Hi, I need a function that expects a const std::string& containing the
visual representation of a number in binary format. It should then output
this number in groups of four bits separated by a space. If the length of
the string is not divisable by four (normally, it should receive 8-bit
numbers (that is, strings of length 8), it should output the number as-is,
no grouping). I came up with:
void
output_binary_s tring(ostream& os, const string& binary_string)
{
/* If the length of the string (i.e., the number of bits in *
* the binary number), isn't divisable by four, simply output *
* the entire string and return. */
if(binary_strin g.length() % 4)
{
os << binary_string;
return;
}
string::size_ty pe index = 0;
for(string::siz e_type i = 0; i < binary_string.l ength() / 4; ++i)
{
for(int j = 0; j < 4; j++)
{
os << binary_string[index++];
}
os << ' ';
}
}
Now, what if I want to use this function in a cout-statement? Do I have to
create a class or struct then and make my function the overloaded operator<<
for that class/struct?
Right now I do:
cout << "binary_represe ntation: ";
output_binary_s tring(cout, s);
cout << endl;
I would like to be able to cout << "binary representation: " <<
output_binary_s tring(cout, s) << endl;
Thanks for any replies 3 2749
Eric Lilja wrote: Hi, I need a function that expects a const std::string& containing the visual representation of a number in binary format. It should then output this number in groups of four bits separated by a space. If the length of the string is not divisable by four (normally, it should receive 8-bit numbers (that is, strings of length 8), it should output the number as-is, no grouping). I came up with:
void output_binary_s tring(ostream& os, const string& binary_string) { /* If the length of the string (i.e., the number of bits in * * the binary number), isn't divisable by four, simply output * * the entire string and return. */ if(binary_strin g.length() % 4) { os << binary_string;
return; }
string::size_ty pe index = 0;
for(string::siz e_type i = 0; i < binary_string.l ength() / 4; ++i) { for(int j = 0; j < 4; j++) { os << binary_string[index++]; }
os << ' '; } }
Now, what if I want to use this function in a cout-statement? Do I have to create a class or struct then and make my function the overloaded operator<< for that class/struct? Right now I do: cout << "binary_represe ntation: "; output_binary_s tring(cout, s); cout << endl;
I would like to be able to cout << "binary representation: " << output_binary_s tring(cout, s) << endl;
An easy way would be
# include <iostream>
# include <string>
class output_binary_s tring
{
private:
std::string s_;
public:
output_binary_s tring(const std::string &s)
: s_(s)
{
}
void print(std::ostr eam &stream) const
{
stream << s_; // just format it as you wish
}
};
std::ostream &operator<<(std ::ostream &stream,
const output_binary_s tring &obs)
{
obs.print(strea m);
return stream;
}
int main()
{
std::string s = "101001010" ;
std::cout << "Binary: " << output_binary_s tring(s) << std::endl;
}
You could work out something with manipulators also. Let us know if you
need help.
Jonathan
"Eric Lilja" <er************ *@yahoo.com> wrote in message
news:cq******** **@news.island. liu.se... Hi, I need a function that expects a const std::string& containing the visual representation of a number in binary format. It should then output this number in groups of four bits separated by a space. If the length of the string is not divisable by four (normally, it should receive 8-bit numbers (that is, strings of length 8), it should output the number as-is, no grouping). I came up with:
void
string
output_binary_s tring(ostream& os, const string& binary_string)
binary_string(c onst string& binary_string)
{ /* If the length of the string (i.e., the number of bits in * * the binary number), isn't divisable by four, simply output * * the entire string and return. */
ostringstream os;
if(binary_strin g.length() % 4) { os << binary_string;
return; }
string::size_ty pe index = 0;
for(string::siz e_type i = 0; i < binary_string.l ength() / 4; ++i) { for(int j = 0; j < 4; j++) { os << binary_string[index++]; }
os << ' '; }
return os.str();
}
Now, what if I want to use this function in a cout-statement?
cout << binary_string(" 10010010") < '\n';
Do I have to create a class or struct then and make my function the overloaded
operator<< for that class/struct? Right now I do: cout << "binary_represe ntation: "; output_binary_s tring(cout, s); cout << endl;
I would like to be able to cout << "binary representation: " << output_binary_s tring(cout, s) << endl;
Thanks for any replies
-Mike
"Mike Wahler" wrote: "Eric Lilja" <er************ *@yahoo.com> wrote in message news:cq******** **@news.island. liu.se... Hi, I need a function that expects a const std::string& containing the visual representation of a number in binary format. It should then output this number in groups of four bits separated by a space. If the length of the string is not divisable by four (normally, it should receive 8-bit numbers (that is, strings of length 8), it should output the number as-is, no grouping). I came up with:
void
string
output_binary_s tring(ostream& os, const string& binary_string)
binary_string(c onst string& binary_string)
{ /* If the length of the string (i.e., the number of bits in * * the binary number), isn't divisable by four, simply output * * the entire string and return. */
ostringstream os;
if(binary_strin g.length() % 4) { os << binary_string;
return; }
string::size_ty pe index = 0;
for(string::siz e_type i = 0; i < binary_string.l ength() / 4; ++i) { for(int j = 0; j < 4; j++) { os << binary_string[index++]; }
os << ' '; }
return os.str();
}
Now, what if I want to use this function in a cout-statement?
cout << binary_string(" 10010010") < '\n';
Do I have to create a class or struct then and make my function the overloaded operator<< for that class/struct? Right now I do: cout << "binary_represe ntation: "; output_binary_s tring(cout, s); cout << endl;
I would like to be able to cout << "binary representation: " << output_binary_s tring(cout, s) << endl;
Thanks for any replies
-Mike
Thanks both Mike and Jonathan for taking the time to help me out! I now
consider this problem solved and I've moved my attention to other issues in
this program. Thanks again.
/ Eric This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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