I have some legacy code which initialises an array using C syntax like
this:
struct bar
{
int i1_;
int i2_;
bool b1_;
};
int main(int argc, char **argv)
{
bar myBar[] =
{
{1,2,false},
{2,2,true},
};
return 0;
}
I now want to use struct bar in C++ and give it a constructor or two:
struct bar
{
bar(void):i1_(0 ),i2_(0),b1_(fa lse){}
bar(int i1, int i2, bool b1):i1_(i1),i2_ (i2),b1_(b1){}
int i1_;
int i2_;
bool b1_;
};
Is there any way I can still use the above syntax for initialising an
array of bar?
--
Simon Elliott http://www.ctsn.co.uk 2  2952 
Hi
"Simon Elliott" <Simon at ctsn.co.uk> wrote: struct bar
{
bar(void):i1_(0 ),i2_(0),b1_(fa lse){}
bar(int i1, int i2, bool b1):i1_(i1),i2_ (i2),b1_(b1){}
int i1_;
int i2_;
bool b1_;
};
Is there any way I can still use the above syntax for initialising an
array of bar?
No, but what about :
bar array[] = {
bar(1,2,true),
bar(3,4,false),
bar(5,0,true),
bar()
};
Markus
On 13/04/2005, Markus Moll wrote: "Simon Elliott" <Simon at ctsn.co.uk> wrote:
struct bar
{
bar(void):i1_(0 ),i2_(0),b1_(fa lse){}
bar(int i1, int i2, bool b1):i1_(i1),i2_ (i2),b1_(b1){}
int i1_;
int i2_;
bool b1_;
};
Is there any way I can still use the above syntax for initialising
an array of bar?
No, but what about:
bar array[] = {
bar(1,2,true),
bar(3,4,false),
bar(5,0,true),
bar()
};
Thanks, that's exactly what I was looking for.
--
Simon Elliott http://www.ctsn.co.uk This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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