sort and get index?

[b83503104]

In matlab, the sort function returns two things:

[a,b]=sort([5, 8, 7])

a = 5 7 8
b = 1 3 2

where a is the sorted result, and b is the corresponding index.
Is there C++ code available to achieve this?
Better compatible with STL vector.
Thanks

[Victor Bazarov]

"b83503104" <b8*******@yaho o.com> wrote...

In matlab, the sort function returns two things:

[a,b]=sort([5, 8, 7])

a = 5 7 8
b = 1 3 2

where a is the sorted result, and b is the corresponding index.
Is there C++ code available to achieve this?

Probably. You could simply sort pairs based on their 'first'
members, then get the 'second' members (which you should set
to ordinal numbers before sorting).

V

[Me]

template<class T> struct index_cmp {
index_cmp(const T arr) : arr(arr) {}
bool operator()(cons t size_t a, const size_t b) const
{ return arr[a] < arr[b]; }
const T arr;
};

vector<int> a;
a.push_back(5); a.push_back(8); a.push_back(7);

vector<size_t> b;
for (unsigned i = 0; i < a.size(); ++i)
b.push_back(i);
// b = [0, 1, 2]
sort(b.begin(), b.end(), index_cmp<vecto r<int>&>(a));
// b = [0, 2, 1]

then just offset into the a vector with the indices in b. I recomend
just sorting the indices this way and not touching the a vector.

[Siemel Naran]

b8*******@yahoo .com (b83503104) wrote in message

In matlab, the sort function returns two things:

[a,b]=sort([5, 8, 7])

a = 5 7 8
b = 1 3 2

where a is the sorted result, and b is the corresponding index.
Is there C++ code available to achieve this?
Better compatible with STL vector.
Thanks

There is no such way in C++. But you can build it yourself.

Here is one suggestion: make your original vector { 5, 8, 7 }, make a
vector of pointers { &orig[0], &orig[1], &orig[2] }, sort the vector
of pointers using std::sort of 3 arguments which should yield {
&orig[0], &orig[2], &orig[1] }.

A second suggestion is: make your original vector a vector of
pair<int, index> as { {5,0}, {8,1}, {7,2} }, sort the vector using
std::sort of 3 arguments which should yield { {5,0}, {7,2}, {8,1} }.

The first way would look something like this:

std::vector<int > orig;
orig.push_back( 5);
orig.push_back( 7);
orig.push_back( 8);
std::vector<con st int *> pointer;
pointer.reserve (orig.size());
const int *const start = &orig[0];
const int *const end = start + orig.size();
for (int * iter = start; iter != end; ++iter) pointer.push_ba ck(iter);
std::sort(point er.begin(), pointer.end(), LessDereference ());

where

struct LessDereference {
template <class T>
bool operator()(cons t T * lhs, const T * rhs) const {
return *lhs < *rhs;
}
};

To print the results, choose whatever option you want. There are many
ways, and here is one:

for (int i=0; i<pointer.size( ); i++) {
const int * p = pointer[i];
cout << "(" << *p << "," << p-start << " ";
}

[Siemel Naran]

b8*******@yahoo .com (b83503104) wrote in message

In matlab, the sort function returns two things:

[a,b]=sort([5, 8, 7])

a = 5 7 8
b = 1 3 2

where a is the sorted result, and b is the corresponding index.
Is there C++ code available to achieve this?
Better compatible with STL vector.
Thanks

There is no such way in C++. But you can build it yourself.

Here is one suggestion: make your original vector { 5, 8, 7 }, make a
vector of pointers { &orig[0], &orig[1], &orig[2] }, sort the vector
of pointers using std::sort of 3 arguments which should yield {
&orig[0], &orig[2], &orig[1] }.

A second suggestion is: make your original vector a vector of
pair<int, index> as { {5,0}, {8,1}, {7,2} }, sort the vector using
std::sort of 3 arguments which should yield { {5,0}, {7,2}, {8,1} }.

The first way would look something like this:

std::vector<int > orig;
orig.push_back( 5);
orig.push_back( 7);
orig.push_back( 8);
std::vector<con st int *> pointer;
pointer.reserve (orig.size());
const int *const start = &orig[0];
const int *const end = start + orig.size();
for (int * iter = start; iter != end; ++iter) pointer.push_ba ck(iter);
std::sort(point er.begin(), pointer.end(), LessDereference ());

where

struct LessDereference {
template <class T>
bool operator()(cons t T * lhs, const T * rhs) const {
return *lhs < *rhs;
}
};

To print the results, choose whatever option you want. There are many
ways, and here is one:

for (int i=0; i<pointer.size( ); i++) {
const int * p = pointer[i];
cout << "(" << *p << "," << p-start << " ";
}

[Siemel Naran]

an************* ****@yahoo.com (Me) wrote in message

template<class T> struct index_cmp {
index_cmp(const T arr) : arr(arr) {}
bool operator()(cons t size_t a, const size_t b) const
{ return arr[a] < arr[b]; }
const T arr;
};
Maybe class index_cmp could hold a const reference rather than an
object (ie. change const T arr to const T& arr). Saves unnecessary
copying.
sort(b.begin(), b.end(), index_cmp<vecto r<int>&>(a));

You can provide rename index_cmp to index_cmp_t and provide an inline
function

template <class Container>
inline
index_cmp_t<Con tainer>
index_cmp(const Container& c)
{
return index_cmp_t<Con tainer>(c);
}

This prevents the need to explicitly qualify template parameters in
the code.

[Jeff Flinn]

"b83503104" <b8*******@yaho o.com> wrote in message
news:73******** *************** ***@posting.goo gle.com...

In matlab, the sort function returns two things:

[a,b]=sort([5, 8, 7])

a = 5 7 8
b = 1 3 2

where a is the sorted result, and b is the corresponding index.
Is there C++ code available to achieve this?
Better compatible with STL vector.
Thanks

Try the following untested code after installing boost from www.boost.org.

#include <map>
#include <boost/bind.hpp>
#include <boost/iterator/counting_iterat or.hpp>

typedef std::map<int,in t> tMap; // <data,index>

tMap Map;

int Data[] = { 5, 8, 7 };

std::transform( &data[0], &data[3]
, boost::counting _iterator<int>( 1)
, std::inserter<t Map>(Map)
, boost::bind( std::make_pair< int,int>, _1, _2 )
);

for( tMap::const_ite rator lItr = Map.begin() ; lItr != Map.end() ; ++lItr )
{
std::cout << "Data Value: " << lItr->first
<< " At Index: " << lItr->second;
}

Jeff F

[Me]

> Maybe class index_cmp could hold a const reference rather than an

object (ie. change const T arr to const T& arr). Saves unnecessary
copying.

sort(b.begin(), b.end(), index_cmp<vecto r<int>&>(a));

It does hold a const reference (notice the '&' at the call to sort). I
did it this way because doing it the way I would do in real life (add
a reference only if T isn't a pointer or a reference) requires a lot
more code or a dependency on boost's type_traits (which will hopefully
be added to the next standard).

[Siemel Naran]

an************* ****@yahoo.com (Me) wrote in message

Maybe class index_cmp could hold a const reference rather than an
object (ie. change const T arr to const T& arr). Saves unnecessary
copying.

sort(b.begin(), b.end(), index_cmp<vecto r<int>&>(a));

It does hold a const reference (notice the '&' at the call to sort). I
did it this way because doing it the way I would do in real life (add
a reference only if T isn't a pointer or a reference) requires a lot
more code or a dependency on boost's type_traits (which will hopefully
be added to the next standard).

Good point, sorry missed it.