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Sensibly printed floats?

Hi all,

I'm used to ANSI Common Lisp implementations sanely printing single and
double floats. By sane I mean the printed decimal representation mimics
the underlying binary precision of the float. For example:

[1]> (coerce 2/3 'single-float)
0.6666667
[2]> (coerce 2/300 'single-float)
0.006666667
[3]> (coerce 2/3 'double-float)
0.6666666666666 666d0
[4]> (coerce 2/300 'double-float)
0.0066666666666 66667d0
[5]> (coerce 2/30000 'double-float)
6.6666666666666 67d-5

Does C99 provide a method to print floats this way (apart from `f', `d'
etc. exponential markers)?

Regards,
Adam
Nov 14 '05 #1
4 1819
Adam Warner wrote:
Hi all,

I'm used to ANSI Common Lisp implementations sanely printing single and
double floats. By sane I mean the printed decimal representation mimics
the underlying binary precision of the float. For example:

[1]> (coerce 2/3 'single-float)
0.6666667
[2]> (coerce 2/300 'single-float)
0.006666667
[3]> (coerce 2/3 'double-float)
0.6666666666666 666d0
[4]> (coerce 2/300 'double-float)
0.0066666666666 66667d0
[5]> (coerce 2/30000 'double-float)
6.6666666666666 67d-5

Does C99 provide a method to print floats this way (apart from `f', `d'
etc. exponential markers)?


I'm not entirely sure I understand what you mean by
"this way," but perhaps the "%g" conversion specifier is
what you're looking for.

--
Er*********@sun .com
Nov 14 '05 #2
"Adam Warner" <us****@consult ing.net.nz> wrote

I'm used to ANSI Common Lisp implementations sanely printing single and
double floats. By sane I mean the printed decimal representation mimics
the underlying binary precision of the float. For example:

[1]> (coerce 2/3 'single-float)
0.6666667
[2]> (coerce 2/300 'single-float)
0.006666667
[3]> (coerce 2/3 'double-float)
0.6666666666666 666d0
[4]> (coerce 2/300 'double-float)
0.0066666666666 66667d0
[5]> (coerce 2/30000 'double-float)
6.6666666666666 67d-5

Does C99 provide a method to print floats this way (apart from `f', `d'
etc. exponential markers)?

The %g and %f flags take "width" and "precision" markers.

To print a float for human consumption, just use a bare %g. To print out for
machine accuracy, use %*g and pass DBL_DIG as the specifier. This will allow
you to convert between text and binary and back with no loss of precision.

To print in tables, mess about with the width specifier and %f. As a last
resort you can write your own formatting routine, but you shouldn't have to
do this for general-purpose programming.
Nov 14 '05 #3
Adam Warner wrote:
Hi all,

I'm used to ANSI Common Lisp implementations sanely printing single and
double floats. By sane I mean the printed decimal representation mimics
the underlying binary precision of the float. For example:

[1]> (coerce 2/3 'single-float)
0.6666667
[2]> (coerce 2/300 'single-float)
0.006666667
[3]> (coerce 2/3 'double-float)
0.6666666666666 666d0
[4]> (coerce 2/300 'double-float)
0.0066666666666 66667d0
[5]> (coerce 2/30000 'double-float)
6.6666666666666 67d-5

Does C99 provide a method to print floats this way (apart from `f', `d'
etc. exponential markers)?


Not just C99, but earlier versions of C as well:

#include <stdio.h>
#include <float.h>

int main(void)
{
printf("2/3 single-float: %.*g\n", FLT_DIG, 2.f / 3.f);
printf("2/300 single-float: %.*g\n", FLT_DIG, 2.f / 300.f);
printf("2/3 double-float: %.*g\n", DBL_DIG, 2. / 3.);
printf("2/300 double-float: %.*g\n", DBL_DIG, 2. / 300.);
printf("2/30000 double-float: %.*g\n", DBL_DIG, 2. / 30000.);
return 0;
}

2/3 single-float: 0.666667
2/300 single-float: 0.00666667
2/3 double-float: 0.6666666666666 67
2/300 double-float: 0.0066666666666 6667
2/30000 double-float: 6.6666666666666 7e-05
Nov 14 '05 #4
Hi Martin Ambuhl,
On Sat, 08 Jan 2005 14:10:48 -0500, Martin Ambuhl wrote:
Does C99 provide a method to print floats this way (apart from `f', `d'
etc. exponential markers)?


Not just C99, but earlier versions of C as well:

#include <stdio.h>
#include <float.h>

int main(void)
{
printf("2/3 single-float: %.*g\n", FLT_DIG, 2.f / 3.f);
printf("2/300 single-float: %.*g\n", FLT_DIG, 2.f / 300.f);
printf("2/3 double-float: %.*g\n", DBL_DIG, 2. / 3.);
printf("2/300 double-float: %.*g\n", DBL_DIG, 2. / 300.);
printf("2/30000 double-float: %.*g\n", DBL_DIG, 2. / 30000.);
return 0;
}

2/3 single-float: 0.666667
2/300 single-float: 0.00666667
2/3 double-float: 0.6666666666666 67
2/300 double-float: 0.0066666666666 6667
2/30000 double-float: 6.6666666666666 7e-05


Thanks everyone! Coupled with the # modifier (so e.g. 666667.f prints as
666667. instead of 666667) it should always be possible to dynamically
distinguish a printed float from an integer.

Regards,
Adam
Nov 14 '05 #5

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