copying data to a structure member array

[anonymous]

Hi folks,

I am in a fix trying to copy data to an array which is member of a
structure. What I am doing right now is:

char array[8] = {0,1,2,3,4,5,6, 7};
memcpy(structur e.array, array, 8);

Is there a nicer way of doing this in a single statement?

One way that I can think of is to use

memcpy(structur e.array, "\x0\x1\x2\x3\x 4\x5\x6\x7", 8);

However, what if I don't want to use hex numbers. For example, if
I want to copy 77, 18, 28, 23, 88, 253, 43, 36 decimals to
structure.array[8], I would not like to first convert all these
numbers to hex. How do I do this without having to use another
variable.

Thanks in advance for any help.

[Keith Thompson]

Chris Torek <no****@torek.n et> writes:
[...]

In C99, however, you can use the new anonymous array syntax to
create an array object whose address is then passed to memcpy:

struct S { int array[8]; } structure;
...
memcpy(structur e.array,
(const int [8]){77, 18, 28, 23, 88, 253, 43, 36},
sizeof(int [8]));

I think you have an extra set of parentheses there.

memcpy(structur e.array,
const int [8]){77, 18, 28, 23, 88, 253, 43, 36},
sizeof(int [8]);

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.

[Ben Pfaff]

Keith Thompson <ks***@mib.or g> writes:

I think you have an extra set of parentheses there.

memcpy(structur e.array,
const int [8]){77, 18, 28, 23, 88, 253, 43, 36},
sizeof(int [8]);

I don't see how your "corrected" code could possibly be right.
--
int main(void){char p[]="ABCDEFGHIJKLM NOPQRSTUVWXYZab cdefghijklmnopq rstuvwxyz.\
\n",*q="kl BIcNBFr.NKEzjwC IxNJC";int i=sizeof p/2;char *strchr();int putchar(\
);while(*q){i+= strchr(p,*q++)-p;if(i>=(int)si zeof p)i-=sizeof p-1;putchar(p[i]\
);}return 0;}

[Keith Thompson]

Ben Pfaff <bl*@cs.stanfor d.edu> writes:

Keith Thompson <ks***@mib.or g> writes:

I think you have an extra set of parentheses there.

memcpy(structur e.array,
const int [8]){77, 18, 28, 23, 88, 253, 43, 36},
sizeof(int [8]);

I don't see how your "corrected" code could possibly be right.

You're right (as was Chris Torek), and I was wrong. I misread his
code and thought the second and third lines were enclosed in a set of
parentheses. Sorry.

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.