Help, getting compiler error warning on returning a temporary character string

[jt]

I'm getting a compiler error: warning C4172: returning address of local
variable or temporary

Here is the function that I have giving this error: I'm returning a
temporary char string and its not liking it.
How can I fix this?

char *dequeue(struct node **first)
{
char temp[1024];
struct node *p=*first;
if(*first==NULL )
{
printf("\nqueue is empty\n");
return(0);
}
else
{
p=*first;
*first=(*first)->next;
strcpy(temp,p->data);
free(p);
return(temp); <----------------- compiler is not liking this
}
}

Big thanks!
JT

[pete]

jt wrote:

I'm getting a compiler error:
warning C4172: returning address of local
variable or temporary

Here is the function that I have giving this error: I'm returning a
temporary char string and its not liking it.
How can I fix this?

char *dequeue(struct node **first)
{
char temp[1024]; return(temp); <----------------- compiler is not liking this
}
}

char *dequeue(struct node **first)
{
static char temp[1024];
return temp;
}

void dequeue(struct node **first, char *temp)
{

}

--
pete

[Al Bowers]

jt wrote:

I'm getting a compiler error: warning C4172: returning address of local
variable or temporary

Here is the function that I have giving this error: I'm returning a
temporary char string and its not liking it.
How can I fix this?

char *dequeue(struct node **first)
{
char temp[1024];
struct node *p=*first;
if(*first==NULL )
{
printf("\nqueue is empty\n");
return(0);
}
else
{
p=*first;
*first=(*first)->next;
strcpy(temp,p->data);
free(p);
return(temp); <----------------- compiler is not liking this
}
}

Yes, storage for the char array ceases when the function
returns. Your compiler is informing you that the return
value is of no value.

A quick fix would be use of the 'static' keyword. Change
the declaration of the char array to:

static char temp[1024];
--
Al Bowers
Tampa, Fl USA
mailto: xa******@myrapi dsys.com (remove the x to send email)
http://www.geocities.com/abowers822/

[jt]

Thank you!
JT

"Al Bowers" <ab*****@myrapi dsys.com> wrote in message
news:3e******** ****@individual .net...

jt wrote:

I'm getting a compiler error: warning C4172: returning address of local
variable or temporary

Here is the function that I have giving this error: I'm returning a
temporary char string and its not liking it.
How can I fix this?

char *dequeue(struct node **first)
{
char temp[1024];
struct node *p=*first;
if(*first==NULL )
{
printf("\nqueue is empty\n");
return(0);
}
else
{
p=*first;
*first=(*first)->next;
strcpy(temp,p->data);
free(p);
return(temp); <----------------- compiler is not liking this
}
}

Yes, storage for the char array ceases when the function
returns. Your compiler is informing you that the return
value is of no value.

A quick fix would be use of the 'static' keyword. Change
the declaration of the char array to:

static char temp[1024];
--
Al Bowers
Tampa, Fl USA
mailto: xab*****@myrapi dsys.com (remove the x to send email)
http://www.geocities.com/abowers822/

[Fred L. Kleinschmidt]

Al Bowers wrote:

jt wrote:

I'm getting a compiler error: warning C4172: returning address of local
variable or temporary

Here is the function that I have giving this error: I'm returning a
temporary char string and its not liking it.
How can I fix this?

char *dequeue(struct node **first)
{
char temp[1024];
struct node *p=*first;
if(*first==NULL )
{
printf("\nqueue is empty\n");
return(0);
}
else
{
p=*first;
*first=(*first)->next;
strcpy(temp,p->data);
free(p);
return(temp); <----------------- compiler is not liking this
}
}
Yes, storage for the char array ceases when the function
returns. Your compiler is informing you that the return
value is of no value.

A quick fix would be use of the 'static' keyword. Change
the declaration of the char array to:

static char temp[1024];

--
Al Bowers
Tampa, Fl USA
mailto: xa******@myrapi dsys.com (remove the x to send email)
http://www.geocities.com/abowers822/

But also be aware that a future call to dequeue() will clobber what is
stored there:
value1 = dequeue(...);
...
value2 = dequeue(...); /* Just clobbered what value1 points to */
--
Fred L. Kleinschmidt
Boeing Associate Technical Fellow
Technical Architect, Common User Interface Services
M/S 2R-94 [phone]
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Date: Mon, 16 May 2005 15:01:32 GMT

I want you both to step back a bit and look at Don't claim more carefully. I
think it is interesting, and very jingoistic, Something a politician would
say at an oil rally, but not as meaningful on close examine. There is no
question (I think) that some of our panels are making net watt-hours today
in a strict energy accounting. It is Don's burden that changes this, and his
odd accounting structure that assures the claim cannot be falsified. But it
is just this that makes it both interesting, and useless for making our long
term energy decisions.
I think we need to examine what "burden" our PV solar structure should carry
and why before we can safely jump on, or off, the bandwagon.

"fkasner" <fk*****@entera ct.com> wrote in message
news:uq******** *****@newssvr12 .news.prodigy.c om... BobG wrote:

Boy, you are tough Don. The way I read that mantra you keep
repeating.."not one net watthour... has ever been produced" means that
a pv panel from the 70s, sitting in the sun, hasn't reached break even
in 35 years? Way unlikely. Only takes one panel to hit break even and I
have disproven your claim. Time is on my side. (Mick Jagger, 1965).

The key to his claim is the usually well hidden costs for collateral
expenses in producing that PV panel and for things that are usually left
out that are after manufacture costs such as synchronous inverters if
you (as is true in most cases) AC rather than low voltage DC.

I don't think he really exaggerates at all.

FK