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Sizeof operator

Hi All ,

I u find out size of struct , does it considers paddding chars into
consideration

struct A
{
char c;
int i;
};

struct B
{
int i;
char c;
}

we see that for alignment some bits are added in case of struct A, but not
in case of struct B
A a ;
sizeof(a);
B b;
sizeof(b);

Will this be same in both cases

TIA

Mohan
does it give
Nov 15 '05
12 2120
santosh wrote:
My outlook is hving some problem. I am testing whether I am able to send
mail to news group.
Post below the text you are replying to, not above.
"santosh" <sa************ *@in.bosch.com> wrote in message
news:dc******** **@ns2.fe.inter net.bosch.com.. .
test mail


Don't post test messages to normal groups, look for groups with test in
the name such as alt.test

Don't repost within minutes because you post has not appeared. It can
take hours for a post to appear.

Don't post as a reply to an existing message when you are not replying
to that message.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.
Nov 15 '05 #11
santosh wrote:

This should not have been a reply to an existing message, you should
have created a new post. You message has nothing to do with the subject
line and is completely unrelated to the post you replied to. Even OE can
do this.
Hello,
I have a fundamental doubt regarding alignment of data when it is stored in
memory.
Alignment issues are entirely implementation specific. On some systems
there are NO alignment restrictions.
I understand the data alignment happens because memory is word addressable.
Or for any other reason. Such as a double only being able to be read by
a floating point processor if it is aligned on a double word boundary.
Or because the person who wrote the implementation had shares in a chip
manufacturer and wanted to increase sales of memory chips.
That means when the system accesses any memory location the address should
be divisible by word size (typically 4bytes).
So in this case when suppose I want to see the memory location of the
variable sd.e ( &(sd.e)) , it is refereing to address location which is not
divisible by 4 in a SOLARISH machine(V 5.8).
It may be, it may not.
Can anyone explain why this alignment happens what are benifits etc...?


Sometimes because the processor can only access a particular data type
with a specific alignment. Sometimes because it is inefficient to access
non-aligned data. If you want to know why a specific alignment is used
on a specific system ask on a group dedicated to that system.
--
Flash Gordon
Living in interesting times.
Although my email address says spam, it is real and I read it.
Nov 15 '05 #12
"santosh" <sa************ *@in.bosch.com> writes:
My outlook is hving some problem. I am testing whether I am able to send
mail to news group.


There are test newsgroups for that.
--
Ben Pfaff
email: bl*@cs.stanford .edu
web: http://benpfaff.org
Nov 15 '05 #13

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