Okay, I'm having a bit of a brain-fart and I can't remember how I would do
this.
Say I have the following:
template <typename T1, typename T2> class A; // Forward declaration of A
template <typename T1, typename T2>
class B
{
private:
/* .... */
public:
friend class A<T1, T2>; // OK - B sees forward declaration of A
/* .... */
};
template <typename T1, typename T2> // Definition of A
class A
{
private:
class<T1, T2> B;
/* .... */
public:
class C { /* .... */ };
};
How do I make private members of B accessable to C? Simply adding `friend
class A<T1, T2>::C;` to class B dosen't work (my compiler complains A has
no nested class C) and I'm not entierly certian of what the correct syntax
is for a forward declaration of A::C is if A is a template class. Any
ideas?
Thanks,
Chris Schadl
1  2073 
"Chris Schadl" <cs*****@satan. blah.org.uk> wrote in message template <typename T1, typename T2> class A; // Forward declaration of A
template <typename T1, typename T2>
class B
{
private:
/* .... */
public:
friend class A<T1, T2>; // OK - B sees forward declaration of A
/* .... */
};
template <typename T1, typename T2> // Definition of A
class A
{
private:
class<T1, T2> B;
/* .... */
public:
class C { /* .... */ };
};
How do I make private members of B accessable to C? Simply adding `friend
class A<T1, T2>::C;` to class B dosen't work (my compiler complains A has
no nested class C) and I'm not entierly certian of what the correct syntax
is for a forward declaration of A::C is if A is a template class. Any
ideas?
You can't make a class a friend to a forward declared nested class, because
you can't forward declare a nested class.
You can make class A::C non-nested, and with a name like A_C. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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