please help with strcmp()

[Andrej Hocevar]

Hello,
I'm having problems with string comparisons.
I have data like char d1[3] = {1, 2, 3} and char d2[1][3] = {1, 2,
3}. Now if I do strcmp(d1, d2[1]), it compares only the first
character, it seems. What is the correct solution?

Thanks,
andrej

--
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[Emmanuel Delahaye]

In 'comp.lang.c', Andrej Hocevar <dr******@volja .net> wrote:

I'm having problems with string comparisons.
I have data like char d1[3] = {1, 2, 3} and char d2[1][3] = {1, 2,
How is {1,2,3} a string?

Remainder : "a string is an array of characters terminated by a 0".

You want (maybe)

char d1[] = {1, 2, 3, 0};

or more likely

char d1[] = {'1', '2', '3', 0};

or

char d1[] = "123";
3}. Now if I do strcmp(d1, d2[1]), it compares only the first
character, it seems. What is the correct solution?

You must be sure that the adresses passed to strcmp() points to valid
strings.

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[Russell Hanneken]

"Andrej Hocevar" <dr******@volja .net> wrote in message
news:sl******** *************@s onet.utopija.li nux...

I'm having problems with string comparisons.
I have data like char d1[3] = {1, 2, 3} and char d2[1][3] = {1, 2,
3}. Now if I do strcmp(d1, d2[1]), it compares only the first
character, it seems. What is the correct solution?

A string is a sequence of characters that ends with a null character. I
don't see any strings in your example, and I can't figure out what you mean
to do. Maybe you should be using strncmp or memcmp? In any case, the
second argument to strcmp--d2[1]--produces undefined results. There is no
d2[1]. There is only d2[0].

--
Russell Hanneken
rh*******@pobox .com

[Gordon Burditt]

>I'm having problems with string comparisons.

I have data like char d1[3] = {1, 2, 3} and char d2[1][3] = {1, 2,
3}. Now if I do strcmp(d1, d2[1]), it compares only the first
character, it seems.
How did you determine this? You obviously used more code than
described above.
What is the correct solution?

A string has a '\0' terminator. The crap you are passing to
strcmp() above doesn't, so it's not a string.

Gordon L. Burditt