Hello!
Is this too crazy or not?
Copy constructor: why can't I copy objects as if they were structs?
I have a set of simple objects (no string properties, just integers,
doubles) and I have to copy the same object millions of times.
So instead of writing in the copy constructor
property1=Sourc eObject.propert y1 can't I use memory copy functions to
do this faster?
Is this too stupid?
By the way, I'm a C++ newbie! But don't go easy on me just because...
;)
Bye! Thanks for your help and attention.
Jorge C. rd******@yahoo. com 24 3606
rdc02271 wrote: Is this too crazy or not? Copy constructor: why can't I copy objects as if they were structs?
What does it mean? I honestly am baffled by questions like this. "Why
can't I use a pencil to write"? How do you answer such a question?
I have a set of simple objects (no string properties, just integers, doubles) and I have to copy the same object millions of times.
OK.
So instead of writing in the copy constructor property1=Sourc eObject.propert y1 can't I use memory copy functions to do this faster?
Sure. If your class is a POD class, you can use memcpy. In general,
if you don't write your copy constructor, the compiler "provides" one,
and it invokes copy constructing semantics for all members.
Is this too stupid?
I don't know how to answer this either.
By the way, I'm a C++ newbie! But don't go easy on me just because... ;)
Have you read the FAQ yet?
V
rdc02271 wrote: Hello! Is this too crazy or not? Copy constructor: why can't I copy objects as if they were structs? I have a set of simple objects (no string properties, just integers, doubles) and I have to copy the same object millions of times. So instead of writing in the copy constructor property1=Sourc eObject.propert y1 can't I use memory copy functions to do this faster? Is this too stupid? By the way, I'm a C++ newbie! But don't go easy on me just because... ;)
If you donot declare a copy constructor explicitly, the compiler will
provide a default copy-constructor which will do a bitwise copy of the
data members of basic types. So if your class contains only integers
and doubles, you may very well skip writing the CC completely - the
compiler generated constructor will do the necessary work for you.
HTH.
Hi! Sorry and where is the FAQ?
Thanks!
Jorge C.
Neelesh Bodas wrote: rdc02271 wrote:
Hello! Is this too crazy or not? Copy constructor: why can't I copy objects as if they were structs? I have a set of simple objects (no string properties, just integers, doubles) and I have to copy the same object millions of times. So instead of writing in the copy constructor property1=Sou rceObject.prope rty1 can't I use memory copy functions to do this faster? Is this too stupid? By the way, I'm a C++ newbie! But don't go easy on me just because... ;)
If you donot declare a copy constructor explicitly, the compiler will provide a default copy-constructor which will do a bitwise copy
No. The default copy-constructor does _memberwise_ copy. IOW, it will
invoke copy semantics for every member. If a member has user-defined
copy constructor, that copy constructor will be used. If some member
does not have a user-defined copy-constructor, it might still adhere to
some copy-construction rules. If members cannot be copy-constructed,
the program is ill-formed.
of the data members of basic types. So if your class contains only integers and doubles, you may very well skip writing the CC completely - the compiler generated constructor will do the necessary work for you.
That is true.
V
Victor Bazarov wrote: Neelesh Bodas wrote: If you donot declare a copy constructor explicitly, the compiler will provide a default copy-constructor which will do a bitwise copy
No. The default copy-constructor does _memberwise_ copy. IOW, it will invoke copy semantics for every member. If a member has user-defined copy constructor, that copy constructor will be used. If some member does not have a user-defined copy-constructor, it might still adhere to some copy-construction rules. If members cannot be copy-constructed, the program is ill-formed.
Thats true. May be I wrote it in a confusing way. I said that - If you donot declare a copy constructor explicitly, the compiler will provide a default copy-constructor which will do a bitwise copy *of the data members of basic types*
I should have also added a comment about the non-POD members.
Also, for basic data types, isn't the memberwise copy same as the
bitwise copy? Or not necessarily?
rdc02271 wrote: Hi! Sorry and where is the FAQ?
The location of the FAQ is spelled out in the "Welcome" message
published here every week for all newcomers to read. It is also
noted many times in the archives available at groups.google.c om
V
Victor Bazarov wrote: If members cannot be copy-constructed, the program is ill-formed.
Hm, what about members of class defined as intentionally not copyable?
Cheers
--
Mateusz Łoskot http://mateusz.loskot.net
Neelesh Bodas wrote: [..] Also, for basic data types, isn't the memberwise copy same as the bitwise copy? Or not necessarily?
A C++ practitioner should only use the term "bitwise" when talking about
the binary operators &, |, and ^, and the unary ~.
V This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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