About (char)13 & (char)10

[Betaver]

What char represent "a new line"?13 or 10, or both?
I got a lot of problem when read a char. Eg.
========
1 2
a b

========
If I write:
int n1,n2;
char c1,c2;
scanf("%d%d",&n 1,&n2);
scanf("%c%c",&c 1,&c2);

I got:
c1=10('\n')
c2=97('a')

So I must wrote:
int n1,n2;
char c1,c2;
scanf("%d%d",&n 1,&n2);
scanf("%c",c1);
scanf("%c%c",&c 1,&c2);
But I don't know if the char of new line in linux is also 10, or 10&13.
If I need to read some more complex vars & chars, how can I solve this
problem?

[Betaver]

A text file:
========
5
AAAAA

========
is 10bytes.(Maybe every newline is 2 bytes)
But scanf("%c") can only read 8 chars.
Can it read any newline as a '\n' no matter it is 10 or 10&13?
My header file is Gcc 3.4.2 provided.

[pete]

Betaver wrote:

A text file:
========
5
AAAAA

========
is 10bytes.(Maybe every newline is 2 bytes)
Maybe {'5', '\n', 'A', 'A', 'A', 'A', 'A','\n', '\n' , '\n'}
But scanf("%c") can only read 8 chars.
Can it read any newline as a '\n' no matter it is 10 or 10&13?
My header file is Gcc 3.4.2 provided.

/* BEGIN type_.c */
/*
** This is a demonstration of a way to use fscanf on text files.
** It is not supposed to be an efficient implementation
** of the "type" command.
*/

#include <stdio.h>

#define ARGV_0 type_
#define LINE_LEN 250
#define str(s) # s
#define xstr(s) str(s)

int main(int argc, char *argv[])
{
int rc;
FILE *fd;
char line[LINE_LEN + 1];

if (argc > 1) {
while (*++argv != NULL) {
fd = fopen(*argv, "r");
if (fd != NULL) {
do {
rc = fscanf(fd,
"%" xstr(LINE_LEN) "[^\n]%*[^\n]", line);
if (!feof(fd)) {
getc(fd);
}
if (rc == 0) {
*line = '\0';
}
if (rc != EOF) {
puts(line);
}
} while (rc == 1 || rc == 0);
fclose(fd);
} else {
fprintf(stderr,
"\nfopen() problem with \"%s\"\n", *argv);
break;
}
}
} else {
puts(
"Usage:\n>" xstr(ARGV_0)
" <FILE_0.txt> <FILE_1.txt> <FILE_2.txt> ...\n"
);
}
return 0;
}

/* END type_.c */
--
pete

[Emmanuel Delahaye]

Betaver a écrit :

What char represent "a new line"?13 or 10, or both?
In a text file context, the new line
character (actually 'end of line) is '\n'.
I got a lot of problem when read a char. Eg. ======== 1 2 a b

Use fgets() and your problems are gone.

--
A+

Emmanuel Delahaye

[Betaver]

If I write a text file:
========
5
AAAAA

========
Windows says it's 10bytes. But scanf("%c") can only read 8 chars.
I think scanf read a 10&13 as a 10('\n'), but can scanf read all 10 or
10&13 as a 10?

[Betaver]

To Emmanuel:
But why my 8bytes file windows shows 10bytes?

[Betaver]

To pete:
I can sure no such newline at end of file.
I think I may use Hex Editor open it and find the 2 more chars.

[pete]

Betaver wrote:

To pete:
I can sure no such newline at end of file.
I think I may use Hex Editor open it and find the 2 more chars.

Your hex editor may see text files differently
from the way that a C program sees them.

--
pete

[Betaver]

Er, too hard to me. Too special C and system works.
So can I only use one scanf("%c") for each newline and it works well
both in Linux & Windows?

[Martin Ambuhl]

Betaver wrote:

What char represent "a new line"?13 or 10, or both?

In C, '\n' represents a newline.
Whether '\n' is represented by 13 (CR in ASCII) or 10 (LF in ASCII) or
both or by some other value or values depends on your OS and platform.
In any case, it should generally be irrelevant.