64 bit integer

[Jay]

Hello, I am sure this has a quick and easy solution but I can't find
it.

I need to store 19 '9's in an integer which means i need an unsigned 64
bit
integer.
in Visual Studio the code would be:

__int64 test = 999999999999999 9999;

I am using g++ version 3.3.5(suse 9.3) and have tried both:

unsigned long long test = 999999999999999 999;
and:
uint64_t test = 999999999999999 9999;

both have this compile error using the command "g++ test.cpp"
test.cpp:5: error: integer constant is too large for "long" type

Am I forgeting to include something or not passing an option to g++, or
is
there another way to do 64 bit integer storage?

Thank you for your help

[Michiel.Salters]

Jay wrote:

Hello, I am sure this has a quick and easy solution but I can't find
it.

I need to store 19 '9's in an integer which means i need an unsigned 64
bit integer. in Visual Studio the code would be:

__int64 test = 999999999999999 9999;
The double underscore is a giveaway that this isn't C++, but a
Microsoft
extension.
I am using g++ version 3.3.5(suse 9.3) and have tried both:

unsigned long long test = 999999999999999 999;
and:
uint64_t test = 999999999999999 9999;

both have this compile error using the command "g++ test.cpp"
test.cpp:5: error: integer constant is too large for "long" type

Reasonable, by the standard rules it may indeed reject the code. If
you need an GCC extension to C++, you should ask in a GCC group.

HTH,
Michiel Salters

[mlimber]

Jay wrote:

Hello, I am sure this has a quick and easy solution but I can't find
it.

I need to store 19 '9's in an integer which means i need an unsigned 64
bit
integer.

[snip]

Or you could use a number class with arbitrary precision. The sizes of
the various built-in integral types are platform-dependent, so you'll
want to check with your OS/compiler documentation.

Cheers! --M

[Jay]

So is there no way to do this in C++ without using an extension?
If this is the wrong group for this question, do you happen to know
which group would be more appropriate?

Thank you

[Jay]

I know that the sizes of int, long etc are platform-dependent and I
know that they are not big enough on my platform, I am looking for a
datatype that guarentees me 64bits on any platform. I don't really want
to have to include non-standard libraries, but is there a number class
with arbitrary precision that you would suggest?

[Bronek Kozicki]

Jay <Co******@gmail .com> wrote:

uint64_t test = 999999999999999 9999;

both have this compile error using the command "g++ test.cpp"
test.cpp:5: error: integer constant is too large for "long" type

try:

uint64_t test = 999999999999999 9999LL;
B.

[mlimber]

Jay wrote:

I know that the sizes of int, long etc are platform-dependent and I
know that they are not big enough on my platform, I am looking for a
datatype that guarentees me 64bits on any platform.
No such thing with built-in types. C++ compilers can be standard
compliant on 8-bit machines, which implies that no built-in type
*necessarily* supports 64 bits.
I don't really want
to have to include non-standard libraries, but is there a number class
with arbitrary precision that you would suggest?

Check out:

http://www.oonumerics.org/oon/

Cheers! --M

[mlimber]

mlimber wrote:

Jay wrote:

I don't really want
to have to include non-standard libraries, but is there a number class
with arbitrary precision that you would suggest?

Check out:

http://www.oonumerics.org/oon/

See also

http://www.swox.com/gmp/

Cheers! --M

[James.Mahler]

unsigned long long a = 999999999999999 9999LLU; is the right way to do
it. If you don't say it's unsigned you get warnings because it's too
large.

That works fine for 64 bit numbers on 32 bit machine.

[Jay]

Thanks, I just forgot the LLU on the end of a non-int constant