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Storing an integer: why "int"?

When you want to store an integer in C++, you use an integral type, eg.

int main()
{
unsigned char amount_legs_dog = 4;
}

In writing portable C++ code, there should be only two factors that
influence which integral type you choose:

A) Signedness. Do you want only positive values? Or do you want both
positive and negative values?

B) The minimum range for that type as specified by the C++ Standard.
The minimum range for "short" and "int" are identical. The following
statement is always true on all implementations :

sizeof(short) <= sizeof(int)

As this is so, why would one ever use the type "int" at all? It seem to have
no merit whatsoever. I will always use "short" in its place.

Any thoughts on this?

-JKop
Jul 22 '05
30 2383

"JKop" <NU**@NULL.NULL > wrote in message
news:XN******** **********@news .indigo.ie...
jeffc posted:

"JKop" <NU**@NULL.NULL > wrote in message
news:dV******** **********@news .indigo.ie...
>
> Whoa, if the sign is "less than or equal to", then why are you > acting like it's "less than"?

Because it can be.


If it "can be", then why are you acting like "it is".


The same reason why fire-men are still on duty when
there's no fires around.


But if you'll notice, they don't act like there's a fire.
Jul 22 '05 #31

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