Outputting the size of an array

[tigrfire]

I need the following code to return a string of character stored in
array and also return the size of the array. I want to do it without
using pointers and so far have the character storing working fine, it's
just that I can't really think of a way to return the number of
characters in the array. Anyone help me out?

int inputPhrase()
{
char msg[characters], ch;
int i = 0;
int n = 5;

while ((ch = getchar()) != '\n')
{
msg[i++] = ch;
}

msg[i] = '\0'; /* prevents garbage from being place at end of array
output */

i = 0;

while (msg[i] != '\0')
{
printf("%c", msg[i++]);
}

return n;
}

int main()
{
inputPhrase();

int size = inputPhrase();
printf("%d\n", size);

return 0;
}

[Kenny McCormack]

In article <j8************ *************** *****@4ax.com>,
Mark McIntyre <ma**********@s pamcop.net> wrote:

On Wed, 16 Nov 2005 21:15:55 GMT, in comp.lang.c , Keith Thompson
<ks***@mib.org > wrote:

ga*****@yin.i nteraccess.com (Kenny McCormack) writes:

(the usual nonsense)

You've told us why several times before. We've explained why you're
wrong (briefly, many of them *do* get it). Save your own breath.

I don't see why you don't killfile the idiot. He rarely says anything
worth listening to, and is erroneous insufficiently often to endure
just so you can correct him.

I see what you're saying, but, hey, call me a masochist, but I find Keith
amusing.