function call in conditional operator?

[bnp]

Hi,

Is possible to use functions in conditional operator as ashown below.
.....
.....
int fun1()
{
// body
}

int fun2()
{
//body
}

....
main()
{...
int x;
x = (a>b)?fun1():fu n2();
}

[Ralmin]

"glen herrmannsfeldt" <ga*@ugcs.calte ch.edu> wrote:

Well, in Java you can do it with Object reference variables.

x=(a>b?string1: string2).equals ("hi");

The concept works on C too, except that it's messy to include a reference to
the object as part of the method's arguments.

#include <string.h>

struct string {
int (*equals)(struc t string *, const char *);
char *data;
};

int str_equals(stru ct string *this, const char *other)
{
return !strcmp(this->data, other);
}

int main(void)
{
struct string string1 = {str_equals, "Hello"};
struct string string2 = {str_equals, "World"};
int x, a = 1, b = 2;
x = ((a > b) ? string1 : string2).equals (((a > b) ? &string1 : &string2),
"hi");
return 0;
}

--
Simon.