Hi All,
I saved hashed values of hex into buf[32], then buf becomes unreadable
by the means of calling puts(buf), printf("%s") and so on. Then, I
need to convert the hex in buf[] into a char buffer cbuf[32], by
calling sprintf(). I did:
sprintf(cbuf, "%x", buf);
No error! Just no working. Well, I used sprintf() a lot in format "%s"
"%d", and liked sprintf. It is my first time of using it in format
"%x". I wonder does format affect sprintf? Anybody can help me to get
this trick? Thanks!
Huey 2 2540
Huey wrote: Hi All,
I saved hashed values of hex into buf[32], then buf becomes unreadable by the means of calling puts(buf), printf("%s") and so on. Then, I need to convert the hex in buf[] into a char buffer cbuf[32], by calling sprintf(). I did:
sprintf(cbuf, "%x", buf);
I understand very little of what you've said, but if buf is an array
then you certainly cannot use it this way in a sprintf call. The %x
format specifier applies *ONLY* to unsigned int. If you pass anything
else, the behavior is undefined.
I would try to suggest an alternative, but I have no idea what you are
trying to do.
-Kevin
--
My email address is valid, but changes periodically.
To contact me please use the address from a recent posting.
"Huey" <hu********@yah oo.com> schrieb im Newsbeitrag
news:ae******** *************** ***@posting.goo gle.com... Hi All,
I saved hashed values of hex into buf[32], then buf becomes unreadable by the means of calling puts(buf), printf("%s") and so on. Then, I need to convert the hex in buf[] into a char buffer cbuf[32], by calling sprintf(). I did:
sprintf(cbuf, "%x", buf);
Try
(CHAR_BIT == 8 assumed)
#include <stdlib.h>
#include <stdio.h>
int main(void)
{
int i;
unsigned char buf[32] =
{0, 1, 2, 3, 4, 5, 55, 66, 77};
char cbuf[97];
for(i = 0; i < 32; i++)
{
sprintf(cbuf + 3 * i, "%02x ", buf[i]);
}
puts(cbuf);
return EXIT_SUCCESS;
} No error! Just no working. Well, I used sprintf() a lot in format "%s" "%d", and liked sprintf. It is my first time of using it in format "%x". I wonder does format affect sprintf? Anybody can help me to get this trick? Thanks!
from N869:
o,u,x,X The unsigned int argument is converted to unsigned octal (o),
unsigned
decimal (u), or unsigned hexadecimal notation (x or X) in the style dddd;
the
letters abcdef are used for x conversion and the letters ABCDEF for X
conversion. The precision specifies the minimum number of digits to appear;
if the value being converted can be represented in fewer digits, it is
expanded
with leading zeros. The default precision is 1. The result of converting a
zero value with a precision of zero is no characters. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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