why overflow?

[milton]

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Compiled by Turboc 2.0,PC with win2000

main()
{
int a=32767;
long b=a+1;
printf("%d,%ld" ,a,b);
}

that output a and b with 32767,-32768.why overflow?

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[pete]

milton wrote:

**** Post for FREE via your newsreader at post.usenet.com ****

Compiled by Turboc 2.0,PC with win2000

main()
{
int a=32767;
long b=a+1;
printf("%d,%ld" ,a,b);
}

that output a and b with 32767,-32768.why overflow?

/*
** int plus int (a + 1), equals int.
** int plus long (a + 1L), equals long.
*/

/* BEGIN new.c */

#include <stdio.h>
#include <limits.h>

int main(void)
{
short a = SHRT_MAX;
long b;

b = a + 1L;
printf("%d, %ld\n", a, b);

b = (long)a + 1;
printf("%d, %ld\n", a, b);

return 0;
}

/* END new.c */

--
pete

[Niklas Norrthon]

"milton" <py*@mail.zjitc .net> wrote in message news:<3f******@ post.usenet.com >...

**** Post for FREE via your newsreader at post.usenet.com ****

Compiled by Turboc 2.0,PC with win2000

main()
{
int a=32767;
long b=a+1;
printf("%d,%ld" ,a,b);
}

that output a and b with 32767,-32768.why overflow?

Try to run this program on your different platforms:

#include <limits.h>
#include <stdio.h>

int main(void)
{
printf("char: %d\n", (int)CHAR_MAX);
printf("short: %d\n", (int)SHRT_MAX);
printf("int: %d\n", INT_MAX);
printf("long: %ld\n", LONG_MAX);
return 0;
}

[Keith Thompson]

pete <pf*****@mindsp ring.com> writes:

milton wrote:

**** Post for FREE via your newsreader at post.usenet.com ****

Compiled by Turboc 2.0,PC with win2000

main()
{
int a=32767;
long b=a+1;
printf("%d,%ld" ,a,b);
}

that output a and b with 32767,-32768.why overflow?

/*
** int plus int (a + 1), equals int.
** int plus long (a + 1L), equals long.
*/

[...]

More generally, the type of an expression (even if it's a
subexpression) is determined by the types of its operands; the context
in which it appears has no effect. Assuming that the type is affected
by the context seems to be a common newbie error (no offense to the OP
intended). For example, few programmers are surprised that

int n = 16 / 5;

performs an integer division and assigns the value 3 to n, but I've
seen people become deeply offended that

float f = 1 / 3;

sets f to 0.0 (because the conversion happens *after* the division).

--
Keith Thompson (The_Other_Keit h) ks*@cts.com <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://www.sdsc.edu/~kst>
Schroedinger does Shakespeare: "To be *and* not to be"

[Peter Nilsson]

Keith Thompson <ks*@cts.com> wrote in message news:<lz******* *****@cts.com>. ..

pete <pf*****@mindsp ring.com> writes:

milton wrote:

**** Post for FREE via your newsreader at post.usenet.com ****

Compiled by Turboc 2.0,PC with win2000

main()
{
int a=32767;
long b=a+1;
printf("%d,%ld" ,a,b);
}

that output a and b with 32767,-32768.why overflow?

/*
** int plus int (a + 1), equals int.
** int plus long (a + 1L), equals long.
*/

[...]

More generally, the type of an expression (even if it's a
subexpression) is determined by the types of its operands; the context
in which it appears has no effect.

There can be subtleties like integer promotion. The type of an
expression passed to sizeof can be different to the promoted type of
the same expression passed as an argument to printf().

--
Peter

[Peter Nilsson]

ni***@passagen. se (Niklas Norrthon) wrote in message news:<d1******* *************** ****@posting.go ogle.com>...
....

printf("short: %d\n", (int)SHRT_MAX);

The cast is redundant.

--
Peter