How can I determine the type of some particular typename?
I am writing a template, and it needs special case handling for some
particular types:
template <typename T>
class foo {
public:
foo() {
if (T == int) cerr << "int\n";
}
};
Thanks!
Joseph 14 2207
Joseph Turian wrote: How can I determine the type of some particular typename?
typeid(T)
Cheers
--
Mateusz Łoskot http://mateusz.loskot.net
In article <11************ **********@z14g 2000cwz.googleg roups.com>,
"Joseph Turian" <tu****@gmail.c om> wrote: How can I determine the type of some particular typename?
I am writing a template, and it needs special case handling for some particular types:
template <typename T> class foo { public: foo() { if (T == int) cerr << "int\n"; } };
Here's one possibility:
template <typename T>
class foo {
public:
foo() {
}
};
template <>
class foo<int> {
public:
foo() {
cerr << "int\n";
}
};
Here's another:
template <typename T>
class foo {
public:
foo();
};
template <typename T>
foo<T>::foo()
{
}
template <>
foo<int>::foo()
{
cerr << "int\n";
}
And here's another:
#include <tr1/type_traits>
#include <iostream>
using std::cerr;
template <typename T>
class foo {
public:
foo()
{
foo_imp(std::tr 1::is_same<T, int>());
}
private:
void foo_imp(std::tr 1::true_type)
{ cerr << "int\n"; }
void foo_imp(std::tr 1::false_type)
{ }
};
-Howard
Mateusz Loskot wrote: How can I determine the type of some particular typename? typeid(T)
I'll see if I can figure out the syntax to use 'typeid'
template <typename T> foo<T>::foo() { }
template <> foo<int>::foo() { cerr << "int\n"; }
So foo<T>::foo is used unless it is overloaded (by foo<int>::foo, in
this circumstance).
If I switched the order in which the constructors were declared, would
foo<T> always be used, or would it be identical?
foo_imp(std::tr 1::is_same<T, int>());
This is weird, I'll have to google tr1.
Does it only work for primitive types, or will it also work for
user-defined classes?
Thanks
Joseph This is weird, I'll have to google tr1. Does it only work for primitive types, or will it also work for user-defined classes?
Thanks
Joseph
it is not supported by most compilers and won't be until next
standardization
n
puzzlecracker wrote: it is not supported by most compilers and won't be until next standardization
I think that's a slightly pessimistic characterizatio n. gcc, for one,
handles partial template specialization pretty well. I don't know the
status of other compilers (I use gcc, why not?), but given the rise in
popularity and practice of things such as template metaprogramming , I
think it's safe to say that an appreciable number of people have found
compilers that to the job for them just fine.
Luke
Luke Meyers wrote: puzzlecracker wrote: it is not supported by most compilers and won't be until next standardization
I think that's a slightly pessimistic characterizatio n. gcc, for one, handles partial template specialization pretty well. I don't know the status of other compilers (I use gcc, why not?), but given the rise in popularity and practice of things such as template metaprogramming , I think it's safe to say that an appreciable number of people have found compilers that to the job for them just fine.
Luke
I was refering to foo_imp(std::tr 1::is_same<T, int>());....
Joseph Turian wrote: How can I determine the type of some particular typename?
I am writing a template, and it needs special case handling for some particular types:
template <typename T> class foo { public: foo() { if (T == int) cerr << "int\n"; } };
Thanks!
This is covered in the FAQ.
> I was refering to foo_imp(std::tr 1::is_same<T, int>());....
Why wait for the standardization ?
Things like tr1::is_same are extremely easy to write so just take a
minute to write some of them.
Or just use the boost library.
Ben
Joseph Turian wrote: How can I determine the type of some particular typename?
I am writing a template, and it needs special case handling for some particular types:
template <typename T> class foo { public: foo() { if (T == int) cerr << "int\n"; } };
What about different types of int ?
const int
unsigned int
volatile int
int &
or any combination of those ? This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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