Size of Allocated Memory

[mandark_br]

I have a function that returns a int pointer to a allocated memory.
How I know the size of this allocated memory?

Compiler = gcc
Ex.:

int main(void)
{
int *pointer;
pointer = fakefunc();

/* How I know the size of allocated memory?? */

return 0;
}

[Jens.Toerring]

mandark_br <ma*****@rockpe sado.com.br> wrote:

I have a function that returns a int pointer to a allocated memory.
How I know the size of this allocated memory? int main(void)
{
int *pointer;
pointer = fakefunc(); /* How I know the size of allocated memory?? */
By simply storing it when you allocate the memory and then
returning it from fakefunc() together with the pointer.
There's no standard function that would give you that
information just from the pointer.
Compiler = gcc

The compiler is completely irrelevant. If you're looking
for a non-portable solution you will have to check if the
libc you're using has an extension for doing that because
the libc is where malloc() and friends are defined.

Regards. Jens
--
\ Jens Thoms Toerring ___ Je***********@p hysik.fu-berlin.de
\______________ ____________ http://www.toerring.de

[Eric Sosman]

mandark_br wrote:

I have a function that returns a int pointer to a allocated memory.
How I know the size of this allocated memory?

This is Question 7.27 in the comp.lang.c Frequently
Asked Questions (FAQ) list

http://www.eskimo.com/~scs/C-faq/top.html

.... and you may want to look at Question 7.26 also. You
won't like the answers, though.

--
Er*********@sun .com

[Alex Monjushko]

mandark_br <ma*****@rockpe sado.com.br> wrote:

I have a function that returns a int pointer to a allocated memory.
How I know the size of this allocated memory? Compiler = gcc
Ex.: int main(void)
{
int *pointer;
pointer = fakefunc(); /* How I know the size of allocated memory?? */ return 0;
}

You can't, and you shouldn't need to. It is your responsibility to keep
track of how much memory 'fakefunc' allocates. If you can't do that in
your context, then show us a more concrete example.

--
Alex Monjushko (mo*******@hotm ail.com)