inherited member function not seen

[Daniel Barna]

Hi
I am a bit confused. I thought always that if a class inherits from
another (public), then all of its base class's public member function
are also visible in this class - even if it declares a function with
the same name, but different parameters.

However, when I try to compile the example below, the compiler claims
that there is no appropriate function:
invalid conversion from 'int' to 'const char *'
initializing argument 1 of 'void B::push_back(co nst char *)'

However, if I don't declare a 'push_back' function inside 'class B',
then everything works fine. Should the compiler in this case not
resolve the
'push_back' function (based on its argument type: int) to
A::push_back(in t) ?

Thank you
DAniel

-----
class A
{ public:
void push_back(int) {}
};

class B : public A
{ public:
void push_back(const char *) {}
};

int main()
{
B b;
b.push_back(1);
return 0;
}

[Rolf Magnus]

Daniel Barna wrote:

Hi
I am a bit confused. I thought always that if a class inherits from
another (public), then all of its base class's public member function
are also visible in this class - even if it declares a function with
the same name, but different parameters.
If you declare a function in a derived class, _all_ functions of its
base classes with the same name are hidden.
However, when I try to compile the example below, the compiler claims
that there is no appropriate function:
invalid conversion from 'int' to 'const char *'
initializing argument 1 of 'void B::push_back(co nst char *)'

However, if I don't declare a 'push_back' function inside 'class B',
then everything works fine. Should the compiler in this case not
resolve the 'push_back' function (based on its argument type: int) to
A::push_back(in t) ?
No. But you can explicitly make it visible in B. See my addition to your
code.
Thank you
DAniel

-----
class A
{ public:
void push_back(int) {}
};

class B : public A
{ public:
void push_back(const char *) {}
using A::push_back;
};

int main()
{
B b;
b.push_back(1);
return 0;
}

[Sharad Kala]

"Daniel Barna" <kk****@freemai l.hu> wrote in message
news:46******** *************** ***@posting.goo gle.com...

Hi
I am a bit confused. I thought always that if a class inherits from
another (public), then all of its base class's public member function
are also visible in this class - even if it declares a function with
the same name, but different parameters.

No, you got it wrong. Base class member functions with same name as a
derived class member function are hidden in the derived class.
Should be in the FAQ - http://www.parashift.com/c++-faq-lite