how to remove a character from a string

[Toto]

Hello,
my problem is quite simple to explain.
I have the following string:

"table+came ra"

and I want to remove the + sign:
"tablecamer a".

How do i do that ?
Thanks for your help.

[Arthur J. O'Dwyer]

On Wed, 7 Apr 2004, Toto wrote:

I have the following string:
"table+came ra"
and I want to remove the + sign:
"tablecamer a".

How do i do that ?

#include <string.h>

char s[] = "table+came ra";
char *p;

while ((p = strchr(s,'+')) != NULL)
strcpy(p, p+1);

Make sure to read the FAQ on string manipulation, too.

HTH,
-Arthur

[Christopher Benson-Manica]

Toto <ma*@nospam.com > spoke thus:

"table+came ra"
and I want to remove the + sign:
"tablecamer a".

Well, I hope this isn't a homework question, because I'll post an
answer:

void rem_char( char *s, char t )
{
if( !s || !*s ) return;

while( *s++ != t ) if( !*s ) return;
while( *(s-1)=*s++ );
}

I don't guarantee that it's conforming, but it produced correct
results for me.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome.

[Eric Sosman]

"Arthur J. O'Dwyer" wrote:

On Wed, 7 Apr 2004, Toto wrote:

I have the following string:
"table+came ra"
and I want to remove the + sign:
"tablecamer a".

How do i do that ?

#include <string.h>

char s[] = "table+came ra";
char *p;

while ((p = strchr(s,'+')) != NULL)
strcpy(p, p+1);

This is only guaranteed to work if the '+' is the
last character in the string. Otherwise the source and
destination overlap, which is a no-no for strcpy(). A
safe alternative is

memmove(p, p+1, strlen(p+1)+1);

.... which can be simplified to

memmove(p, p+1, strlen(p));

Also, the Little Tin God might be better propitiated
by replacing the `while' with

p = s;
while ((p = strchr(p, '+')) != NULL)

.... thus not searching and re-searching and re-re-searching
parts of `s' already known to be free of '+' characters.

--
Er*********@sun .com

[Martin Dickopp]

"Arthur J. O'Dwyer" <aj*@nospam.and rew.cmu.edu> writes:

On Wed, 7 Apr 2004, Toto wrote:

I have the following string:
"table+came ra"
and I want to remove the + sign:
"tablecamer a".

How do i do that ?

#include <string.h>

char s[] = "table+came ra";
char *p;

while ((p = strchr(s,'+')) != NULL)
strcpy(p, p+1);

7.21.2.3#2 (strcpy): "[...] If copying takes place between objects that
overlap, the behavior is undefined."

(Your algorithm is also inefficient, because it scans `s' from the
beginning after replacing each '+' character.)

I suggest the following:

char s [] = "table+came ra";
const char *src = s;
char *dst = s;

do
{
while (*src == '+')
++src;
}
while ((*dst++ = *src++) != '\0');

Martin
--
,--. Martin Dickopp, Dresden, Germany ,= ,-_-. =.
/ ,- ) http://www.zero-based.org/ ((_/)o o(\_))
\ `-' `-'(. .)`-'
`-. Debian, a variant of the GNU operating system. \_/

[Eric Sosman]

Eric Sosman wrote:

"Arthur J. O'Dwyer" wrote:

while ((p = strchr(s,'+')) != NULL)
strcpy(p, p+1);

This is only guaranteed to work if the '+' is the
last character in the string. [...]

And now that I think about it, not even then.

--
Er*********@sun .com

[code_wrong]

"Toto" <ma*@nospam.com > wrote in message
news:c5******** **@news-reader4.wanadoo .fr...

Hello,
my problem is quite simple to explain.
I have the following string:

"table+came ra"

and I want to remove the + sign:
"tablecamer a".

How do i do that ?
Thanks for your help.

#define MAX_LEN 1000

char input_string[MAX_LEN];
char output_string[MAX_LEN];

strcpy(input_st ring, "table+camera") ;
int len = strlen(input_st ring);
int j =0;
for(int i =0; i<=len; i++)/*we wanna copy the null terminator*/
{
if(input_string[i] != '+')
{
output_string[j] = input_string[i];
j++;
}
}

[Joe Wright]

Toto wrote:

Hello,
my problem is quite simple to explain.
I have the following string:

"table+came ra"

and I want to remove the + sign:
"tablecamer a".

How do i do that ?
Thanks for your help.

#include <stdio.h>
#include <string.h>

int main(void) {
char string[] = "table+came ra";
char *s;
int i;
puts(string);
s = strchr(string, '+');
i = s - string + 1;
while ((*s++ = string[i++])) ;
puts(string);
return 0;
}

Try this.
--
Joe Wright mailto:jo****** **@comcast.net
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---

[Mac]

On Wed, 07 Apr 2004 22:34:59 +0200, Toto wrote:

Hello,
my problem is quite simple to explain.
I have the following string:

"table+came ra"

and I want to remove the + sign:
"tablecamer a".

How do i do that ?
Thanks for your help.

Use strchr() to find the character. Use memmove() to copy over it. If you
want to replace more than one instance of the character, do this
repeatedly until strchr() returns NULL.

If there is any chance that the string is long, be sure to avoid
re-searching the whole string for the character.

HTH

--Mac

[pete]

Toto wrote:

Hello,
my problem is quite simple to explain.
I have the following string:

"table+came ra"

and I want to remove the + sign:
"tablecamer a".

How do i do that ?
Thanks for your help.

/* BEGIN new.c */

#include <stdio.h>

#define STRING "table+came ra"
#define WHITE "+"

char *str_squeeze(ch ar *, const char *);
char *str_tok_r(char *, const char *, char **);
size_t str_spn(const char *, const char *);
size_t str_cspn(const char *, const char *);
char *str_chr(const char *, int);
char *str_cpy(char *, const char *);

int main(void)
{
const char *const original = STRING;
char s1[sizeof STRING];

puts(str_squeez e(str_cpy(s1, original), WHITE));
return 0;
}

char *str_squeeze(ch ar *s1, const char *s2)
{
char *p3;
char const *const p2 = s2;
char *const p1 = s1;

s2 = str_tok_r(p1, p2, &p3);
while (s2 != NULL) {
while (*s2 != '\0') {
*s1++ = *s2++;
}
s2 = str_tok_r(NULL, p2, &p3);
}
*s1 = '\0';
return p1;
}

char *str_tok_r(char *s1, const char *s2, char **p1)
{
if (s1 != NULL) {
*p1 = s1;
}
s1 = *p1 + str_spn(*p1, s2);
if (*s1 == '\0') {
return NULL;
}
*p1 = s1 + str_cspn(s1, s2);
if (**p1 != '\0') {
*(*p1)++ = '\0';
}
return s1;
}

size_t str_spn(const char *s1, const char *s2)
{
size_t n;

for (n = 0; *s1 != '\0' && str_chr(s2, *s1) != NULL; ++s1) {
++n;
}
return n;
}

size_t str_cspn(const char *s1, const char *s2)
{
size_t n;

for (n = 0; str_chr(s2, *s1) == NULL; ++s1) {
++n;
}
return n;
}

char *str_chr(const char *s, int c)
{
while (*s != (char)c) {
if (*s == '\0') {
return NULL;
}
++s;
}
return (char *)s;
}

char *str_cpy(char *s1, const char *s2)
{
char *const p1 = s1;

do {
*s1 = *s2++;
} while (*s1++ != '\0');
return p1;
}

/* END new.c */

--
pete