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ofstream

Hello,

ofstream ofs;

fun(char* str)
{
ofs<<str<<endl;
}

void main()
{

int i=0;
....
....

if(i)
{
ofs.open("text. txt");
fun("heih0");
}
else
{
// Here iam not opening file
fun("heih0");
}

}

In the above code, in else condition iam not opening file, but still
calling fun(), What happens here???

Regards

Jul 23 '05 #1
11 3823
"Gurikar" <ms*******@gmai l.com> wrote in message
news:11******** **************@ g43g2000cwa.goo glegroups.com
Hello,

ofstream ofs;

fun(char* str)
{
ofs<<str<<endl;
}

void main()
{

int i=0;
...
...

if(i)
{
ofs.open("text. txt");
fun("heih0");
}
else
{
// Here iam not opening file
fun("heih0");
}

}

In the above code, in else condition iam not opening file, but still
calling fun(), What happens here???

Regards

Here I am, banging my head with a hammer. What happens here?

--
John Carson
Jul 23 '05 #2

"Gurikar" <ms*******@gmai l.com> wrote in message
news:11******** **************@ g43g2000cwa.goo glegroups.com.. .
Hello,

ofstream ofs;

fun(char* str)
{
ofs<<str<<endl;
}

void main()
{

int i=0;
...
...

if(i)
{
ofs.open("text. txt");
fun("heih0");
}
else
{
// Here iam not opening file
fun("heih0");
}

}

In the above code, in else condition iam not opening file, but still
calling fun(), What happens here???


Who knows, the above code is not C++. Neither would it compile on any
compiler(c++ or not). fun() has no return type, ofs in fun() is not defined.
main must return an integer. You need to read up on scopes and lifetime of
objects.

try something like:

#include <iostream>
#include <fstream>
#include <string>

void fun(std::ofstre am& ofs, const std::string s)
{
ofs << s << std::endl;
}

int main()
{
bool b_havefun = false;

// output file stream
std::string s_file("text.tx t");
std::ofstream ofs;
ofs.open(s_file .c_str());
if (!ofs)
{
std::cout << "error while opening " << s_file << std::endl;
}

if (b_havefun)
{
fun(ofs, "lets party");
}
else
{
fun(ofs, "off to work");
}

return 0;
}

Write-protect the text.txt file to see the error message.
Jul 23 '05 #3

"Gurikar" <ms*******@gmai l.com> wrote in message
news:11******** **************@ g43g2000cwa.goo glegroups.com.. .
Hello,

#include <cstdlib>
#include <fstream>
#include <ostream>
using namespace std;
ofstream ofs;

fun(char* str)
Return type required. e.g.:

void fun(char *str)
{
ofs<<str<<endl;
}

void main()
'main()' is required to have return type of 'int'.

int main()
{

int i=0;
...
...

if(i)
{
ofs.open("text. txt");
You should check whether the open succeeded or failed.

if(!ofs)
{
cerr << "can't open file\n";
return EXIT_FAILURE;
}

fun("heih0");
}
else
{
// Here iam not opening file
fun("heih0");
}

}

In the above code, in else condition iam not opening file, but still
calling fun(), What happens here???


The call to ofs<< will fail.
-Mike
Jul 23 '05 #4
codigo wrote:
"Gurikar" <ms*******@gmai l.com> wrote:

ofstream ofs;

fun(char* str)
{
ofs<<str<<endl;
}


The above code is not C++. Neither would it compile on any
compiler(c++ or not). fun() has no return type, ofs in fun()
is not defined. main must return an integer. You need to read
up on scopes and lifetime of objects.


It's you who needs to read up on scopes: 'ofs' in fun()
correctly refers to the global (file-scope) variable 'ofs'.

Jul 23 '05 #5

ofstream ofs;
ofs<<"hello"<<e ndl;

here i have not opened file, iam able to use this, only thing file wont
get created(its like dummy). I checked it, its running file, ofs value
is NULL. But i want to know does it affect performance. Actually i dont
want to write in a file in some situation so i wont open file, in some
case i want write a file, so i open a file. and call this. So just
using ofs<<"hello"<<e ndl many times affect performance without opening
file( i mean is performancei is same as withour using
ofs<<"hello"<<e ndl in code.)

Regards

Jul 23 '05 #6
On 12 May 2005 20:48:31 -0700, "Gurikar" <ms*******@gmai l.com> wrote
in comp.lang.c++:

ofstream ofs;
ofs<<"hello"<<e ndl;

here i have not opened file, iam able to use this, only thing file wont
get created(its like dummy). I checked it, its running file, ofs value
is NULL. But i want to know does it affect performance. Actually i dont
want to write in a file in some situation so i wont open file, in some
case i want write a file, so i open a file. and call this. So just
using ofs<<"hello"<<e ndl many times affect performance without opening
file( i mean is performancei is same as withour using
ofs<<"hello"<<e ndl in code.)

Regards


Writing to an uninitialized stream is completely undefined behavior.
It could do nothing. It could take 100 times as long as writing to a
real file. It could crash your computer or corrupt files on your disk
drive.

It is undefined behavior and the C++ language neither knows nor cares
what it does, once you generate undefined behavior.

--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.l earn.c-c++
http://www.contrib.andrew.cmu.edu/~a...FAQ-acllc.html
Jul 23 '05 #7
Jack Klein wrote:
On 12 May 2005 20:48:31 -0700, "Gurikar" <ms*******@gmai l.com> wrote
in comp.lang.c++:

ofstream ofs;
ofs<<"hello"< <endl;

here i have not opened file, iam able to use this, only thing file wont
get created(its like dummy). I checked it, its running file, ofs value
is NULL. But i want to know does it affect performance. Actually i dont
want to write in a file in some situation so i wont open file, in some
case i want write a file, so i open a file. and call this. So just
using ofs<<"hello"<<e ndl many times affect performance without opening
file( i mean is performancei is same as withour using
ofs<<"hello"< <endl in code.)

Regards

Writing to an uninitialized stream is completely undefined behavior.
It could do nothing. It could take 100 times as long as writing to a
real file. It could crash your computer or corrupt files on your disk
drive.

It is undefined behavior and the C++ language neither knows nor cares
what it does, once you generate undefined behavior.


Mark another -1 for C++. C++ has so many undefined behaviors, gotchas
and unintuitive constructs that it makes it very difficult to get things
done sometimes. I've been using C++ for over 10 years, and always seem
to stumble on something. It seems to be the standard libraries that
cause the issues actually, not the language.

Mike
Jul 23 '05 #8

"Old Wolf" <ol*****@inspir e.net.nz> wrote in message
news:11******** **************@ g43g2000cwa.goo glegroups.com.. .
codigo wrote:
"Gurikar" <ms*******@gmai l.com> wrote:

ofstream ofs;

fun(char* str)
{
ofs<<str<<endl;
}


The above code is not C++. Neither would it compile on any
compiler(c++ or not). fun() has no return type, ofs in fun()
is not defined. main must return an integer. You need to read
up on scopes and lifetime of objects.


It's you who needs to read up on scopes: 'ofs' in fun()
correctly refers to the global (file-scope) variable 'ofs'.


indeed, i didn't see it.
Jul 23 '05 #9
"Mike Austin" <no@spam.com> wrote in message
news:Lr******** ************@bg tnsc04-news.ops.worldn et.att.net
Jack Klein wrote:


Writing to an uninitialized stream is completely undefined behavior.
It could do nothing. It could take 100 times as long as writing to a
real file. It could crash your computer or corrupt files on your
disk drive.

It is undefined behavior and the C++ language neither knows nor cares
what it does, once you generate undefined behavior.


Mark another -1 for C++. C++ has so many undefined behaviors, gotchas
and unintuitive constructs that it makes it very difficult to get
things done sometimes. I've been using C++ for over 10 years, and
always seem to stumble on something. It seems to be the standard
libraries that cause the issues actually, not the language.

You think it is unreasonable to expect that files be opened before writing
to them? Or that if you do "write to them" without them being opened, then
the consequences are undefined? Unintuitive? Pretty damned obvious I'd say.

--
John Carson

Jul 23 '05 #10

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