0;
}
If you compile this code with a C89 compiler you'll get undefined
behaviour. You did not provide a prototype for bar() and baz() so the
compiler will assume int. Since the actual return type is void, the
behaviour is undefined (IIRC). In C99 the code is not compilable since
a correct prototype in scope is needed.
I assume you know how to compile the three .c files and then create the
executable. That's technically Off Topic here. :-)

Each of foo.c, bar.c and baz.c include foo.h and so declare x an int
somewhere. Only foo.c defines 'int x = 1;' with external linkage. Now
bar and baz can 'see' x as if it were theirs.

There is no case for 'static int x = 1;'.

How would you declare a variable with static duration, file scope and
internal linkage if it was not in this way?

[pete]

fo*@scene.pl wrote:

Of course I could make forward declarations of my static functions,
for example:

static void pause(short paused);
Why wouldn't you?
Too much typing?
(I'm sure this is a declaration and never a definition)
and then define "mod" at the top, but as you can see there are several
static functions while there's just one "mod".

--
pete

[Default User]

pete wrote:

fo*@scene.pl wrote:

Of course I could make forward declarations of my static functions,
for example:

static void pause(short paused);

Why wouldn't you?
Too much typing?

Some people just prefer to define the functions in the order they'll be
used. With statics, there's no need for declarations for other
translation units.

I always find it easier to just put prototypes in, that way if the
design changes I don't end up moving functions around to get them in
the correct order.
Brian