Suppose I have a class of objects which take an integer parameter.
I can easily create an object with the required parameter as follows:
name_of_class variable_name(i nteger_value);
For clarity, suppose I have a bank-account class and each object falls
into one of 5 distinct categories.
Then I might have code like:
bank_account object_1(5);
bank account object_2(3);
But if I have lots of objects of the class, I don't know what the
correct syntax is for doing such assignments (creating the objects) in
a loop.
Would the following work? (By using a giant leap of imagination, let
my_integer_valu ed_function denote an integer_valued function.)
object_array = new bank_account[n];
for (i=0; i<n; i++)
bank_account object_array[i] (my_integer_val ued function of i);
Or perhaps it should be
object_array = new bank_account[n];
for (i=0; i<n; i++)
object_array[i] (my_integer_val ued function of i);
Thanks for all your help and advice. I have received a lot of help
from this group.
Paul Epstein 2 1263 pa**********@at t.net wrote: Suppose I have a class of objects which take an integer parameter.
I can easily create an object with the required parameter as follows:
name_of_class variable_name(i nteger_value);
For clarity, suppose I have a bank-account class and each object falls into one of 5 distinct categories.
Then I might have code like:
bank_account object_1(5);
bank account object_2(3);
But if I have lots of objects of the class, I don't know what the correct syntax is for doing such assignments (creating the objects) in a loop.
Would the following work? (By using a giant leap of imagination, let my_integer_valu ed_function denote an integer_valued function.)
object_array = new bank_account[n];
for (i=0; i<n; i++)
bank_account object_array[i] (my_integer_val ued function of i);
No Or perhaps it should be
object_array = new bank_account[n];
for (i=0; i<n; i++)
object_array[i] (my_integer_val ued function of i);
No.
When you use operator new[], all objects get constructed using the
no-arg constructor.
If you want to construct all objects with a different initial value,
use array of pointers, and allocate in a loop.
const int n = 100;
bank_account* object_array[n];
for(int i=0; i < n; i++)
{
object_array[i] = new bank_account(i) ; // initailze with i.
}
Also, prefer std::vector over arrays.
Hope this helps.
Neelesh Bodas wrote: pa**********@at t.net wrote: Suppose I have a class of objects which take an integer parameter.
I can easily create an object with the required parameter as follows:
name_of_class variable_name(i nteger_value);
For clarity, suppose I have a bank-account class and each object falls into one of 5 distinct categories.
Then I might have code like:
bank_account object_1(5);
bank account object_2(3);
But if I have lots of objects of the class, I don't know what the correct syntax is for doing such assignments (creating the objects) in a loop.
Would the following work? (By using a giant leap of imagination, let my_integer_valu ed_function denote an integer_valued function.)
object_array = new bank_account[n];
for (i=0; i<n; i++)
bank_account object_array[i] (my_integer_val ued function of i);
No
Or perhaps it should be
object_array = new bank_account[n];
for (i=0; i<n; i++)
object_array[i] (my_integer_val ued function of i);
No. When you use operator new[], all objects get constructed using the no-arg constructor. If you want to construct all objects with a different initial value, use array of pointers, and allocate in a loop.
const int n = 100; bank_account* object_array[n];
for(int i=0; i < n; i++) { object_array[i] = new bank_account(i) ; // initailze with i. }
Also, prefer std::vector over arrays.
Thanks.
I find const int n = 100 to be a bit inflexible.
I can't get this to work in the case of variable n. Since arrays need
to have constant integer bounds, it seems I need a pointer to a
pointer.
I somehow can't get this to work.
Thanks for your continued help.
Paul Epstein This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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