Unaligned pointers question

[Steven Jones]

Up until now, I was under the impression that when one talks about data
alignment, what one means is at what address some data is stored. For
instance, if we write

unsigned int x ;

assuming that sizeof(unsigned int) is 4 then &x will evaluate to some
address the value of which will be a multiple of 4. The reasoning is
analogous for the other fundamental data types supported by a given
compiler.

However, I recently came across the following:

unsigned short * p = (unsigned short *) str ;

where str has been defined as unsigned char * elsewhere, and points to
some data. str can point to an address with an arbitrary value, as far as
divisibility is concerned.

unsigned short x ;
unsigned short * y = &x ;

*y = p[0] ;

In my naivete, I thought that this last line would result in an unaligned
access whenever the address p is not a multiple of 2 (assuming that
sizeof(unsigned short) is 2) but my little test code shows that sometimes
it does, sometimes it doesn't.

Can anybody enlighten me here? What is the foolproof criterion to
determine is some data is correctly aligned?

[Nils Weller]

On 2005-10-22, Steven Jones <sj****@sjones. org> wrote:

[...]
However, I recently came across the following:

unsigned short * p = (unsigned short *) str ;

where str has been defined as unsigned char * elsewhere, and points to
some data. str can point to an address with an arbitrary value, as far as
divisibility is concerned.

unsigned short x ;
unsigned short * y = &x ;

*y = p[0] ;

In my naivete, I thought that this last line would result in an unaligned
access whenever the address p is not a multiple of 2 (assuming that
sizeof(unsigned short) is 2) but my little test code shows that sometimes
it does, sometimes it doesn't.

I have to ask HOW you determined whether that line resulted in an
unaligned access or not. Your assertion that the divisibility of an
address indicates the alignment is correct in practice (though the C
standards do not guarantee that such a relationship between pointers and
integers exists.)

However, since unaligned access invokes undefined behavior in C, the
implementation is free to behave in any way it chooses upon encountering
such a construct, and that may be may be what you're seeing: Some
processors require correct alignment for all types and yield a bus error
for unaligned access, others do not (in particular, the x86 architecture
can perform misaligned data access in exchange for a performance
penalty), and still others may perform the access but silently yield
unwanted results. Some operating systems work around such processor
limitations by catching alignment faults and building your desired
results from combining two aligned reads/writes, and some compilers can
do the same thing in advance, such that the processor never gets to see
the bad access.

The fact that the access worked for you does not necessarily mean that
the address is really correctly aligned.

[Nils Weller]

I hate following up to myself, but somebody's gotta do it ...

On 2005-10-22, Nils Weller <[e-mail] > wrote:

results from combining two aligned reads/writes, and some compilers can
do the same thing in advance, such that the processor never gets to see
the bad access.

Actually compilers that try to prevent unaligned reads/writes in advance
tend to do so by reading/writing the data byte-wise rather than in units
of the particular type.

--
Nils R. Weller, Bremen (Germany)
My real email address is ``nils<at>gnuli nux<dot>nl''
.... but I'm not speaking for the Software Libre Foundation!

[Steven Jones]

On Sat, 22 Oct 2005 21:31:44 +0000, Nils Weller wrote:

On 2005-10-22, Steven Jones <sj****@sjones. org> wrote:

[...]
However, I recently came across the following:

unsigned short * p = (unsigned short *) str ;

where str has been defined as unsigned char * elsewhere, and points to
some data. str can point to an address with an arbitrary value, as far
as divisibility is concerned.

unsigned short x ;
unsigned short * y = &x ;

*y = p[0] ;

In my naivete, I thought that this last line would result in an
unaligned access whenever the address p is not a multiple of 2 (assuming
that sizeof(unsigned short) is 2) but my little test code shows that
sometimes it does, sometimes it doesn't.
I have to ask HOW you determined whether that line resulted in an
unaligned access or not.

Well, when I run run the code a big fat warning is printed out that says
so. This is under Linux x86.
Your assertion that the divisibility of an address indicates the
alignment is correct in practice (though the C standards do not
guarantee that such a relationship between pointers and integers
exists.) However, since unaligned access invokes undefined behavior in C, the
implementation is free to behave in any way it chooses upon encountering
such a construct, and that may be may be what you're seeing: Some
processors require correct alignment for all types and yield a bus error
for unaligned access, others do not (in particular, the x86 architecture
can perform misaligned data access in exchange for a performance
penalty), and still others may perform the access but silently yield
unwanted results. Some operating systems work around such processor
limitations by catching alignment faults and building your desired
results from combining two aligned reads/writes, and some compilers can
do the same thing in advance, such that the processor never gets to see
the bad access.

The fact that the access worked for you does not necessarily mean that
the address is really correctly aligned.

Well, this is a nice explanation, but it does not really address the
issue I raised: Is the divisibility criterion I mentioned the right one
for determining data alignment, or does this vary so dramatically from
processor to processor that such criterion is not generally valid?

I am aware that this is not directly related to the C standard, but it is
a question that surely arises whenever one writes C code on any platform,
right?

[Nils Weller]

On 2005-10-23, Steven Jones <sj****@sjones. org> wrote:

On Sat, 22 Oct 2005 21:31:44 +0000, Nils Weller wrote:

On 2005-10-22, Steven Jones <sj****@sjones. org> wrote:

[...]

I have to ask HOW you determined whether that line resulted in an
unaligned access or not.

Well, when I run run the code a big fat warning is printed out that says
so. This is under Linux x86.

Interesting, so you're running a Linux with x86 alignment exceptions
turned on. The x86 architecture, as I mentioned in my previous message,
can correctly handle unaligned memory access. However, it is also
capable of causing an exception upon encountering such an access, just
like those architectures that always respond with bus errors to
unaligned access. There's a bit in an x86 control register that can be
set to select the desired behavior. Most x86 systems do not make use of
this feature, so misaligned memory access will work on them without any
indication of a problem except for the increased access time.

Your assertion that the divisibility of an address indicates the
alignment is correct in practice (though the C standards do not
guarantee that such a relationship between pointers and integers
exists.)

[...]

Well, this is a nice explanation, but it does not really address the
issue I raised: Is the divisibility criterion I mentioned the right one
for determining data alignment, or does this vary so dramatically from
processor to processor that such criterion is not generally valid?

The very first paragraph of the explanation addresses the issue you
raised: Yes, the divisibility criterion you mentioned is the right one
for determining data alignment, in the real world (again, the C standard
does not say this.)

--
Nils R. Weller, Bremen (Germany)
My real email address is ``nils<at>gnuli nux<dot>nl''
.... but I'm not speaking for the Software Libre Foundation!

[Steven Jones]

On Sun, 23 Oct 2005 02:04:24 +0000, Nils Weller wrote:

The very first paragraph of the explanation addresses the issue you
raised: Yes, the divisibility criterion you mentioned is the right one for
determining data alignment, in the real world (again, the C standard does
not say this.)

All right. I guess that the way to understand what I am observing is,
for some cases in which unaligned data access is taking place, the
platform that I am using is not reacting in any immediately visible way,
whereas in some others (for whatever reason) it does.

[Malcolm]

"Steven Jones" <sj****@sjones. org> wrote

All right. I guess that the way to understand what I am observing is,
for some cases in which unaligned data access is taking place, the
platform that I am using is not reacting in any immediately visible way,
whereas in some others (for whatever reason) it does.

Not all processors require data to be aligned.
Others slow down when they hit unaligned data, but give correct output.
Others require strict alignment.

Therefore casting a char * to an unsigned short is asking for trouble.
Normally there should be no reason to do this, but sometimes you do need to
play games with memory, in which case flag it as a portability hazard.

[Jack Klein]

On Sun, 23 Oct 2005 01:22:33 GMT, Steven Jones <sj****@sjones. org>
wrote in comp.lang.c:

On Sat, 22 Oct 2005 21:31:44 +0000, Nils Weller wrote:

On 2005-10-22, Steven Jones <sj****@sjones. org> wrote:

[...]
However, I recently came across the following:

unsigned short * p = (unsigned short *) str ;

where str has been defined as unsigned char * elsewhere, and points to
some data. str can point to an address with an arbitrary value, as far
as divisibility is concerned.

unsigned short x ;
unsigned short * y = &x ;

*y = p[0] ;

In my naivete, I thought that this last line would result in an
unaligned access whenever the address p is not a multiple of 2 (assuming
that sizeof(unsigned short) is 2) but my little test code shows that
sometimes it does, sometimes it doesn't.

I have to ask HOW you determined whether that line resulted in an
unaligned access or not.

Well, when I run run the code a big fat warning is printed out that says
so. This is under Linux x86.

Your assertion that the divisibility of an address indicates the
alignment is correct in practice (though the C standards do not
guarantee that such a relationship between pointers and integers
exists.)

However, since unaligned access invokes undefined behavior in C, the
implementation is free to behave in any way it chooses upon encountering
such a construct, and that may be may be what you're seeing: Some
processors require correct alignment for all types and yield a bus error
for unaligned access, others do not (in particular, the x86 architecture
can perform misaligned data access in exchange for a performance
penalty), and still others may perform the access but silently yield
unwanted results. Some operating systems work around such processor
limitations by catching alignment faults and building your desired
results from combining two aligned reads/writes, and some compilers can
do the same thing in advance, such that the processor never gets to see
the bad access.

The fact that the access worked for you does not necessarily mean that
the address is really correctly aligned.

Well, this is a nice explanation, but it does not really address the
issue I raised: Is the divisibility criterion I mentioned the right one
for determining data alignment, or does this vary so dramatically from
processor to processor that such criterion is not generally valid?

I am aware that this is not directly related to the C standard, but it is
a question that surely arises whenever one writes C code on any platform,
right?

No, I would say that you are wrong. There is never any need to write
C code that accesses an lvalue via a pointer with incorrect alignment.

Most such code is written by those who decide, generally without
evidence or testing, that doing things properly is "too slow".

Almost all such decisions are based on incorrect assumptions
(premature optimization and all that) that would turn out to be just
plain wrong if actually measured or tested.

--
Jack Klein
Home: http://JK-Technology.Com
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