Two-Dimensional Char Array

[miketigerwoods]

I'm having problems where I need to parse a command line, and place
each token from strtok() into an array. I've read here:
http://www.phim.unibe.ch/comp_doc/c_...PT/arrays.html (at
bottom) that you can access a char[][] by doing char[i] and getting the
string. However when I try the code below I get

error: invalid use of array with unspecified bounds

whenever argv is accessed. It is declared in main() as:

char argv[ARGV_LENGTH][ARGV_LENGTH]; /* ARGV_LENGTH is a const int of
64 */

This is pretty much my first time with C, I'm usually using Java and a
little C++. Any help is appreciated.

Thanks,
Mike
void parse_cmdline(c har cmdline [], char argv [][])
{
char * command;
int i = 1;
command = strtok(cmdline, DELIMITERS);
argv[0] = malloc(sizeof(c har)*(strlen(co mmand)+1));
strcpy(argv[0],command);
while (command != NULL) {
printf("%s\n", command);
command = strtok(NULL, DELIMITERS);
argv[i] = malloc(sizeof(c har)*(strlen(co mmand)+1));
strcpy(argv[i],command);
i++;
}
}

[Vimal Aravindashan]

mi************@ gmail.com wrote:

I'm having problems where I need to parse a command line, and place
each token from strtok() into an array. I've read here:
http://www.phim.unibe.ch/comp_doc/c_...PT/arrays.html (at
bottom) that you can access a char[][] by doing char[i] and getting the
string. However when I try the code below I get You need to read something better. I suggest K&R2

error: invalid use of array with unspecified bounds

whenever argv is accessed. It is declared in main() as:

char argv[ARGV_LENGTH][ARGV_LENGTH]; /* ARGV_LENGTH is a const int of
64 */
Please post the code where you call your parse_cmdline() function.

void parse_cmdline(c har cmdline [], char argv [][]) When passing unsized arrays, you can optionally leave out only the
leftmost dimension. The remaining must be specified.
{
char * command;
int i = 1;
command = strtok(cmdline, DELIMITERS);
argv[0] = malloc(sizeof(c har)*(strlen(co mmand)+1)); You passed a two dimensional array to this function! Maybe what you
really wanted to pass was an array of pointers.
strcpy(argv[0],command);
while (command != NULL) {
printf("%s\n", command);
command = strtok(NULL, DELIMITERS);
argv[i] = malloc(sizeof(c har)*(strlen(co mmand)+1));
strcpy(argv[i],command); You are wasting a call when command equals NULL in the end. Use a
do...while instead.
i++;
}
}

Hope this helps,
Vimal.
--
"If you would be a real seeker after truth, it is necessary that at
least once in your life you doubt, as far as possible, all things."
-- Rene Descartes

[miketigerwoods]

The spec for this assignment shows a two-dimensional array, no mention
of pointers anywhere. As for the website vs. the mentioned text, I have
a C++ text that I use, I really just never use C so it's just not worth
it in my opinion. Those do...while's always slip my mind, thanks for
that.

Thanks,
Mike

int main(void)
{
char cmdline[MAX_CMD_LENGTH];
char argv[ARGV_LENGTH][ARGV_LENGTH];
while (TRUE) {
display_prompt( );
get_user_input( cmdline);
parse_cmdline(c mdline, argv);
if (!try_builtins( argv))
fork_and_execut e(argv);
}
exit(0); /* should never reach here */
}

[Vimal Aravindashan]

mi************@ gmail.com wrote:

The spec for this assignment shows a two-dimensional array, no mention
of pointers anywhere. As for the website vs. the mentioned text, I have
a C++ text that I use, I really just never use C so it's just not worth
it in my opinion. Those do...while's always slip my mind, thanks for
that.

Irrespective of whether you use C or C++, you cannot re-assign an
address of an element in an array:

int parse_cmdline(c har *cmdline, char argv[][64])
{
int i;

i = 0;
cmdline = strtok(cmdline, DELIMITERS);
do {
strcpy(argv[i++], cmdline);
cmdline = strtok(NULL, DELIMITERS);
} while(cmdline != NULL);

return i;
}

Cheers,
Vimal.

--
"If you would be a real seeker after truth, it is necessary that at
least once in your life you doubt, as far as possible, all things."
-- Rene Descartes

[Neil Cerutti]

On 2005-10-18, mi************@ gmail.com <mi************ @gmail.com> wrote:

I'm having problems where I need to parse a command line, and place
each token from strtok() into an array. I've read here:
http://www.phim.unibe.ch/comp_doc/c_...PT/arrays.html (at
bottom) that you can access a char[][] by doing char[i] and getting the
string. However when I try the code below I get

error: invalid use of array with unspecified bounds

whenever argv is accessed. It is declared in main() as:

char argv[ARGV_LENGTH][ARGV_LENGTH]; /* ARGV_LENGTH is a const int of
64 */

This is pretty much my first time with C, I'm usually using Java and a
little C++. Any help is appreciated.

Thanks,
Mike
void parse_cmdline(c har cmdline [], char argv [][])
{

You cannot use unspecified size arrays in C.

In C,

/* 1 */ void f(int a[])

is synonymous with

/* 2 */ void f(int *a)

which is synonymous with

/* 3 */ void f(int a[50000])

They all declare that parameter a is a pointer to int.

Thus, what you have really declared is this:

void parse_cmdline(c har *cmdline, char (*argv)[])

Parameter argv is a pointer to an unspecied size array of char.
All arrays must have a specified size, so your code is an error.
Without knowing the size of the object you are storing in each
element of argv, C has no way to compute indexes, e.g., argv[1].

You need this:

void parse_cmdline(c har cmdline[], char[][ARGV_LENGTH])
{

or this:

void parse_cmdline(c har *cmdline, char (*argv)[ARGV_LENGTH])
{

Some programmers prefer to use the [] syntactic sugar when they
plan to treat the parameter as an array, and the pointer syntax
when they plan to treat it as a pointer. I always use the pointer
syntax, since otherwise I feel like I'm lying to myself. ;)

--
Neil Cerutti

[Christopher Benson-Manica]

mi************@ gmail.com wrote:

I'm having problems where I need to parse a command line, and place
each token from strtok() into an array. I've read here:
http://www.phim.unibe.ch/comp_doc/c_...PT/arrays.html

Don't read there any more. The page dealing with NULL is proof enough
that the site's authors are not to be trusted. They don't seem
particularly interested in so simple a thing as the distinction
between the NULL macro and the null character, among other unfortunate
misstatements.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome.

[Netocrat]

On Tue, 18 Oct 2005 23:00:35 +0530, Vimal Aravindashan wrote:
[...]

int parse_cmdline(c har *cmdline, char argv[][64])
64 would be better as the OP-defined macro ARGV_LENGTH.
{
int i;

i = 0;
cmdline = strtok(cmdline, DELIMITERS);
The original while loop had the correct semantics. This do loop fails to
check for the above function returning NULL. There is nothing wasted - it
is a necessary check.
do {
while(cmdline != NULL && i < ARGV_LENGTH) {
strcpy(argv[i++], cmdline);
cmdline = strtok(NULL, DELIMITERS);
You have perpetuated the OP's use of strtok, and it should be mentioned
that this is in general a less than ideal function for many reasons,
documented in plenty of places (e.g. this group's archives).
} while(cmdline != NULL);
/* return value >= ARGV_LENGTH indicates under-sized buffer */ return i;
}

--
http://members.dodo.com.au/~netocrat

[Vimal Aravindashan]

Netocrat wrote:

On Tue, 18 Oct 2005 23:00:35 +0530, Vimal Aravindashan wrote:
[...]

int parse_cmdline(c har *cmdline, char argv[][64])

64 would be better as the OP-defined macro ARGV_LENGTH.

{
int i;

i = 0;
cmdline = strtok(cmdline, DELIMITERS);

The original while loop had the correct semantics. This do loop fails to
check for the above function returning NULL. There is nothing wasted - it
is a necessary check.

Check the OP's code again. He doesn't check for the first one himself.
In most real world scenarios, there are input specifications. Some of
which favour the programmer. Like in this case, the OP maybe guaranteed
that 'cmdline' parameter has one or more tokens, and also less than 64
(ARGV_LENGTH). Given the OP's code, I think its safe to assume further
that his set of DELIMITERS combined with strtok() will yield the
necessary results for him.

do {

while(cmdline != NULL && i < ARGV_LENGTH) {

strcpy(argv[i++], cmdline);
cmdline = strtok(NULL, DELIMITERS);

You have perpetuated the OP's use of strtok, and it should be mentioned
that this is in general a less than ideal function for many reasons,
documented in plenty of places (e.g. this group's archives).

Above comments apply here too.

} while(cmdline != NULL);

/* return value >= ARGV_LENGTH indicates under-sized buffer */

return i;
}

Cheers,
Vimal.
--
"If you would be a real seeker after truth, it is necessary that at
least once in your life you doubt, as far as possible, all things."
-- Rene Descartes

[Vimal Aravindashan]

Vimal Aravindashan wrote:

Netocrat wrote:

The original while loop had the correct semantics. This do loop fails to
check for the above function returning NULL. There is nothing wasted
- it
is a necessary check.

Check the OP's code again. He doesn't check for the first one himself.
In most real world scenarios, there are input specifications. Some of
which favour the programmer. Like in this case, the OP maybe guaranteed
that 'cmdline' parameter has one or more tokens, and also less than 64
(ARGV_LENGTH). Given the OP's code, I think its safe to assume further
that his set of DELIMITERS combined with strtok() will yield the
necessary results for him.

Oh, and I forgot to mention that all I intended to show the OP was that
he was misusing malloc(). An error he would encounter once he cleared
"invalid use of array with unspecified bounds" error. ( 'misuse' may not
be the proper wording here, but I cant think of another ;-) )

Cheers,
Vimal.
--
"If you would be a real seeker after truth, it is necessary that at
least once in your life you doubt, as far as possible, all things."
-- Rene Descartes

[Netocrat]

On Wed, 19 Oct 2005 10:47:46 +0530, Vimal Aravindashan wrote:

Netocrat wrote:

On Tue, 18 Oct 2005 23:00:35 +0530, Vimal Aravindashan wrote: [...]

int parse_cmdline(c har *cmdline, char argv[][64])

64 would be better as the OP-defined macro ARGV_LENGTH.

{
int i;

i = 0;
cmdline = strtok(cmdline, DELIMITERS);

The original while loop had the correct semantics. This do loop fails
to check for the above function returning NULL. There is nothing
wasted - it is a necessary check.

Check the OP's code again. He doesn't check for the first one himself.

Here is the relevant portion of the OP's code:

command = strtok(cmdline, DELIMITERS); ...
while (command != NULL) {
...
command = strtok(NULL, DELIMITERS);
...
}

This has correct semantics; the do loop does not.

Perhaps you misread my comments as applying to the test for i <
ARGV_LENGTH that I added.
In most real world scenarios, there are input specifications. Some of
which favour the programmer. Like in this case, the OP maybe guaranteed
that 'cmdline' parameter has one or more tokens, and also less than 64
(ARGV_LENGTH).
He may be, however there's no need to assume - the check is simple.

Passing the size of the array's first dimension as a parameter rather than
fixing it as ARGV_LENGTH is a possible extension, but this is probably
beyond the OP's requirements.
Given the OP's code, I think its safe to assume further that his set of
DELIMITERS combined with strtok() will yield the necessary results for
him.

It will likely generate correct results without ill-effect for the OP's
situation, but a general warning re strtok is warranted.

[...]
--
http://members.dodo.com.au/~netocrat