Hello guys, i have this part of code and i want to compute the time of
processes A, B and C :
/* process A */
pid_t pid1, pid2, pid;
struct rusage ru1, ru2;
pid1 = fork();
if (pid != 0) {/* parent process */
pid2 = fork();
if (pid2 != 0) {/* parent process */
pid = waitpid(-1, &status, 0);
getrusage(RUSAG E_CHILDREN, &ru1);
waitpid(-1, &status, 0);
getrusage(_CHIL DREN, &ru2);
if (pid == pid1) {
printf("B took time...\n", ru1.ru_utime.tv _sec);
printf("C took time...\n", ru2.ru_utime.tv _sec);
} else {
printf("C took time...\n", ru1.ru_utime.tv _sec);
printf("B took time...\n", ru2.ru_utime.tv _sec);
}
getrusage(RUSAG E_SELF, &ru);
printf("A took overall time...\n", ru.ru_utime.tv_ sec);
} else {
/* process C */
execp(...);
}
} else {
/* process B */
execp(...);
}
The question is : Do i compute the time of each process successfully?
I get shorter time for proccess A than for its children... Isn't it
peculiar?Why?
I think that the time for proccess B is right, but i wonder if the next
call of getrusage adds c's time over b's. Do anyone know sth about
that?
Thanks a lot... 3 1971 ba*****@gmail.c om wrote: Hello guys, i have this part of code and i want to compute the time of processes A, B and C :
/* process A */ pid_t pid1, pid2, pid; struct rusage ru1, ru2;
pid1 = fork();
<snip!> The question is : Do i compute the time of each process successfully? I get shorter time for proccess A than for its children... Isn't it peculiar?Why? I think that the time for proccess B is right, but i wonder if the next call of getrusage adds c's time over b's. Do anyone know sth about that?
fork(), thread, child processes etc. are not topical to comp.lang.c,
thus you cannot rely on getting the best/good advice on that here.
comp.unix.progr ammer or similar may be a better place to ask.
Cheers
Michael
--
E-Mail: Mine is an /at/ gmx /dot/ de address.
On 27 Nov 2005 10:08:50 -0800, ba*****@gmail.c om wrote in comp.lang.c: Hello guys, i have this part of code and i want to compute the time of processes A, B and C :
The problem here is that your question is not about the C language,
but about non-standard, system-specific extensions. /* process A */ pid_t pid1, pid2, pid; struct rusage ru1, ru2;
pid1 = fork(); if (pid != 0) {/* parent process */ pid2 = fork(); if (pid2 != 0) {/* parent process */ pid = waitpid(-1, &status, 0); getrusage(RUSAG E_CHILDREN, &ru1); waitpid(-1, &status, 0); getrusage(_CHIL DREN, &ru2);
if (pid == pid1) { printf("B took time...\n", ru1.ru_utime.tv _sec); printf("C took time...\n", ru2.ru_utime.tv _sec);
} else { printf("C took time...\n", ru1.ru_utime.tv _sec); printf("B took time...\n", ru2.ru_utime.tv _sec); } getrusage(RUSAG E_SELF, &ru); printf("A took overall time...\n", ru.ru_utime.tv_ sec);
} else { /* process C */ execp(...); }
} else { /* process B */ execp(...); }
The question is : Do i compute the time of each process successfully? I get shorter time for proccess A than for its children... Isn't it peculiar?Why? I think that the time for proccess B is right, but i wonder if the next call of getrusage adds c's time over b's. Do anyone know sth about that? Thanks a lot...
None of fork(), waitpid(), getrusage(), or execp() are standard C
library functions, although I imagine they are all POSIX.
You need to ask in a platform specific group. Since you posted via
Google, the headers do not reveal your platform, so I can only suggest
either news:comp.os.li nux.development .apps or
news:comp.unix. programmer.
--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.l earn.c-c++ http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html
Ok, then , sorry for that and thanks for the advice. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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