execlp() - mystery arg

[Erik S. Bartul]

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed.

the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.

my question is, what does the third argument do?

[Joona I Palaste]

Erik S. Bartul <ad***@phork.ne t> scribbled the following:

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed. the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer. my question is, what does the third argument do?

Something POSIX-specific. Ask in comp.unix.progr ammer.

--
/-- Joona Palaste (pa*****@cc.hel sinki.fi) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/

[Sean Kenwrick]

"Erik S. Bartul" <ad***@phork.ne t> wrote in message
news:z90Yb.4152 6$yE5.169277@at tbi_s54...

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed.

the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.

my question is, what does the third argument do?

excelp() allows you to pass the arguments as a list strings terminated by 0:
e.g

execlp("MyProgr am","parm1","pa rm2","another parm", (char *) 0);

The function you were (almost) describing is execvp() which takes the first
two parameters as you describe above but there is no third parameter....

Sean

[David Rubin]

Erik S. Bartul wrote:

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed. the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer. my question is, what does the third argument do?

This terminates the argument list. man execlp.

/david

--
Andre, a simple peasant, had only one thing on his mind as he crept
along the East wall: 'Andre, creep... Andre, creep... Andre, creep.'
-- unknown

[Alex Monjushko]

Erik S. Bartul <ad***@phork.ne t> wrote:

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed. the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer. my question is, what does the third argument do?

There is no such function is standard C. You may want to try:

comp.unix.progr ammer

Or, failing that, the documentation on your system. Seriously.

--
Alex Monjushko (mo*******@hotm ail.com)

[Jack Klein]

On Mon, 16 Feb 2004 16:41:34 +0000 (UTC), "Sean Kenwrick"
<sk*******@hotm ail.com> wrote in comp.lang.c:

"Erik S. Bartul" <ad***@phork.ne t> wrote in message
news:z90Yb.4152 6$yE5.169277@at tbi_s54...

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed.

the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.

my question is, what does the third argument do?

excelp() allows you to pass the arguments as a list strings terminated by 0:
e.g

execlp("MyProgr am","parm1","pa rm2","another parm", (char *) 0);

The function you were (almost) describing is execvp() which takes the first
two parameters as you describe above but there is no third parameter....

Sean

Please cite the references from any version of the ISO C Standard for
the above.

--
Jack Klein
Home: http://JK-Technology.Com
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[CBFalconer]

Sean Kenwrick wrote:

"Erik S. Bartul" <ad***@phork.ne t> wrote in message

as i understand if, the first argument of execlp() is a null terminated
string containing the path of the command which to be executed.

the second argument is an array of pointers to null terminated strings,
containing the arguments to be passed to said command, ending in a null
pointer.

my question is, what does the third argument do?

excelp() allows you to pass the arguments as a list strings terminated by 0:
e.g

execlp("MyProgr am","parm1","pa rm2","another parm", (char *) 0);

The function you were (almost) describing is execvp() which takes the first
two parameters as you describe above but there is no third parameter....

Please DO NOT post answers to off-topic questions in c.l.c. Refer
the OP to an appropriate newsgroup, where other posters are likely
to be able to criticise any faulty answers.

To the OP: Close to 50% of all answers posted anywhere are wrong
to some degree or other. Your only protection is to have this go
on in the open under the scrutiny of people knowledgeable about
the subject. execlp() does not exist in standard C, and thus does
not exist in c.l.c and we have absolutely no knowledge about it.

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Available for consulting/temporary embedded and systems.
<http://cbfalconer.home .att.net> USE worldnet address!