All,
Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Thank you!
-RB
8  4769 
"Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote... Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Is your 'long' 8 bytes? Really? And your char is 8 bits?
Usually it's something like
union { long l; char c[sizeof(long)]; } u;
char array[64];
// fill the array somehow
memcpy(u.c, array, sizeof(long));
long id = u.l;
You just need to make sure the order of bytes is correct. If it
is not, reverse the order of bytes in u.c before extracting u.l.
V
"Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote... Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Is your 'long' 8 bytes? Really? And your char is 8 bits?
Usually it's something like
union { long l; char c[sizeof(long)]; } u;
char array[64];
// fill the array somehow
memcpy(u.c, array, sizeof(long));
long id = u.l;
You just need to make sure the order of bytes is correct. If it
is not, reverse the order of bytes in u.c before extracting u.l.
V
"Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote... Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Is your 'long' 8 bytes? Really? And your char is 8 bits?
Usually it's something like
union { long l; char c[sizeof(long)]; } u;
char array[64];
// fill the array somehow
memcpy(u.c, array, sizeof(long));
long id = u.l;
You just need to make sure the order of bytes is correct. If it
is not, reverse the order of bytes in u.c before extracting u.l.
V
"Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote in message
news:9d******** *************** ***@posting.goo gle.com... All,
Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Thank you!
It's very likely that your long is 4 bytes big. If so then this is
impossible. Perhaps you should try two longs? Or maybe your platform has a
64 bit integer type, __int 64 perhaps.
john
Ramiro Barbosa, Jr. wrote: All,
Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
First of all you'd have to make sure that sizeof(long)==8
-- this is usually the case only on 64bit machines, but who
knows. Then you'd have to tell us if your machine is big-
of little-endian.
You might be lucky with
memcpy(&id,arra y,8)
HTH,
- J.
"Ramiro Barbosa, Jr." <ra******@yahoo .com> schrieb im Newsbeitrag
news:9d******** *************** ***@posting.goo gle.com... All,
Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Thank you!
As you mentioned socket I'd use htons() for having a defined byteorder.
Regards
Michael
John,
How would I use two longs? The primitive long in my platform (win2k)
is 4 bytes only!
Thanks,
-RB
"John Harrison" <jo************ *@hotmail.com> wrote in message news:<2t******* ******@uni-berlin.de>... "Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote in message
news:9d******** *************** ***@posting.goo gle.com... All,
Any ideas on how to convert the first 8 bytes of raw uninterpreted
sequence of bytes from 'char array[64];' (populated with _binary_ data
read from a socket), into a 'long id'?
Thank you!
It's very likely that your long is 4 bytes big. If so then this is
impossible. Perhaps you should try two longs? Or maybe your platform has a
64 bit integer type, __int 64 perhaps.
john
"Ramiro Barbosa, Jr." <ra******@yahoo .com> wrote in message
news:9d******** *************** ***@posting.goo gle.com... John,
How would I use two longs? The primitive long in my platform (win2k)
is 4 bytes only!
Thanks,
-RB
Well, first four bytes into one long, and the next four bytes into the other
long. Something like
long one = (256L*256L*256L )*(unsigned char)array[0] +
(256L*256L)*(un signed char)array[1] +
(256L)*(unsigne d char)array[2] +
(unsigned char)array[3];
long two = (256L*256L*256L )*(unsigned char)array[4] +
(256L*256L)*(un signed char)array[5] +
(256L)*(unsigne d char)array[6] +
(unsigned char)array[7];
(or the other way round of course).
john This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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