inheritage: possible to call the original function ?

[mandatory]

hi,

i have two classes:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p);
}
What i want to do in the Push() in class B, is that i want to do some
additional checking in the start of the function - and the i would like to
call the original code for Push().

Is that possible, can i somehow call the original Push() (the one definded
in ClassA) ? the problem im facing is ofcourse, that when i overrides the
code for Push() it will override it all, so i have to duplicate the code if
i want it to work.

Hope you can understand - and hope you can help - thanks :)

[Alf P. Steinbach]

* mandatory:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p)
{
A::Push( p );
}

}

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[Karl Heinz Buchegger]

mandatory wrote:

hi,

i have two classes:

class A
{
public:
virtual Push (void *p);

};

And the other one:

Class B : Public A
{
public:
virtual Push (void *p);
}

What i want to do in the Push() in class B, is that i want to do some
additional checking in the start of the function - and the i would like to
call the original code for Push().

Is that possible, can i somehow call the original Push() (the one definded
in ClassA) ?

Yep.

void B::Push( void* p)
{
...
A::Push( p );
}
--
Karl Heinz Buchegger
kb******@gascad .at

[mandatory]

"Alf P. Steinbach

{
A::Push( p );
}

Thanx alot Alf :)