Here is the code..
#define NAME "MEGATHINK, INC"
#define ADDRESS "10 Megabuck Plaza"
#define PLACE "Megapolis, CA 94904"
int main()
{
starbar();
printf("%s\n",N AME);
printf("%s\n",A DDRESS);
printf("%s\n",P LACE);
starbar();
}
#include <stdio.h>
#define LIMIT 65
starbar()
{
int count;
for (count=1;count< =LIMIT;count++)
putchar('*');
putchar('\n');
}
it shows me the following warning message
implicit declaration of function 'starbar'
implicit declaration of function 'printf'
control reaches end of non-void function
Could anyone explain why this happens.. i'm still having hard time
learning C
thanks in advance. 3 2236
>Subject: Novice question.. From: "herrcho" he*********@kor net.net Date: 8/9/03 4:52 PM Hawaiian Standard Time Message-id: <bh**********@n ews1.kornet.net >
Here is the code..
#define NAME "MEGATHINK, INC" #define ADDRESS "10 Megabuck Plaza" #define PLACE "Megapolis, CA 94904"
int main() { starbar(); printf("%s\n",N AME); printf("%s\n",A DDRESS); printf("%s\n",P LACE); starbar(); }
#include <stdio.h> #define LIMIT 65 starbar() { int count; for (count=1;count< =LIMIT;count++) putchar('*'); putchar('\n'); }
it shows me the following warning message
implicit declaration of function 'starbar'
You didin't have a function definition for starbar when the compiler reached
the declaration. It will assume you meant
int starbar();
Which is not what you meant.
Put the include and function definition for starbar on top.implicit declaration of function 'printf'
see above.
control reaches end of non-void function
You declare main to return an int. Yet you have no "return" statement in main. Could anyone explain why this happens.. i'm still having hard time learning C
Well, it wasn't that bad. Just put things in the right order..
Stuart
#include <stdio.h>
#define LIMIT 30
#define NAME "MEGATHINK, INC"
#define ADDRESS "10 Megabuck Plaza"
#define PLACE "Megapolis, CA 94904"
int starbar();
int main()
{
starbar();
printf("%s\n",N AME);
printf("%s\n",A DDRESS);
printf("%s\n",P LACE);
starbar();
}
starbar()
{
int count;
for (count=1;count< =LIMIT;count++)
putchar('*');
putchar('\n');
}
herrcho wrote: Here is the code..
#define NAME "MEGATHINK, INC" #define ADDRESS "10 Megabuck Plaza" #define PLACE "Megapolis, CA 94904"
int main() { starbar(); printf("%s\n",N AME); printf("%s\n",A DDRESS); printf("%s\n",P LACE); starbar(); }
#include <stdio.h> #define LIMIT 65 starbar() { int count; for (count=1;count< =LIMIT;count++) putchar('*'); putchar('\n'); }
it shows me the following warning message
implicit declaration of function 'starbar'
Because you use starbar() in your main() function /before/ you define it.
Your definition of starbar() follows, later in your source code.
implicit declaration of function 'printf'
Because you use printf() in your main() function /before/ you define it.
Your definition of printf() follows; it comes from the
#include <stdio.h>
control reaches end of non-void function
You do not define starbar() to return any explicit type of value, so (as is the
C89 standard), it defaults to returning an int ("implicit int" in the standard).
However, your starbar() function neglects to explicitly return an int value (it
does not have a return statement that returns an int), so the compiler warns you
about this nonstandard behaviour. Could anyone explain why this happens.. i'm still having hard time learning C
thanks in advance.
--
Lew Pitcher
Master Codewright and JOAT-in-training
Registered Linux User #112576 ( http://counter.li.org/)
Slackware - Because I know what I'm doing. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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