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function call in conditional operator?

bnp
Hi,

Is possible to use functions in conditional operator as ashown below.
.....
.....
int fun1()
{
// body
}

int fun2()
{
//body
}

....
main()
{...
int x;
x = (a>b)?fun1():fu n2();
}
Nov 14 '05
30 2177
Case <no@no.no> writes:
Kevin Bracey wrote:
Yes. And even more entertainingly, you can do this:
x = (a > b ? fun1 : fun2) (c, d, e);


BTW what other seemingly strange standard C construction
do you know? I mentioned 5["fsdssdfssf "] which looks
very strange to most people even very experienced C
programmers. It would be fun to discuss this kind of
constructs.


Google "Duff's Device".

You might also take a look at the past winners of the International
Obfuscated C Code Contest (google "IOCCC"). Please keep firmly in
mind that some of the earlier winners are non-portable, and that
*none* of them are examples of good C code (except for extremely and
deliberately perverse values of "good").

--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Nov 14 '05 #11
Case wrote:
Kevin Bracey wrote:
Yes. And even more entertainingly, you can do this:

x = (a > b ? fun1 : fun2) (c, d, e);


Yes, of course! Never thought of stretching the meaning
of a function 'pointer' this far.


That's hardly "stretching ", more a "perfectly routine use".

[And people think the Sapir-Whorf hypothesis is false ...]

--
Chris "f(x) := E means updater(f)(x)(E )" Dollin
C FAQs at: http://www.faqs.org/faqs/by-newsgrou...mp.lang.c.html
C welcome: http://www.angelfire.com/ms3/bchambl...me_to_clc.html
Nov 14 '05 #12
On Mon, 17 May 2004 18:40:49 +0000, glen herrmannsfeldt wrote:
bnp wrote:

(snip)
Is possible to use functions in conditional operator as ashown below.


(snip)
int x;
x = (a>b)?fun1():fu n2();


Not only that, you can even do

x=(a>b?fun1:fun 2)();


Yes, that is possible, now that I think of it. It could even be a rather
elegant solution to a problem.

It will, however, leave the wet-behind-the-ears maintenance programmer who
was raised on Java and Visual Basic scratching his head, as well as
sparking a Holy War with those who still believe in Structured Programming. ;)

--
yvoregnevna gjragl-guerr gjb-gubhfnaq guerr ng lnubb qbg pbz
To email me, rot13 and convert spelled-out numbers to numeric form.
"Makes hackers smile" makes hackers smile.

Nov 14 '05 #13
Keith Thompson wrote:
Case <no@no.no> writes:
Kevin Bracey wrote:
Yes. And even more entertainingly, you can do this:
x = (a > b ? fun1 : fun2) (c, d, e);

BTW what other seemingly strange standard C construction
do you know? I mentioned 5["fsdssdfssf "] which looks
very strange to most people even very experienced C
programmers . It would be fun to discuss this kind of
constructs.

Google "Duff's Device".


This one is really amazing! Thanks.

You might also take a look at the past winners of the International
Obfuscated C Code Contest (google "IOCCC"). Please keep firmly in
mind that some of the earlier winners are non-portable, and that
*none* of them are examples of good C code (except for extremely and
deliberately perverse values of "good").


I know IOCCC and own the book "Obfuscated C and Other Mysteries" by Don
Libes. That's real fun too indeed.

Kees

Nov 14 '05 #14
August Derleth <se*@sig.now> scribbled the following:
On Mon, 17 May 2004 18:40:49 +0000, glen herrmannsfeldt wrote:
Not only that, you can even do

x=(a>b?fun1:fun 2)();
Yes, that is possible, now that I think of it. It could even be a rather
elegant solution to a problem. It will, however, leave the wet-behind-the-ears maintenance programmer who
was raised on Java and Visual Basic scratching his head, as well as
sparking a Holy War with those who still believe in Structured Programming. ;)


It's not so much a feature of C as a feature of first-class functions.
In other languages, like ML or Haskell, you can even manufacture new
functions at run-time and then call them.

For example:
mynewfunction :: int -> (int -> int)
mynewfunction x = \y.(x+y)

When called, for example, with an argument of 5, this function returns
a function that adds 5 to its argument. Can you do this in C?

It wouldn't be too much trouble, semantically, to add method references
to Java. How it's handled down at the implemenation level is anyone's
guess, though.

--
/-- Joona Palaste (pa*****@cc.hel sinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"Nothing lasts forever - so why not destroy it now?"
- Quake
Nov 14 '05 #15
In <7d************ *************@p osting.google.c om> bh**********@ya hoo.com (bnp) writes:
Is possible to use functions in conditional operator as ashown below.
....
....
int fun1()
{
// body
}

int fun2()
{
//body
}

...
main()
{...
int x;
x = (a>b)?fun1():fu n2();
}


In such cases, the best way of finding the answer is by trying to answer
another question: why not?

Dan
--
Dan Pop
DESY Zeuthen, RZ group
Email: Da*****@ifh.de
Nov 14 '05 #16
August Derleth wrote:

(snip)
x=(a>b?fun1:f un2)();
Yes, that is possible, now that I think of it. It could even be a rather
elegant solution to a problem. It will, however, leave the wet-behind-the-ears maintenance programmer who
was raised on Java and Visual Basic scratching his head, as well as
sparking a Holy War with those who still believe in Structured Programming. ;)


Well, in Java you can do it with Object reference variables.

x=(a>b?string1: string2).equals ("hi");

something like:

x=!strcmp((a>b? string1:string2 ),"hi");

With Java's reflection, you can probably do the equivalent of
function pointers in a conditional expression, though I won't try.

I don't know about VB at all.

-- glen

Nov 14 '05 #17
"Case" <no@no.no> wrote in message

BTW what other seemingly strange standard C construction
do you know? I mentioned 5["fsdssdfssf "] which looks
very strange to most people even very experienced C
programmers. It would be fun to discuss this kind of
constructs.

C allows a lot of this sort of thing in order to make the compiler's grammar
easier to specify.
The problem is that people then think it is fun to use such constructions in
production code.
Nov 14 '05 #18
On Mon, 17 May 2004 18:17:05 +0200, Case <no@no.no> wrote:
Yes, of course! Never thought of stretching the meaning
of a function 'pointer' this far. Things like 5["Hello world"]
(as you know I'm sure) are entertaining too.


I'm a bit stumped here, how does 5("Hello world"); works?
#define 5(_a) printf("%s",_a) ?
Nov 14 '05 #19
Mitchell <ch************ ***@inahatespam me.cohatespamm> scribbled the following:
On Mon, 17 May 2004 18:17:05 +0200, Case <no@no.no> wrote:
Yes, of course! Never thought of stretching the meaning
of a function 'pointer' this far. Things like 5["Hello world"]
(as you know I'm sure) are entertaining too.

I'm a bit stumped here, how does 5("Hello world"); works?
#define 5(_a) printf("%s",_a) ?


5("Hello world"); doesn't work. It's 5["Hello world"] with square
brackets instead of normal ones. It works because [] is actually a
commutative operator - a[b] is the exact same thing as b[a].

--
/-- Joona Palaste (pa*****@cc.hel sinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
Nov 14 '05 #20

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