double while loop in linked list

[picknicker187]

hi,

the following while function(it´s supposed to find word synonyms out of a
list) always quits after running through the list in the inner loop once.
it´s like the aktuell = aktuell->next on the bottom would not be there.
can anyone tell me what the problem might be?

greetz,

bastian
int checksyn(Relati ons *head)
{
char rel = 'S';
Relations *aktuell = head;
Relations *aktuell2 = head;

while (aktuell != NULL)
{
if(aktuell->relType == rel)
{
while (aktuell2 != NULL)
{
if(aktuell2->relType == rel && aktuell2->word == aktuell->dest &&
aktuell->word == aktuell2->dest)

printf("match found for: %c %s %s\n",aktuell->relType, aktuell->word,
aktuell->dest);
else
printf("no match found for: %c %s %s\n", aktuell->relType, aktuell->word,
aktuell->dest);
aktuell2 = aktuell2->next;
}

}
aktuell = aktuell->next;
}
return 0;
}

[Artie Gold]

picknicker187 wrote:

hi,

the following while function(it´s supposed to find word synonyms out of a
list) always quits after running through the list in the inner loop once.
it´s like the aktuell = aktuell->next on the bottom would not be there.
can anyone tell me what the problem might be?

greetz,

bastian
int checksyn(Relati ons *head)
{
char rel = 'S';
Relations *aktuell = head;
Relations *aktuell2 = head;

while (aktuell != NULL)
{
if(aktuell->relType == rel)
{
Once you've run througgh the inner loop, `aktuell2' is NULL. while (aktuell2 != NULL)
{
if(aktuell2->relType == rel && aktuell2->word == aktuell->dest &&
aktuell->word == aktuell2->dest)

printf("match found for: %c %s %s\n",aktuell->relType, aktuell->word,
aktuell->dest);
else
printf("no match found for: %c %s %s\n", aktuell->relType, aktuell->word,
aktuell->dest);
aktuell2 = aktuell2->next;
}

}
aktuell = aktuell->next;
}
return 0;
}

HTH,
--ag

BTW - please post appropriately indented code (spaces, not tabs).

--
Artie Gold -- Austin, Texas

"If you don't think it matters, you're not paying attention."

[Pedro Graca]

picknicker187 wrote:

the following while function(it´s supposed to find word synonyms out of a
list) always quits after running through the list in the inner loop once.
it´s like the aktuell = aktuell->next on the bottom would not be there.
can anyone tell me what the problem might be?

You need to restart aktuell2 before the inner while() loop.

'aktuell = aktuell->next;' is working fine.
The problem is that

while (aktuell2 != NULL) { /* ... */ }

never goes inside the loop the second (or later) time around.

[un-indented code snipped]

Do a favor to us and, especially, to yourself: indent your code.
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[Karthik Kumar]

picknicker187 wrote:

hi,

the following while function(it´s supposed to find word synonyms out of a
list) always quits after running through the list in the inner loop once.
it´s like the aktuell = aktuell->next on the bottom would not be there.
can anyone tell me what the problem might be?

greetz,

bastian
int checksyn(Relati ons *head)
Please post the prototype of Relations.
or better, a compilable code.
{
char rel = 'S';
Relations *aktuell = head;
Relations *aktuell2 = head;

while (aktuell != NULL)
{
if(aktuell->relType == rel)
{
while (aktuell2 != NULL)
{
if(aktuell2->relType == rel && aktuell2->word == aktuell->dest &&
aktuell->word == aktuell2->dest)
Well - I am guessing that the members word and dest are
pointers to characters, from the next line .

Assuming that, aktuell->word == aktuell2->dest may not be what you
want in the previous line. It is comparing pointers, instead of
two C-strings. You may want 'strcmp' .

printf("match found for: %c %s %s\n",aktuell->relType, aktuell->word,
aktuell->dest);

--
Karthik. http://akktech.blogspot.com .
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