Hello.
Based on this simple test program:
class Test {};
int main()
{
Test t;
const Test u;
}
Why does the definition of 'u' fail? What if all that's wanted is to
have a default constructed Test object? Must one explicitly write so? E.g.:
const Test u = Test();
What's the rationale for such restriction? And, lastly, why does
defining a default constructor solve the issue? I.e.:
class Test
{
public:
Test() {}
};
int main()
{
Test t;
const Test u;
}
Now the compiler accepts it just fine. Why? Pardon me if the answer to
these questions should be obvious. I don't presently find them to be so.
Thank you,
--
Ney André de Mello Zunino 5 9119
which compiler you are using..?
I tried it on VC++ compiler it is not giving any error in both the
cases
since constructor is called during object creation, it doesn't matter
wether the object is const or not
by declaring a object as const the only restrictions that you have on
it is
-- you can only call const methods of that object( ex: methods like
void print() const )
-- you cannot modify any member variables
Ney André de Mello Zunino wrote:
[snip] What's the rationale for such restriction? And, lastly, why does defining a default constructor solve the issue? I.e.:
The code you posted is not your real code.
The code you posted should compile fine without a problem,
since if you don't define any constructor on your own, the compiler
will create a default constructor for you.
So please post your real problem code.
--
Karl Heinz Buchegger kb******@gascad .at
Ney André de Mello Zunino wrote: class Test {};
int main() { Test*t; const*Test*u; }
Why does the definition of 'u' fail?
[8.5]
9. If no initializer is specified for an object, and the object is of
(possibly cv-qualified) non-POD class type (or array thereof), the object
shall be default-initialized; if the object is of const-qualified type,
the underlying class type shall have a user-declared default constructor.
Otherwise, if no initializer is specified for an object, the object and
its subobjects, if any, have an indeterminate initial value 90) ; if the
object or any of its subobjects are of const-qualified type, the program
is ill-formed.
Your object is of const POD type, then the last sentence of the paragraph
applies.
MM
* Karl Heinz Buchegger: Ney André de Mello Zunino wrote: [snip] What's the rationale for such restriction? And, lastly, why does defining a default constructor solve the issue? I.e.:
The code you posted is not your real code. The code you posted should compile fine without a problem, since if you don't define any constructor on your own, the compiler will create a default constructor for you.
So please post your real problem code.
Sorry.
Check out the standard's text quoted by "Max M." in this thread;
some explicit definition of the value is necessary for a const
object.
Unfortunately Visual C++ erronously compiles the code, at least as
I remember it it does.
--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
"Alf P. Steinbach" wrote: * Karl Heinz Buchegger: Ney André de Mello Zunino wrote: [snip] What's the rationale for such restriction? And, lastly, why does defining a default constructor solve the issue? I.e.:
The code you posted is not your real code. The code you posted should compile fine without a problem, since if you don't define any constructor on your own, the compiler will create a default constructor for you.
So please post your real problem code.
Sorry.
Check out the standard's text quoted by "Max M." in this thread; some explicit definition of the value is necessary for a const object.
I saw it.
I didn't know that.
I learned.
--
Karl Heinz Buchegger kb******@gascad .at This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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